Prayas JEE 2.0 2025 Basic Maths PDF

Summary

This is a mathematics exam paper for Prayas JEE 2.0 2025. It has questions and answers on topics such as algebra and basic maths. The document is suitable for undergraduate students preparing for the Joint Entrance Examination.

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JEE Prayas JEE 2.0 2025...

JEE Prayas JEE 2.0 2025 Maths DPP: 2 Basic Maths Q1 Find relation between x, y and z if Q6 If a + b = 7 and ab = 12 then what is the value of 2 2 x + 9y + 25z 2 = xyz ( 15 x + 5 y + z) 3 a2 – ab – b2? (A) 12 (B) 13 (A) x = 3y = 5z (C) 14 (D) –5 (B) x = 2y = 3z (C) x = −3y = 5z Q7 If x2 + 12 = 51 , then what is the value of x (D) x = −3y = −5z x3 − 1 x3 −− −− (A) 364 (B) 365 Q2 If A = (4 + √15 )1/3 + (4 − √15 )1/3 , the A3 − 3A is equal to (C) 756 (D) 367 Q3 The least value of expression Q8 If a + b + c = 12 and a2 + b2 + c2 =50, find the x2 + 4y 2 + 9z 2 − 2x+ 8y + 27z + 15 value of ab + bc + ca. (A) 15 (A) 44 (B) 45 (B) 5 (C) 46 (D) 47 (C) − 31 7 Q9 If (x + y + z) = 1, xy + yz + zx = –1, xyz = –1 then (D) − 41 4 value of x3 + y3 + z3 is – −− −− – – (A) –1 (B) 1 Q4 The value of (√4 − √10 + √25 )(√2 + √5 ) 3 3 3 3 3 (C) 2 (D) –2 is equal to. Q10 The expansion of (x + y – z)2 is (A) x2 + y2 + z2 + 2xy + 2yz + 2zx Q5 If x + x1 = 2, then prove that (B) x2 + y2 – z2 – 2xy + yz + 2zx 1 1 1 (C) x2 + y2 + z2 + 2xy – 2yz – 2zx x2 + = x 4 + = x 6 + x2 x4 x6 (D) x2 + y2 – z2 + 2xy – 2yz – 2zx Android App | iOS App | PW Website JEE Answer Key Q1 (A) Q6 (D) Q2 (A) Q7 (A) Q3 (D) Q8 (D) Q4 7 Q9 (B) Q5 Proof Q10 (C) Android App | iOS App | PW Website

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