Summary

This presentation provides an overview of the 8086 microprocessor, covering its different generations from the first to fifth, including details on its key features, and general architecture.

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8086 Microprocessor Case Study: Intel Slide 2 Processors Microproc Fifth Generation Pentium e ssor Fourth Generation...

8086 Microprocessor Case Study: Intel Slide 2 Processors Microproc Fifth Generation Pentium e ssor Fourth Generation During 1980s Low power version of HMOS technology (HCMOS) Third Generation 32 bit processors During 1978 Physical memory space 224 bytes = 16 Mb HMOS technology  Faster speed, Higher Virtual memory space 240 bytes = 1 Tb packing density Floating point hardware 16 bit processors  40/ 48/ 64 pins Supports increased number of addressing Easier to program modes Dynamically relatable programs Processor has multiply/ divide arithmetic Intel 80386 hardware More powerful interrupt handling capabilities Second Generation Flexible I/O port addressing During 1973 NMOS technology  Faster speed, Higher Intel 8086 (16 bit processor) density, Compatible with TTL 4 / 8/ 16 bit processors  40 pins Ability First Generation to address large memory spaces and Between 1971 – 1973 I/O ports PMOS technology, non compatible with TTL Greater number of levels of subroutine 4 bit processors  16 pins nesting 8 and 16 bit processors  40 pins Better interrupt handling capabilities Due to limitations of pins, signals are 3 multiplexed Intel 8085 (8 bit processor) 8086 Microprocessor Overview First 16- bit processor released by Addressable memory space is INTEL in the year 1978 organized in to two banks of 512 kb each; Even (or lower) bank and Odd (or higher) bank. Address line A0 is used to 𝐁𝐇𝐄 is used to access odd bank Originally HMOS, now manufactured select even bank and control signal using HMOS III technique Uses a separate 16 bit address for I/O Approximately 29, 000 transistors, 40 mapped devices  can generate 216 = pin DIP, 5V supply 64 k addresses. Operates in two modes: minimum mode the signal at MN and 𝐌𝐗 pins. Does not have internal clock; external and maximum mode, decided by asymmetric clock source with 33% duty cycle 20-bit address to access memory  can address up to 220 = 1 megabytes of memory space. 8086 Microprocessor Pins and Signals Common signals AD0-AD15 (Bidirectional) Address/Data bus Low order address bus; these are multiplexed with data. When AD lines are used to transmit memory address the symbol A is used instead of AD, for example A0- A15. When data are transmitted over AD lines the symbol D is used in place of AD, for example D0-D7, D8-D15 or D0-D15. A16/S3, A17/S4, A18/S5, A19/S6 High order address bus. These are multiplexed with status signals 8086 Microprocessor Pins and Signals Common signals BHE (Active Low)/S7 (Output) Bus High Enable/Status It is used to enable data onto the most significant half of data bus, D8-D15. 8-bit device connected to upper half of the data bus use BHE (Active Low) signal. It is multiplexed with status signal S7. MN/ MX MINIMUM / MAXIMUM This pin signal indicates what mode the processor is to operate in. RD (Read) (Active Low) The signal is used for read operation. It is an output signal. It is active when low. 8086 Microprocessor Pins and Signals Common signals TEST 𝐓𝐄𝐒𝐓 input is tested by the ‘WAIT’ instruction. 8086 will enter a wait state after execution of the WAIT instruction and 𝐓𝐄𝐒𝐓 is made low by an active will resume execution only when the hardware. This is used to synchronize an external activity to the processor internal operation. READY This is the acknowledgement from the slow device or memory that they have completed the data transfer. The signal made available by the devices is synchronized by the 8284A clock generator to provide ready input to the 8086. The signal is active 7 8086 Microprocessor Pins and Signals Common signals RESET (Input) Causes the processor to immediately terminate its present activity. The signal must be active HIGH for at least four clock cycles. CLK The clock input provides the basic timing for processor operation and bus control activity. Its an asymmetric square wave with 33% duty cycle. INTR Interrupt Request This is a triggered input. This is sampled during the last clock cycles of each instruction to determine the availability of the request. If any interrupt request is pending, the processor enters the interrupt acknowledge cycle. synchronized. 8 8086 Microprocessor Pins and Min/ Max Pins Signals The 8086 microprocessor can work in two modes of operations : Minimum mode and Maximum mode. In the minimum mode of operation the microprocessor do not associate with any co-processors and can not be used multiprocessor for systems. In the maximum mode the 8086 can work in multi-processor or co-processor configuration. Minimum or maximum mode operations are decided by the pin MN/ MX(Active low). When this pin is high 8086 operates in minimum mode otherwise it operates in Maximum mode. 10 8086 Microprocessor Pins and Signals Minimum mode signals Pins 24 -31 For minimum mode operation, the MN/ 𝐌𝐗 is tied to VCC (logic high) 8086 itself generates all the bus control signals DT/𝐑ഥ (Data Transmit/ Receive) Output signal from the processor to control the direction of data flow through the data transceivers 𝐃𝐄 𝐍 (Data Enable) Output signal from the processor used as out put enable for the transceivers ALE (Address Latch Enable) Used to demultiplex the address and data lines using external latches 𝐈𝐎 M/ Used to differentiate memory access and I/O access. For memory reference instructions, it is high. For IN and OUT instructions, it is low. 