Summary

Evaluación de una integración doble en un dominio determinado. El texto muestra ecuaciones y cálculos para evaluar la integral doble.

Full Transcript

Evaduatin Double htegalo bistsial chenged acceidengly DATE 42 2 de 2...

Evaduatin Double htegalo bistsial chenged acceidengly DATE 42 2 de 2 (9-ed 3 8x t e - 9x-e 7 t e'-e da e'e. *=2 2 3 2 3)6-)+ees 2 2 DATE è valuata de dy 0 2 dy DATE ouea the tiangle bouded tt oy atr-y) -e -e 3 2 we Caw alyo dyd te Same DATE dy de de ZxF3(1-4) e 2 2 2 =e e -, 2 3 2 3 N Qe'-3e) DATE whme barabolese nd bonndd by parabols uese 2 eguaAb 2 botu dide y64 whem L= l6 ne4. When do 92- loy Jist ie dy EvaluotM i ple egaly Mtytz L dyde ytzytz e dydz Z+ 2 tteete-feet) 3 e-3e +3e-] da dyde Costtto dyd here fom same the evalul heme &ddy 2 oRDER of DHANGE N dz z a ta'az =4tt 2 dz + t az 2 A42 dz DATE DATE 9 2 evauate tte ame y=2 We Cuves -0 to =2y 0 y) t 2 2 Carod Cndhal to Caten brCos Zr odtei VAe co ALsS Polar (,, plieyical 1) to Catea Ze HANG J= Cooit Polad tcos tPoa + X=cos Catena dQcos do fa'- t)*d da To-caleulate eiwit acos Qco’t Whenr teo oz0 when t acost co-ordiiate Poler cbaging t 2 uadrant pesitve the in Sim dhdy ay Evaly ualzcivde wbeu R and v) u, einit Lwtere eplaee Vauabla OATE DATE J ade d tao 2 Hence, khow tua -x M 2. aata to to 2Coso geos rdode 26050 Cose 0 CosYeos'9-o) dg 3 rdodp de t ( ) de DATE dedyda Co odt octat rSn os n-drdsdt - V si,e dorde d 2 I - 1. I de d OATE By DoUBLs /MeGeATIN kigi baded beunded by tha L dydo JteeAen Point u x (-3) o AYE 2 andy 2 2 -2]4(h-) Tmpb volune plae plame XoY z dyda de 2 be - abc lo-) =

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