Light Refraction Previous Year Questions 2020 PDF

LightRefraction PREVIOUS Retention YEAR QUESTIONS I - , - - - y Designed with ta. Snobhit Nirwan  2020...

LightRefraction PREVIOUS Retention YEAR QUESTIONS I - , - - - y Designed with ta. Snobhit Nirwan  2020 ¥ #" : t in , Cas ft tu f - f tf.to/- Is V - 30cm ④ M 3 enlarged tf -3% = - → = 8am Erect & virtual. * SOLIE Atdg y Mn = 3- I 2µg = 43 NOW nklz = Me g Mn ( multiply divide by Mys HE Yuan = ' ' # gutta ' LI 'T = ,. Now , ally = 22 = speedoflightinmediumn speed of light in medium y. 221=31×101 Vy /Vy=2Xl08mI - 2-019 AMI : iii.÷. : : f- tf f an : - - - Ist FAI - # 'T Io t = tu Io +To - = µ=-60cmT # I  - Now , m- if = - t¥o) Iz m=h÷=¥ ¥ hut - I antsy partJ - I =-3 m- In hz= -2cm ¥ - ¥2 = ¥3 1V=8cmI Now , I I - -_ If f- tf)=f - H=-48cmI ans⑧ : - f- 20am gu= -30cm using lens formula , I I If - - I Hotta - T Io fo - - - 4=60-51 Ndifoncept (Ego) -2T Inverted ~ as R O ooo R2 - to - sand inverted M= Iu same - , also , m- he is Real , inverted , Behind Lfzg ho magnified. 2=hz hz=-L0cm_ - ^ a FZ Zook I O f 2 Fd , Y 2018 ) an an A convex erect diminished virtual mirror forms image for all the positions of the object placed infront of it Itis used as rear. view mirrors in automobiles,  as reflectors in street light bulbs and in parking lots. ants : - laws of Reflection → Pg① of notes. Absolute Reflective sp.eedoflightinracuumo.gr index = speed of light in optical medium Power of lens → Pg ⑨ of notes. Ehlers : F- 2.5 D → ④ ve Io convex lens. m FYf÷÷ m - SD → ore so concave lens. ansdd : lens formula f I f- = f- - = Io 4=60*7 ' Now m I the - , - = he hut cm = Ratio of size of image to size of object. tho ' , = I ① = 2017 ANI Yoo u 15cm f 30cm - = - = - g lens formula g f f-- = If f- ft tu To Is = + :O f- fo Hm7 - = ④re tf Ifs M - - = → : for med left side of mirror is virtual g erect and Image on concave. on same -. g side as of the object. anti - positions are b/w Fs 40 and btw Fs and 2 Fs Two → → ( Ray diagrams on Pg⑧ of notes) Ansi : ca ) when the object distance and image distance are the sameg it - means that the object is placed at Zf or the image is formed at 2f. from the table g it is clear that I = 40cm. Therefore , the focal length of lens Ps 20cm convex. (b) Serial number 6 is incorrect Given that the object is placed at 15cm which.. is between the focal length and the lens Thus the , image should be formed. on same side as the object The data given in observation serial number 6 does. not satisfy the condition. CC) f- m= Let us consider third observation u= - 40cm & V = 40cm : m y Fo - - -. - ans②← I - ( as convex mirror. Cbs Uses → Pg ③ of Notes. 2016 Is a_m④ : concave mirror - is used in the design of solar furnaces When. a solar furnace is placed at the focus of large concave mirror is called reflectors g it focuses a parallel beam of light coming from sun on the furnace. is L It means the image is real and invested an Magnification and is same size as that -. of of the object so if the image is at a distance of 40cm from the mirror then the object is also at a distance of 40cm from the mirror because the object is placed at C i.e center of. curvature of mirror. If object is moved 20cm towards the mirror the object is placed at f at the principal focus and the is formed at Fe. image infinity. The nature of image so formed is real inverted and highly enlarged. And27 (a) In mirror erect is formed concave only when the object is placed between pole and focus. ⑥ Image will be larger than the object ↳ (c) If object distance is 24cm which is the apps on position of centre of curvature, then the image will be formed at the same position. Fay censed 3 : - Optical center of the lens is defined as the point which lies on the principal axis through the rays of light passes without any deflection. ⑥ Given g f -20cm = No = 4cm ✓= - 10cm lens formula f- I f - - - fo tu Iot U= 20cm - - - = Now g m= the I = ¥ has Iff he 2cm - = - ⑥ 2017 BB  z⑨ : 2×108 M/s an Mg - 1g Mw = I Vg = - , g caifnowtug tug EMILY - - 2×108 2.67×108 Mls ④ we know, Nw = C- Vw 78×108m/s 2067342101 Vw do µSw = = ' airs : - A convex mirror produces an erect and diminished imagemirror of the object placed in front of it So,. given is convex mirror. Used Pg ③ of - notes. anSIL : - power definition → notes. Now g f-A = +10cm = -10 I m. - convex C : ⑦ ve) ' diam fB = - IO cm = - O Im. → concave t: -0 re ) 11 , In a convex dens, when the object is placed b/w the pole and focus , the image formed will be always virtual virtual and magnified Whereas a concave erect but diminished. , lens produces ,images. and: The convex lens will produce the complete image of the object even though half of lens is covered This. is because the other half of the lens can refract the light coming from object. But , the intensity of the light will reduce.  tens formula, f- I I - -_ f- = Itf =Eo * fo - - €69 m f- If ④ - - → erect I. Virtual and erect. ht = 4 "° o : hseuxho 4X4 ④ 2014 Lanes ↳ dnsd3T AMIL 's In notes - ID G- 3×108 m/s µ= 3/2 We µ= 3×10-8 µn0W9 V=fq= 3/2 2×108 m/s = ANIL : Is Concave - EB Real , inverted and of same size as object the. Iii Here the object distance image = distance as the object is placed on the center of curvature Therefore, the object is placed at 40cm from the mirror.. ED and : ⑨ A concave mirror produces real images and hence it should - be used. (b) The candle flame should be placed between the focus and centre of curvature of mirror. ⑥ Yes , if candle flame is placed at a distance Linfen Pty) ft is possible long the diminished to get image of the candle flame on the wall. 2013 AM 13: ans-34 or cis con real mirrors are used as rear view mirror because It forms erect and virtual → image → It can cover large areas as image formed are ofsmall size. II concave mirrors are used as shaving mirrors because , : → It forms images of larger size which helps to see object clearly. → Image formed is always erect and virtual when the object is near the mirror which is true in this case ,. ans35= : ho = 6cm g f- = -5cm g U = LO cm - lens formula is f- to If - = f- Hot t E to - = - - f- I - = 10 /v=-I7 Now , M= tf = 1¥13 = I - also g m= he no = HE lhz=I ans⑤ : - M Pg ⑥- of notes 415 2017 → Q4. 2012 Fs Pg ② of notes. Is 2013g 034 ' dad48 no = 5cm g f - 12cm , U = - 8cm lens formula , f- I f - = f- ttfstz 4=-2474 - A- hh÷= F 1m=I - tore :O erect ¥ - II i. magnification is ④ re. Image is erect and h5omI virtual and is enlarged.