𝐖 𝐑 Write control signal; asserted low Whenever processor writes data to memory or I/O port 𝐈𝐍𝐓 𝐀 (Interrupt Acknowledge) When the interrupt request is accepted by the processor, the output is low on this line. 11 8086 Microprocessor Pins and Signals Minimum mode signals Pins 24 -31 For minimum mode operation, the MN/ 𝐌𝐗 is tied to VCC (logic high) 8086 itself generates all the bus control signals HOLD Input signal to the processor form the bus masters as a request to grant the control of the bus. Usually used by the DMA controller to get the control of the bus. HLDA (Hold Acknowledge) Acknowledge signal by the processor to the bus master requesting the control of the bus through HOLD. The acknowledge is asserted high, when the processor accepts HOLD. 12 8086 Microprocessor Pins and Signals Maximum mode signals During maximum mode operation, the MN/ 𝐌𝐗 is grounded (logic low) Pins 24 -31 are reassigned 𝑺 𝟎, 𝑺𝟏, 𝑺𝟐 Status signals; used by the 8086 bus controller to generate bus timing and control signals. These are decoded as shown. 13 8086 Microprocessor Pins and Signals Maximum mode signals During maximum mode operation, the MN/ 𝐌𝐗 is grounded (logic low) Pins 24 -31 are reassigned 𝑸𝑺𝟎, 𝑸𝑺𝟏 (Queue Status) The processor provides the status of queue in these lines. The queue status can be used by external device to track the internal status of the queue in 8086. The output on QS0 and QS1 can be interpreted as shown in the table. 14 8086 Microprocessor Pins and Signals Maximum mode signals During maximum mode operation, the MN/ 𝐌𝐗 is grounded (logic low) Pins 24 -31 are reassigned 𝐑𝐐/𝐆𝐓𝟎, 𝐑𝐐/𝐆𝐓𝟏 (Bus Request/ Bus Grant) These requests are used by other local bus masters to force the processor to release the local bus at the end of the processor’s current bus cycle. These pins are bidirectional. The request on𝐆𝐓𝟎 will have higher priority than𝐆𝐓𝟏 𝐋𝐎𝐂 𝐊 An output signal activated by the LOCK prefix instruction. Remains active until the completion of the instruction prefixed by LOCK. The 8086 output low on the 𝐋𝐎𝐂𝐊 pin while executing an instruction prefixed by LOCK to prevent other bus masters from gaining control of the system bus. 15 8086 Microprocessor Architecture 16 8086 Microprocessor Architecture Execution Unit (EU) Bus Interface Unit (BIU) EU executes instructions that BIU fetches instructions, reads data have already been fetched by the from memory and I/O ports, writes BIU. data to memory and I/ O ports. BIU and EU functions separately. 17 8086 Architecture Bus Interface Unit (BIU) Microprocessor Dedicated Adder to generate 20 bit address Four 16-bit segment registers Code Segment (CS) Data Segment (DS) Stack Segment (SS) Extra Segment (ES) Segment Registers >> 18 8086 Microprocessor Architecture 8086 registers 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 categorized into 4 groups OF DF IF TF SF ZF AF PF CF Sl.No. Type Register width Name of register 1 General purpose register 16 bit AX, BX, CX, DX 8 bit AL, AH, BL, BH, CL, CH, DL, DH 2 Pointer register 16 bit SP, BP 3 Index register 16 bit SI, DI 4 Instruction Pointer 16 bit IP 5 Segment register 16 bit CS, DS, SS, ES 6 Flag (PSW) 16 bit Flag register 18 8086 Microprocessor Architecture Registers and Special Functions Register Name of the Register Special Function AX 16-bit Accumulator Stores the 16-bit results of arithmetic and logic operations AL 8-bit Accumulator Stores the 8-bit results of arithmetic and logic operations BX Base register Used to hold base value in base addressing mode to access memory data CX Count Register Used to hold the count value in SHIFT, ROTATE and LOOP instructions DX Data Register Used to hold data for multiplication and division operations SP Stack Pointer Used to hold the offset address of top stack memory BP Base Pointer Used to hold the base value in base addressing using SS register to access data from stack memory SI Source Index Used to hold index value of source operand (data) for string instructions DI Data Index Used to hold the index value of destination operand (data) for string 19 operations 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Registers 8086’s 1-megabyte The 8086 can Programs obtain access memory is divided directly address four to code and data in into segments of (256 Ksegments bytes within the 1 the segments by up to 64K bytes M byte of memory) at a changing the segment each. particular time. register content to point to the desired segments. 21 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Code Segment Registers Register 16-bit CS contains the base or start of the current code segment; IP contains the distance or offset from this address to the next instruction byte to be fetched. BIU computes the 20-bit physical address by logically shifting the contents of CS 4-bits to the left and then adding the 16-bit contents of IP. That is, all instructions of a program are relative to the contents of the CS register multiplied by 16 and then offset is added provided by the IP. 22 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Data Segment Registers Register 16-bit Points to the current data segment; opera for most instructions are fetched from this segmen The 16-bit contents of the Source Index (S or Destination Index (DI) or a 16-bit displacement are used as offset for computing the 20-bit physical address. 23 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Stack Segment Registers Register 16-bit Points to the current stack. The 20-bit physical stack address is calculated from the Stack Segment (SS) and the Stack Pointer (SP) for stack instructions such as PUSH and POP. In based addressing mode, the 20-bit physical stack address is calculated from the Stack segment (SS) and the Base Pointer (BP). 24 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Extra Segment Registers Register 16-bit Points to the extra segment in which data excess of 64K pointed to by the DS) is stored. String instructions use the ES and DI to determine the 20- bit physical address for the destination. 