CHE 129 F24 Practice Exam 1 A (1).pdf

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CHE 129 Exam 1 Fall 2022 Form 1A Directions 1. Do not open this exam until told to do so. 2. Place your ID (face up), pencils, erasers, and a scientific calculator at your desk now. 3. Place all other items out of sight and or beneath your sea...

CHE 129 Exam 1 Fall 2022 Form 1A Directions 1. Do not open this exam until told to do so. 2. Place your ID (face up), pencils, erasers, and a scientific calculator at your desk now. 3. Place all other items out of sight and or beneath your seat. 4. Verify that the Form number (1, 2, 3, or 4) on your scantron and your exam form match. Then on your scantron write and bubble-in your: LAST NAME FIRST NAME IDENTIFICATION NUMBER 5. Under Course Name, write “CHE 129” 6. All scantron forms must be submitted by 9:35 PM. No extra time will be given. 7. All answers must be entered on the Scantron answer sheet, which you must turn in. Answer sheets will not be returned, so record your answers next to each question on the exam for comparison with the answers when they are posted on Blackboard. Use the space between questions, the backs of pages, or the extra sheets for analysis and calculations. 8. Once you open the exam, be sure you have all the pages including a Periodic Table and a sheet of equations/conversion factors. Page numbers and the total number of pages are at the bottom of each page. If you are missing pages, request another exam. 9. During the exam you will be asked to show your ID and sign in on an attendance sheet. 10. General Chemistry Policies: Possession of cell phones, other communication devices, or any unauthorized materials during the exam will result in a grade of 0 on this exam, a report to Academic Judiciary, and a possible grade of F for the course. Ifyoudo nothaveanID,notethatonthesign-in sheet,andyoumustseeDr.Amarante the day after the exam and show him a valid ID. Blank Page Conversion Factors Mass Temperature Pressure 1 lb = 453.59237 g TC = 5/9(TF – 32) 1 Pa = 1 N m–2 1 lb = 16 oz TK = TC + 273.15 K = 1 kg m–1 s–1 Length TF = (9/5)TC + 32 1 atm = 101.325 kPa 1 km = 0.62137 miles Energy = 760 mm Hg 1 Å = 10–10 m 1 Joule = 1 kg m2 s–2 = 760 Torr 1 in = 2.54 cm = 0.2390 calorie = 14.70 lb/in2 Volume = 1 C 1 V 1 bar = 1 105 Pa 1 L = 1.056710 qt = 1 Pa m3 1 gallon = 4 quarts 1 L atm = 101.325 J 1 Cal = 1000 cal Physical and Chemical Constants electron mass = 9.109 10–31 kg proton mass = 1.672621 10–27 kg neutron mass = 1.674927 10–27 kg electron charge = 1.602 10–19 C NA = 6.022 x 1023 mol–1 R = 0.08206 L atm mol–1 K–1 = 8.314 J mol–1 K–1 c = 2.998 ×108 m s–1 h = 6.626 10–34 J s kB = 1.381 10–23 J K–1 RH = 2.178 ×10–18 J F = 96,485 C mol–1 π = 3.141592654 –13 –10 1 MeV = 1.6022 ×10 J 1 Ci = 3.70 10 d/s 1 u = 931.5 MeV –27 2 –2 1 u = 1.66054 ×10 kg ke = 8.9875 10 N m C 9 Properties of Water Heat Capacities J g–1 K–1 J mol–1 K–1  = 1.00 g/mL = 1.00 g/cm3 Water(steam) 2.080 37.47 Hfus = 6.01 kJ/mol Water(liquid, 25ºC) 4.184 75.327 Hvap = 40.68 kJ/mol Water(ice, –10ºC) 2.050 38.09 Kw = 1.00 10–14 at 298 K Standard Thermodynamic Conditions: 1 atm, 1M, 298 K STP: 1 bar, 0 ºC                           =¢e„}mg{¤ =gvq˜y¤   + 0¤   + ,(.¤ Cq’oq˜y¤ 6gvvq˜y¤ 9vgyg{“¤ G^yg¤ 6}Œ{¤ 7^ƒa}{¤ Gq’Œmg{¤ H ¢mg{¤ :v˜}ƒq{g¤ Gg}{¤          .1,¤ + + 1((¤ *!# + 4’}yqc¤œgq_o’¤yg^{¤ˆv^“qšg¤y^¤ + 0¤ + (¤ ,/¤ +  -111¤ + 0110¤ + (0¤ L}eq˜y¤ E^m{gq˜y¤ 4v˜yq{q˜y¤ Lqvqc}{¤ Io}€o}ƒ˜¤ L˜vi˜ƒ¤ 7ov}„q{g¤ 4Š}{¤         ((11¤ + (,*-¤ +  + + (.10(¤ (00-¤  *1/,¤  *(.¤  + %+ *-,-¤ *11,0¤ I}’^q˜y¤ 7^vcq˜y¤ Lc^{eq˜y¤ Mr“^{r˜y¤ S^{^eq˜y¤ 7oŒyq˜y¤ E^{m^{gg¤ ?Œ{¤ 7}a^v’¤ Gqctgv¤ 7}€€g„¤ Yq{c¤

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