25 8086 Architecture Bus Interface Unit (BIU) Microprocessor Segment Instruction Pointer Registers 16-bit Always points to the next instruction to be executed within the currently executing code segment. So, this register contains the 16-bit offset address pointing to the next instruction code within the 64Kb of the code segment area. Its content is automatically incremented as the execution of the next instruction takes place. 26 8086 Architecture Bus Interface Unit (BIU) Microprocessor Instruction queue A group of First-In-First- Out (FIFO) in which up to 6 bytes of instruction code are pre fetched from the memory ahead of time. This is done in order to by speed upoverlapping the instruction execution fetch execution. with This mechanism is known as pipelining. 27 8086 Architecture Execution Unit (EU) Microprocessor EU decodes and executes instructions. A decoder in the EU control system translates instructions. 16-bit ALU for performing arithmetic and logic operation Four general purpose registers(AX, BX, CX, DX); Pointer registers (Stack Pointer, Base Pointer); and Some of the 16 bit registers can Index registers (Source be used as two 8 bit registers as Index, Destination Index) : each of 16-bits AX can be used as AH and AL BX can be used as BH and BL CX can be used as CH and CL 27 DX can be used as DH and 8086 Architecture Execution Unit (EU) Microprocessor EU Accumulator Register (AX) Registers Consists of two 8-bit registers AL and AH, which can be combined together and used as a 16-bit register AX. AL in this case contains the low order byte of the word, and AH contains the high-order byte. The I/O instructions use the AX or AL for inputting / outputting 16 or 8 bit data to or from an I/O port. Multiplication and Division instructions also use the AX or AL. 29 8086 Architecture Execution Unit (EU) Microprocessor EU Base Register (BX) Registers Consists of two 8-bit registers BL and BH, which can be combined together and used as a 16-bit register BX. BL in this case contains the low-order byte of the word, and BH contains the high-order byte. This is the only general purpose register whose contents can be used for addressing the 8086 memory. All memory references utilizing this register content for addressing use DS as the default segment register. 30 8086 Architecture Execution Unit (EU) Microprocessor EU Counter Register (CX) Registers Consists of two 8-bit registers CL and CH, which can be combined together and used as a 16-bit register CX. When combined, CL register contains the low order byte of the word, and CH contains the high-order byte. Instructions such as SHIFT, ROTATE and LOOP use the contents of CX as a counter. Example: The instruction LOOP START automatically decrements CX by 1 without affecting flags and will check if [CX] = 0. If it is zero, 8086 executes the next instruction; otherwise the 8086 branches to the label START. 31 8086 Architecture Execution Unit (EU) Microprocessor EU Data Register (DX) Registers Consists of two 8-bit registers DL and DH, which can be combined together and used as a 16-bit register DX. When combined, DL register contains the low order byte of the word, and DH contains the high-order byte. Used to hold the high 16-bit result (data) in 16 X 16 32 ÷ 16 division and the 16-bit reminder after division. multiplication or the high 16-bit dividend (data) before a 32 8086 Architecture Execution Unit (EU) Microprocessor EU Stack Pointer (SP) and Base Pointer (BP) Registers SP and BP are used to access data in the stack segment. SP is used as an offset from the current SS during execution of instructions that involve the stack segment in the external memory. SP contents are automatically updated (incremented/ decremented) due to execution of a POP or PUSH instruction. BP contains an offset address in the current SS, which is used by instructions utilizing the based addressing mode. 33 8086 Architecture Execution Unit (EU) Microprocessor EU Source Index (SI) and Destination Index (DI) Registers Used in indexed addressing. Instructions that process data strings use the SI and DI registers together with DS and ES respectively in order to distinguish between the source and destination addresses. 34 8086 Architecture Execution Unit (EU) Microprocessor EU Source Index (SI) and Destination Index (DI) Registers Used in indexed addressing. Instructions that process data strings use the SI and DI registers together with DS and ES respectively in order to distinguish between the source and destination addresses. 35 8086 Architecture Execution Unit (EU) Microprocessor Auxiliary Carry Flag Carry Flag Flag Register This is set, if there is a carry from the This flag is set, when there is lowest nibble, i.e, bit three during addition, or borrow for the lowest a carry out of MSB in case of nibble, i.e, bit three, during addition or a borrow in case subtraction. of subtraction. Sign Flag Zero Flag Parity Flag This flag is set, when the This flag is set, if the result of This flag is set to 1, if the lower result of any computation the computation or comparison byte of the result contains even is negative performed by an instruction is number of 1’s ; for odd number zero of 1’s set to zero. 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 OF DF IF TF SF ZF AF PF CF Tarp Flag Over flow Flag If this flag is set, the processor This flag is set, if an overflow occurs, i.e, if the result of a signed enters the single step execution operation is large enough to accommodate in a destination mode by generating internal register. The result is of more than 7-bits in size in case of 8-bit signed operation and more than 15-bits in size in case of 16-bit interrupts after the execution of sign operations, then the overflow will be set. each instruction Direction Flag Interrupt Flag This is used by string manipulation instructions. If this flag bit is ‘0’, the string is processed beginning from the lowest Causes the 8086 to recognize address to the highest address, i.e., auto incrementing mode. external mask interrupts; clearing IF Otherwise, the string is processed from the highest address disables these interrupts. towards the lowest address, i.e., auto incrementing mode. 35 ADDRESSING MODES & Instruction set 8086 Microprocessor Introduction Program A set of instructions written to solve a problem. Instruction Directions which a microprocessor follows to execute a task or part of a task. Computer language High Level Low Level Machine Assembly Language Language ⯀ Binary bits ⯀ English Alphabets ⯀ ‘Mnemonics’ ⯀ Mnemonics Assembler Machine 37 Language ADDRESSING MODES 8086 Microprocessor Addressing Modes Every instruction of a program has to operate on a data. The different ways in which a source operand is denoted in an instruction are known as addressing modes. 1. Register Addressing Group I : Addressing modes for 2. Immediate Addressing register and immediate data 3. Direct Addressing 4. Register Indirect Addressing 5. Based Addressing Group II : Addressing modes for 6. Indexed Addressing memory data 7. Based Index Addressing 8. String Addressing 9. Direct I/O port Addressing Group III : Addressing modes for 10. Indirect I/O port Addressing I/O ports 11. Relative Addressing Group IV : Relative Addressing mode 12. Implied Addressing Group V : Implied Addressing m4o0de 8086 Group I : Addressing modes for Microprocessor Addressing register and immediate Modes data 1. Register The instruction will specify the name of Addressing the register which holds the data to be 2. Immediate Addressing operated by the instruction. 3. Direct Addressing Example: 4. Register Indirect Addressing MOV CL, 5. Based Addressing DH The content of 8-bit register DH is moved 6. Indexed Addressing to another 8-bit register CL 7. Based Index Addressing (CL)  (DH) 8. String Addressing 9. Direct I/O port Addressing 10. Indirect I/O port Addressing 11. Relative Addressing 12. Implied Addressing 41 8086 Group I : Addressing modes for Microprocessor Addressing register and immediate Modes data 1. Register Addressing In immediate addressing mode, an 8-bit or 16-bit 2. Immediate Addressing data is specified as part of the instruction 3. Direct Addressing Example: 4. Register Indirect Addressing MOV DL, 08H 5. Based Addressing The 8-bit data (08H) given in the instruction is 6. Indexed Addressing moved to DL 7. Based Index Addressing (DL)  08H 8. String Addressing MOV AX, 0A9FH 9. Direct I/O port Addressing The 16-bit data (0A9FH) given in the instruction is 10. Indirect I/O port Addressing moved to AX register 11. Relative Addressing (AX)  0A9FH 12. Implied Addressing 42 8086 Microprocessor Addressing Modes : Memory Access 20 Address lines  8086 can address up to 2 = 1M bytes of memory 20 However, the largest register is only 16 bits Physical Address will have to be calculated Physical Address : Actual address of a byte in memory. i.e. the value which goes out onto the address bus. Memory Address represented in the form – Seg : Offset (Eg - 89AB:F012) Each time the processor wants to access memory, it takes the contents of a segment register, shifts it one hexadecimal place to the 16 bytes of left (same as multiplying by 1610), then add the contiguous memory required offset to form the 20- bit address 89AB : F012 89AB 89AB0 (Paragraph to byte 89AB x 10 = 89AB0) F012 0F012 (Offset is already in byte unit) + ------- 98AC2 (The absolute 44 address) 8086 Group II : Addressing modes Microprocessor Addressing Modes for memory data 1. Register Addressing 2. Immediate Addressing Here, the effective address of the 3. Direct Addressing memory location at which the data operand is 4. Register Indirect Addressing stored is given in the instruction. 5. Based Addressing The effective address is just a 16-bit number written directly in the instruction. 6. Indexed Addressing Example: 7. Based Index Addressing MOV BX, [1354H] 8. String MOV BL, [0400H] Addressing 9. Direct I/O port Addressing The square brackets around the 1354H denotes 10. Indirect I/O port Addressing the contents of the memory location. When executed, this instruction will copy the 11. Relative Addressing contents of the memory location into BX register. 12. Implied Addressing This addressing mode is called direct because the displacement of the operand from the segment base is specified directly in the instruction. 46 Group II : Addressing modes 8086 Addressing Modes Microprocessor for memory data 1. Register In Register indirect addressing, name of Addressing the register which holds the effective address 2. Immediate Addressing (EA) will be specified in the instruction. 3. Direct Addressing Registers used to hold EA are any of the following registers: 4. Register Indirect Addressing BX, BP, DI and SI. 5. Based Addressing Content of the DS register is used for 6. Indexed Addressing address calculation. base 7. Based Index Addressing Example: Note : Register/ memory 8. String Addressing enclosed in brackets refer MOV CX, [BX] to content of register/ 9. Direct I/O port Addressing memory Operations: 10. Indirect I/O port Addressing EA = (BX) 11. Relative Addressing BA = (DS) x 1610 MA = BA + EA 12. Implied Addressing (CX)  (MA) or, (CL)  (MA) (CH)  (MA +1) 47 8086 Group II : Addressing modes Microprocessor Addressing for memory data Modes 1. Register In Based Addressing, BX or BP is used to hold Addressing base value for effective addressthe and a signed 8- 2. Immediate Addressing or unsigned 16-bit displacement will be specified bit in the instruction. 3. Direct Addressing In case of 8-bit displacement, it is sign extended 4. Register Indirect Addressing to 16-bit before adding to the base value. 5. Based Addressing When BX holds the base value of EA, 20-bit physical address is calculated from BX and DS. 6. Indexed Addressing When BP holds the base value of EA, BP and SS 7. Based Index Addressing is 8. String Addressing used. Example: 9. Direct I/O port Addressing MOV AX, [BX + 08H] 10. Indirect I/O port Addressing Operations: 11. Relative Addressing 0008H  08H (Sign extended) 12. Implied Addressing EA = (BX) + 0008H BA = (DS) x 1610 MA = BA + EA (AX)  (MA) or, (AL)  (MA) 48 (AH)  (MA + 1) 8086 Group II : Addressing modes Microprocessor Addressing for memory data Modes 1. Register SI or DI register is used to hold an index value for Addressing memory data and a signed 8-bit or unsigned 16- 2. Immediate Addressing bit displacement will be specified in the instruction. 3. Direct Addressing Displacement is added to the index value in SI or 4. Register Indirect Addressing DI register to obtain the EA. 5. Based Addressing In case of 8-bit displacement, it is sign extended to 16-bit before adding to the base value. 6. Indexed Addressing 7. Based Index Addressing Example: 8. String Addressing MOV CX, [SI + 0A2H] 9. Direct I/O port Addressing Operations: 10. Indirect I/O port Addressing FFA2H  A2H (Sign extended) 11. Relative Addressing EA = (SI) + FFA2H 12. Implied Addressing BA = (DS) x 1610 MA = BA + EA (CX)  (MA) or, (CL)  (MA) (CH)  (MA + 1) 49 8086 Group II : Addressing modes Microprocessor Addressing Modes for memory data 1. Register In Based Index Addressing, the effective address Addressing is computed from the sum of a base register 2. Immediate Addressing (BX or BP), an index register (SI or DI) and a displacement. 3. Direct Addressing Example: 4. Register Indirect Addressing MOV DX, [BX + SI + 0AH] 5. Based Addressing Operations: 6. Indexed Addressing 000AH  0AH (Sign extended) 7. Based Index Addressing 8. String EA = (BX) + (SI) + 000AH Addressing BA = (DS) x 1610 9. Direct I/O port Addressing MA = BA + EA 10. Indirect I/O port Addressing (DX)  (MA) or, 11. Relative Addressing (DL)  (MA) (DH)  (MA + 1) 12. Implied Addressing 50 8086 Group II : Addressing modes Microprocessor Addressing Modes for memory data 1. Register Employed in string operations to operate on Addressing string data. 2. Immediate Addressing The effective address (EA) of source data is 3. Direct Addressing stored in SI register and the EA of destination is stored in DI register. 4. Register Indirect Addressing Segment register for calculating base address of 5. Based Addressing source data is DS and that of the destination data is ES 6. Indexed Addressing 7. Based Index Addressing Example: MOVS BYTE 8. String Addressing Operations: 9. Direct I/O port Addressing Calculation of source memory location: 10. Indirect I/O port Addressing EA = (SI) BA = (DS) x 1610 MA = BA + EA 11. Relative Addressing Calculation of destination memory location: EAE = (DI) BAE = (ES) x 1610 MAE = BAE + EAE 12. Implied Addressing Note : Effective address of (MAE)  (MA) the Extra segment register If DF = 1, then (SI)  (SI) – 1 and (DI) = (DI) - 1 If DF = 0, then (SI)  (SI) +1 and (DI) = (DI)51+ 1 8086 Group III : Addressing Microprocessor Addressing modes for I/O ports Modes 1. Register These addressing modes are used to access Addressing data from standard I/O mapped devices or ports. 2. Immediate Addressing In direct port addressing mode, an 8-bit port 3. Direct Addressing address is directly specified in the instruction. 4. Register Indirect Addressing Example: IN AL, [09H] 5. Based Addressing Operations: PORTaddr = 09H (AL)  (PORT) 6. Indexed Addressing Content of port with address 09H is 7. Based Index Addressing moved to AL register 8. String Addressing In indirect port addressing mode, the instruction 9. Direct I/O port Addressing will specify the name of the register which holds the port address. In 8086, the 16-bit port 10. Indirect I/O port Addressing address is stored in the DX register. 11. Relative Addressing Example: OUT [DX], AX 12. Implied Addressing Operations: PORTaddr = (DX) (PORT)  (AX) Content of AX is moved to port whose address is specified by DX register. 52 8086 Group IV : Relative Microprocessor Addressing Addressing Modes mode 1. Register Addressing 2. Immediate Addressing 3. Direct Addressing In this addressing mode, the effective address of a program instruction is specified relative 4. Register Indirect Addressing to Instruction Pointer (IP) by an 8-bit signed displacement. 5. Based Addressing Example: JZ 0AH 6. Indexed Addressing Operations: 7. Based Index Addressing 8. String 000AH  0AH (sign extend) Addressing 9. Direct I/O port Addressing If ZF = 1, then 10. Indirect I/O port Addressing EA = (IP) + 000AH BA = (CS) x 1610 11. Relative Addressing MA = BA + EA 12. Implied Addressing If ZF = 1, then the program control jumps to new address calculated above. If ZF = 0, then next instruction of the program is executed. 53 8086 Group IV : Implied Microprocessor Addressing Addressing Modes mode 1. Register Addressing 2. Immediate Addressing 3. Direct Addressing 4. Register Indirect Addressing 5. Based Addressing 6. Indexed Addressing Instructions using this mode have no operands. The instruction itself will specify the data to 7. Based Index Addressing be operated by the instruction. 8. String Addressing Example: CLC 9. Direct I/O port Addressing This clears the carry flag to 10. Indirect I/O port Addressing zero. 11. Relative Addressing 12. Implied Addressing 54 INSTRUCTION SET 8086 Microprocessor Instruction Set 8086 supports 6 types of instructions. 1. Data Transfer Instructions 2. Arithmetic Instructions 3. Logical Instructions 4. String manipulation Instructions 5. Process Control Instructions 6. Control Transfer Instructions 56 8086 Microprocessor Instruction Set 1. Data Transfer Instructions Instructions that are used to transfer data/ address in to registers, memory locations and I/O ports. Generally involve two operands: Source operand and Destination operand of the same size. Source: Register or a memory location or an immediate data Destination : Register or a memory location. The size should be a either a byte or a word. A 8-bit data can only be moved to 8-bit register/ memory and a 16-bit data can be moved to 16-bit register/ memory. 57 8086 Microprocessor Instruction Set 1. Data Transfer Instructions Mnemonics: MOV, XCHG, PUSH, POP, IN, OUT … MOV reg2/ mem, reg1/ mem MOV reg2, reg1 (reg2)  (reg1) MOV mem, reg1 (mem)  (reg1) MOV reg2, (reg2)  (mem) mem MOV reg/ mem, data MOV reg, data (reg)  data MOV mem, data (mem)  data XCHG reg2/ mem, reg1 XCHG reg2, reg1 (reg2)  (reg1) XCHG mem, reg1 (mem)  (reg1) 58 8086 Microprocessor Instruction Set 1. Data Transfer Instructions Mnemonics: MOV, XCHG, PUSH, POP, IN, OUT … PUSH reg16/ mem PUSH reg16 (SP)  (SP) – 2 MA S = (SS) x 1610 + SP (MA S ; MA S + 1)  (reg16) PUSH mem (SP)  (SP) – 2 MA S = (SS) x 1610 + SP (MA S ; MA S + 1)  (mem) POP reg16/ mem POP reg16 MA S = (SS) x 1610 + SP (reg16)  (MA S ; MA S + 1) (SP)  (SP) + 2 POP mem MA S = (SS) x 1610 + SP (mem)  (MA S ; MA S + 1) (SP)  (SP) + 2 59 8086 Microprocessor Instruction Set 1. Data Transfer Instructions Mnemonics: MOV, XCHG, PUSH, POP, IN, OUT … IN A, [DX] OUT [DX], A IN AL, [DX] PORTaddr = (DX) OUT [DX], AL PORTaddr = (DX) (AL)  (PORT) (PORT)  (AL) IN AX, [DX] PORTaddr = (DX) OUT [DX], AX PORTaddr = (DX) (AX)  (PORT) (PORT)  (AX) IN A, addr8 OUT addr8, A IN AL, addr8 (AL)  (addr8) OUT addr8, AL (addr8)  (AL) IN AX, addr8 (AX)  (addr8) OUT addr8, (addr8)  (AX) AX 60 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… ADD reg2/ mem, reg1/mem ADC reg2, reg1 (reg2)  (reg1) + (reg2) ADC reg2, mem (reg2)  (reg2) + (mem) ADC mem, reg1 (mem)  (mem)+(reg1) ADD reg/mem, data ADD reg, data (reg)  (reg)+ data ADD mem, data (mem)  (mem)+data ADD A, data ADD AL, data8 (AL)  (AL) + data8 ADD AX, data16 (AX)  (AX) +data16 61 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… ADC reg2/ mem, reg1/mem ADC reg2, reg1 (reg2)  (reg1) + (reg2)+CF ADC reg2, mem (reg2)  (reg2) + (mem)+CF ADC mem, reg1 (mem)  (mem)+(reg1)+CF ADC reg/mem, data ADC reg, data (reg)  (reg)+ data+CF ADC mem, data (mem)  (mem)+data+CF ADDC A, data ADD AL, data8 (AL)  (AL) + data8+CF ADD AX, data16 (AX)  (AX) +data16+CF 62 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… SUB reg2/ mem, reg1/mem SUB reg2, reg1 (reg2)  (reg1) - (reg2) SUB reg2, mem (reg2)  (reg2) - (mem) SUB mem, reg1 (mem)  (mem) - (reg1) SUB reg/mem, data SUB reg, data (reg)  (reg) - data SUB mem, data (mem)  (mem) - data SUB A, data SUB AL, data8 (AL)  (AL) - data8 SUB AX, data16 (AX)  (AX) - data16 63 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… SBB reg2/ mem, reg1/mem SBB reg2, reg1 (reg2)  (reg1) - (reg2) - CF SBB reg2, mem (reg2)  (reg2) - (mem)- CF SBB mem, reg1 (mem)  (mem) - (reg1) –CF SBB reg/mem, data SBB reg, data (reg)  (reg) – data - CF SBB mem, data (mem)  (mem) - data - CF SBB A, data SBB AL, data8 (AL)  (AL) - data8 - CF SBB AX, data16 (AX)  (AX) - data16 - CF 64 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… INC reg/ mem INC reg8 (reg8)  (reg8) + 1 INC reg16 (reg16)  (reg16) + 1 INC mem (mem)  (mem) + 1 DEC reg/ mem DEC reg8 (reg8)  (reg8) - 1 DEC reg16 (reg16)  (reg16) - 1 DEC mem (mem)  (mem) - 1 65 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… MUL reg/ mem MUL reg For byte : (AX)  (AL) x (reg8) For word : (DX)(AX)  (AX) x (reg16) MUL mem For byte : (AX)  (AL) x (mem8) For word : (DX)(AX)  (AX) x (mem16) IMUL reg/ mem IMUL reg For byte : (AX)  (AL) x (reg8) For word : (DX)(AX)  (AX) x (reg16) IMUL mem For byte : (AX)  (AX) x (mem8) For word : (DX)(AX)  (AX) x (mem16) 66 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… DIV reg/ mem DIV reg For 16-bit :- 8-bit : (AL)  (AX) :- (reg8) Quotient (AH)  (AX) MOD(reg8) Remainder For 32-bit :- 16-bit : (AX)  (DX)(AX) :- (reg16) Quotient (DX)  (DX)(AX) MOD(reg16) DIV mem Remainder For 16-bit :- 8-bit : (AL)  (AX) :- (mem8) Quotient (AH)  (AX) MOD(mem8) Remainder For 32-bit :- 16-bit : (AX)  (DX)(AX) :- (mem16) Quotient (DX)  (DX)(AX) MOD(mem16) Remainder 67 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… IDIV reg/ mem IDIV reg For 16-bit :- 8-bit : (AL)  (AX) :- (reg8) Quotient (AH)  (AX) MOD(reg8) Remainder For 32-bit :- 16-bit : (AX)  (DX)(AX) :- (reg16) Quotient (DX)  (DX)(AX) MOD(reg16) IDIV mem Remainder For 16-bit :- 8-bit : (AL)  (AX) :- (mem8) Quotient (AH)  (AX) MOD(mem8) Remainder For 32-bit :- 16-bit : (AX)  (DX)(AX) :- (mem16) Quotient (DX)  (DX)(AX) MOD(mem16) Remainder 68 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… CMP reg2/mem, reg1/ mem CMP reg2, reg1 Modify flags  (reg2) – (reg1) If (reg2) > (reg1) then CF=0, ZF=0, SF=0 If (reg2) < (reg1) then CF=1, ZF=0, SF=1 If (reg2) = (reg1) then CF=0, ZF=1, SF=0 CMP reg2, mem Modify flags  (reg2) – (mem) If (reg2) > (mem) then CF=0, ZF=0, SF=0 If (reg2) < (mem) then CF=1, ZF=0, SF=1 If (reg2) = (mem) then CF=0, ZF=1, SF=0 CMP mem, reg1 Modify flags  (mem) – (reg1) If (mem) > (reg1) then CF=0, ZF=0, SF=0 If (mem) < (reg1) then CF=1, ZF=0, SF=1 If (mem) = (reg1) then CF=0, ZF=1, SF=0 69 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… CMP reg/mem, data CMP reg, data Modify flags  (reg) – (data) If (reg) > data then CF=0, ZF=0, SF=0 If (reg) < data then CF=1, ZF=0, SF=1 If (reg) = data then CF=0, ZF=1, SF=0 CMP mem, data Modify flags  (mem) – (mem) If (mem) > data then CF=0, ZF=0, SF=0 If (mem) < data then CF=1, ZF=0, SF=1 If (mem) = data then CF=0, ZF=1, SF=0 70 8086 Microprocessor Instruction Set 2. Arithmetic Instructions Mnemonics: ADD, ADC, SUB, SBB, INC, DEC, MUL, DIV, CMP… CMP A, data CMP AL, data8 Modify flags  (AL) – data8 If (AL) > data8 then CF=0, ZF=0, SF=0 If (AL) < data8 then CF=1, ZF=0, SF=1 If (AL) = data8 then CF=0, ZF=1, SF=0 CMP AX, data16 Modify flags  (AX) – data16 If (AX) > data16 then CF=0, ZF=0, SF=0 If (mem) < data16 then CF=1, ZF=0, SF=1 If (mem) = data16 then CF=0, ZF=1, SF=0 71 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 72 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 73 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 74 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 75 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 76 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 77 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 78 8086 Microprocessor Instruction Set 3. Logical Instructions Mnemonics: AND, OR, XOR, TEST, SHR, SHL, RCR, RCL … 79 8086 Microprocessor Instruction Set 4. String Manipulation Instructions  String Sequence of bytes or words :  8086 instruction set includes instruction string movement, comparison, scan, for load and store.  REP instruction : used to repeat execution of string prefix instructions  String instructions end with S or SB or SW. S represents string, SB string byte and SW string word.  Offset or effective address of the source operand is stored in SI register and that of the destination operand is stored in DI register.  Depending on the status of DF, SI and DI registers are automatically updated.  DF = 0  SI and DI are incremented by 1 for byte and 2 for word.  DF = 1  SI and DI are decremented by 1 for byte and 2 for word. 80 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS REP REPZ/ REPE While CX  0 and ZF = 1, repeat execution of string instruction and (Repeat CMPS or SCAS (CX)  (CX) – 1 until ZF = 0) REPNZ/ REPNE While CX  0 and ZF = 0, repeat execution of string instruction (Repeat CMPS or SCAS and (CX)  (CX) - 1 until ZF = 1) 81 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS MOVS MOVSB MA = (DS) x 1610 + (SI) MAE = (ES) x 1610 + (DI) (MAE)  (MA) If DF = 0, then (DI)  (DI) + 1; (SI)  (SI) + 1 If DF = 1, then (DI)  (DI) - 1; (SI)  (SI) - 1 MOVSW MA = (DS) x 1610 + (SI) MAE = (ES) x 1610 + (DI) (MAE ; MAE + 1)  (MA; MA + 1) If DF = 0, then (DI)  (DI) + 2; (SI)  (SI) + 2 If DF = 1, then (DI)  (DI) - 2; (SI)  (SI) - 2 82 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS Compare two string byte or string word CMPS CMPSB MA = (DS) x 1610 + (SI) MAE = (ES) x 1610 + (DI) Modify flags  (MA) - (MAE) If (MA) > (MAE), then CF = 0; ZF = 0; SF = 0 CMPSW If (MA) < (MAE), then CF = 1; ZF = 0; SF = 1 If (MA) = (MAE), then CF = 0; ZF = 1; SF = 0 For byte operation If DF = 0, then (DI)  (DI) + 1; (SI)  (SI) + 1 If DF = 1, then (DI)  (DI) - 1; (SI)  (SI) - 1 For word operation If DF = 0, then (DI)  (DI) + 2; (SI)  (SI) + 2 If DF = 1, then (DI)  (DI) - 2; (SI)  (SI) - 2 83 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS Scan (compare) a string byte or word with accumulator SCAS SCASB MAE = (ES) x 1610 + (DI) Modify flags  (AL) - (MAE) If (AL) > (MAE), then CF = 0; ZF = 0; SF = 0 If (AL) < (MAE), then CF = 1; ZF = 0; SF = 1 If (AL) = (MAE), then CF = 0; ZF = 1; SF = 0 If DF = 0, then (DI)  (DI) + 1 If DF = 1, then (DI)  (DI) – 1 SCASW MAE = (ES) x 1610 + (DI) Modify flags  (AL) - (MAE) If (AX) > (MAE ; MAE + 1), then CF = 0; ZF = 0; SF = 0 If (AX) < (MAE ; MAE + 1), then CF = 1; ZF = 0; SF = 1 If (AX) = (MAE ; MAE + 1), then CF = 0; ZF = 1; SF = 0 If DF = 0, then (DI)  (DI) + 2 If DF = 1, then (DI)  (DI) – 2 84 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS Load string byte in to AL or string word in to AX LODS LODSB MA = (DS) x 1610 + (SI) (AL)  (MA) If DF = 0, then (SI)  (SI) + 1 If DF = 1, then (SI)  (SI) – 1 LODSW MA = (DS) x 1610 + (SI) (AX)  (MA ; MA + 1) If DF = 0, then (SI)  (SI) + 2 If DF = 1, then (SI)  (SI) – 2 85 8086 Microprocessor Instruction Set 4. String Manipulation Instructions Mnemonics: REP, MOVS, CMPS, SCAS, LODS, STOS Store byte from AL or word from AX in to string STOS STOSB MAE = (ES) x 1610 + (DI) (MAE)  (AL) If DF = 0, then (DI)  (DI) + 1 If DF = 1, then (DI)  (DI) – 1 STOSW MAE = (ES) x 1610 + (DI) (MAE ; MAE + 1 )  (AX) If DF = 0, then (DI)  (DI) + 2 If DF = 1, then (DI)  (DI) – 2 86 8086 Microprocessor Instruction Set 5. Processor Control Instructions Mnemonics Explanation STC Set CF  1 CLC Clear CF  0 CMC Complement carry CF  CF/ STD Set direction flag DF  1 CLD Clear direction flag DF  0 STI Set interrupt enable flag IF  1 CLI Clear interrupt enable flag IF  0 NOP No operation HLT Halt after interrupt is set WAIT Wait for TEST pin active ESC opcode mem/ reg Used to pass instruction to a coprocessor which shares the address and data bus with the 8086 LOCK Lock bus during next instruction 87 8086 Microprocessor Instruction Set 6. Control Transfer Instructions Transfer the control to a specific destination or target instruction Do not affect flags  8086 Unconditional transfers Mnemonics Explanation CALL reg/ mem/ disp16 Call subroutine RET Return from subroutine JMP reg/ mem/ disp8/ disp16 Unconditional jump 88 8086 Microprocessor Instruction Set 6. Control Transfer Instructions  8086 signed conditional  8086 unsigned conditional branch instructions branch instructions Checks flags If conditions are true, the program control is transferred to the new memory location in the same segment by modifying the content of IP 89 8086 Microprocessor Instruction Set 6. Control Transfer Instructions  8086 signed conditional  8086 unsigned conditional branch instructions branch instructions Name Alternate name Name Alternate name JE disp8 JZ disp8 JE disp8 JZ disp8 Jump if equal Jump if result is 0 Jump if equal Jump if result is 0 JNE disp8 JNZ disp8 JNE disp8 JNZ disp8 Jump if not equal Jump if not zero Jump if not equal Jump if not zero JG disp8 JNLE disp8 JA disp8 Jump JNBE disp8 Jump if greater Jump if not less or if above Jump if not below equal or equal JGE disp8 JNL disp8 JAE disp8 JNB disp8 Jump if greater Jump if not less Jump if above or Jump if not below than or equal equal JL disp8 JNGE disp8 JB disp8 Jump JNAE disp8 Jump if less than Jump if not if below Jump if not above greater than or equal or equal JLE disp8 JNG disp8 JBE disp8 JNA disp8 Jump if less than Jump if not Jump if below or Jump if not above or equal greater equal 90 8086 Microprocessor Instruction Set 6. Control Transfer Instructions  8086 conditional branch instructions affecting individual flags Mnemonics Explanation JC disp8 Jump if CF = 1 JNC disp8 Jump if CF = 0 JP disp8 Jump if PF = 1 JNP disp8 Jump if PF = 0 JO disp8 Jump if OF = 1 JNO disp8 Jump if OF = 0 JS disp8 Jump if SF = 1 JNS disp8 Jump if SF = 0 JZ disp8 Jump if result is zero, i.e, Z = 1 JNZ disp8 Jump if result is not zero, i.e, Z = 1 91 directive Assembl s er 8086 Microprocessor Assemble Directives Instructions to the Assembler regarding the program being executed. Control the generation of machine codes and organization of the program; but no machine codes are generated for assembler directives. Also called ‘pseudo instructions’ Used to : › specify the start and end of a program › attach value to variables › allocate storage locations to input/ output data › define start and end of segments, procedures, macros etc.. 93 8086 Microprocessor Assemble Directives DB Define Byte DW Define a byte type (8-bit) variable SEGMENT Reserves specific amount of memory ENDS locations to each variable ASSUME Range : 00H – FFH for unsigned value; 00H – 7FH for positive value and ORG 80H – FFH for negative value END EVEN EQU General form : variable DB value/ values PROC FAR Example: NEAR LIST DB 7FH, 42H, 35H ENDP Three consecutive memory locations are reserved for SHORT the variable LIST and each data specified in the instruction are stored as initial value in the MACRO reserved memory location ENDM 94 8086 Microprocessor Assemble Directives DB Define Word DW Define a word type (16-bit) variable SEGMENT Reserves two consecutive memory locations ENDS to each variable ASSUME Range : 0000H – FFFFH for unsigned value; 0000H – 7FFFH for positive value and ORG 8000H – FFFFH for negative value END EVEN EQU General form : variable DW value/ values PROC FAR Example: NEAR ALIST DW 6512H, 0F251H, 0CDE2H ENDP Six consecutive memory locations are reserved for SHORT the variable ALIST and each 16-bit data specified in the instruction is stored in two consecutive memory MACRO location. ENDM 95 8086 Microprocessor Assemble Directives DB SEGMENT : Used to indicate the beginning of DW a code/ data/ stack segment ENDS : Used to indicate the end of a code/ SEGMENT data/ stack segment ENDS General form: ASSUME ORG END Segnam SEGMENT EVEN … EQU … Program code … or … Data Defining PROC … Statements FAR … NEAR Segnam ENDS ENDP SHOR T MACRO User defined name of the segment ENDM 96 8086 Microprocessor Assemble Directives DB Informs the assembler the name of the program/ data segment that should be used DW for a specific segment. SEGMENT General form: ENDS ASSUME segreg : segnam,.. , segreg : ASSUME segnam ORG User defined name of END Segment Register the segment EVEN EQU PROC Example: FAR NEAR ASSUME CS: ACODE, DS:ADATA Tells the compiler that the instructions of the program are ENDP stored in the segment ACODE and data are stored in the SHORT segment ADATA MACRO ENDM 97 8086 Microprocessor Assemble Directives ORG (Origin) is used to assign the starting DB address (Effective address) for a program/ data segment DW END is used to terminate a program; statements after END will be ignored SEGMENT ENDS EVEN : Informs the assembler to store program/ data segment starting from an even address ASSUME EQU (Equate) is used to attach a value to a variable ORG Examples: END EVEN ORG 1000H Informs the assembler that the statements EQU following ORG 1000H should be stored in memory starting with effective address 1000H PROC FAR LOOP EQU 10FEH Value of variable LOOP is 10FEH NEAR ENDP _SDATA SEGMENT In this data segment, effective address of SHOR ORG 1200H memory location assigned to A will be 1200H A DB 4CH and that of B will be 1202H and 1203H. T EVEN B DW MACRO 1052H 98 _SDATA ENDS ENDM 8086 Microprocessor Assemble Directives PROC Indicates the beginning of a DB procedure ENDP End of DW procedure FAR Intersegment call SEGMENT ENDS NEAR Intrasegment call General form ASSUME ORG procname PROC[NEAR/ FAR] END EVEN … Program statements of the … EQU … procedure RET Last statement of PROC the procedure ENDP FAR procname ENDP NEAR SHORT User defined name of the procedure MACRO ENDM 99 8086 Microprocessor Assemble Directives DB Examples: DW SEGMENT ADD64 PROC NEAR The subroutine/ procedure named ADD64 is ENDS declared as NEAR and so the assembler will … code the CALL and RET instructions involved … in this procedure as near call and return … ASSUME RET ORG ADD64 ENDP END EVEN EQU CONVERT PROC FAR The subroutine/ procedure named CONVERT is declared as FAR and so the assembler will … code the CALL and RET instructions involved PROC … in this procedure as far call and return ENDP … FAR RET NEAR CONVERT ENDP SHOR T MACRO ENDM 100 8086 Microprocessor Assemble Directives DB Reserves one memory location for 8-bit signed displacement in jump instructions DW Example: SEGMENT ENDS ASSUME JMP SHORT The directive will reserve one AHEAD memory location for 8-bit displacement named AHEAD ORG END EVEN EQU PROC ENDP FAR NEAR SHORT MACRO ENDM 101 8086 Microprocessor Assemble Directives DB MACRO Indicate the beginning of a macro DW ENDM End of a macro SEGMENT General form: ENDS ASSUME macroname MACRO[Arg1, Arg2...] Program … statements ORG … in the macro END … EVEN EQU macroname ENDM PROC ENDP FAR User defined name of NEAR the macro SHORT MACRO ENDM 102

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