OCR A Level Physics Resistance & Resistivity PDF

Head to savemyexams.com for more awesome resources OCR A Level Physics 4.2 Resistance & Resistivity Contents 4.2.1 Resistance 4.2.2 Ohm's Law & I-V Characteristics 4.2.3 Investigating Electrical Characteristics of Components 4.2.4 T he Light-Dependent Resistor (LDR) 4.2.5 Resistivity 4.2.6 Determining the Resistivity of a Metal 4.2.7 T hermistors Page 1 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources 4.2.1 Resistance Your notes Resistance Resistance is defined as the opposition to current For a given potential difference: The higher the resistance the lower the current Wires are often made from copper because copper has a low electrical resistance Materials with low resistance are known as good conductors The resistance R of a conductor is defined as the ratio of the potential difference V across to the current I in it Resistance is measured in Ohms (Ω) Ω is the Greek capital letter 'Omega' An Ohm is defined as one volt per ampere (1 V A-1) The resistance controls the siz e of the current in a circuit A higher resistance means a smaller current A lower resistance means a larger current All electrical components, including wires, have some value of resistance Worked example Calculate the potential difference through a resistor of resistance 10 Ω if there is a current of 0.3 A through it. Step 1: List the known quantities Page 2 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Resistance, R = 10 Ω Current, I = 0.3 A Your notes Step 2: Write the resistance equation Step 3: Rearrange for V V = IR Step 4: Substitute in the values V = 0.3 × 10 = 3 V Exam Tip Although all electrical components have resistance, the resistance of wires is taken to be 0 in exam questions. Page 3 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources 4.2.2 Ohm's Law & I-V Characteristics Your notes Ohm's Law & I-V Characteristics Ohm’s law states: For a conductor at a constant temperature, the current through it is proportional to the potential difference across it Constant temperature implies constant resistance Ohm's law is represented in the equation below: Measuring the variation of current with potential difference through a fixed resistor will produce a straight line graph, such as the one below Circuit for plotting graphs of current against voltage Page 4 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Since the gradient is constant, the resistance R of the resistor can be calculated by using 1 ÷ gradient of the graph An electrical component obeys Ohm’s law if its graph of current against potential difference is a straight line through the origin A resistor does obey Ohm’s law A filament lamp does not obey Ohm’s law This applies to any metal wires, provided that the current isn’t large enough to increase their temperature I–V Characteristics As the potential difference (voltage) across a component is increased, the current also increases (by Ohm’s law) The precise relationship between voltage and current is different for different components and can be shown on an I–V graph For an ohmic conductor eg. a fixed resistor: The I–V graph is a straight line through the origin For a non-ohmic conductor, such as A semiconductor diode, the I–V graph is a horizontal line that goes sharply upwards An LED (light-emitting diode), the I–V graph is similar to the semiconductor diode, since it is a specific diode that emits visible light A filament lamp, the I–V graph has an 'S' shaped curve A thermistor, the I–V graph is a curved line with increasing gradient through the origin Page 5 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Your notes Page 6 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes I–V characteristics for an ohmic conductor (e.g. resistor), semiconductor diode, filament lamp, LED and thermistor Ohmic Conductor The I–V graph for an ohmic conductor at constant temperature e.g. a resistor is very simple: The current is directly proportional to the potential difference This is demonstrated by the straight-line graph through the origin Semiconductor Diode The I–V graph for a semiconductor diode is slightly different. A diode is used in a circuit to allow current to flow only in a specific direction When the current is in the direction of the arrowhead symbol, this is forward bias This is shown by the sharp increase in potential difference and current on the right side of the graph When the diode is switched around, it does not conduct and is called reverse bias This is shown by a z ero reading of current or potential difference on the left side of the graph which then goes steeply vertically down For an LED, the I–V graph is identical, except the sharp increase in p.d is further away from the origin as the frequency of the light increases Page 7 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Filament Lamp The I–V graph for a filament lamp shows the current increasing at a proportionally slower rate than the potential difference This is because: As the current increases, the temperature of the filament in the lamp increases Since the filament is a metal, the higher temperature causes an increase in resistance Resistance opposes the current, causing the current to increase at a slower rate Where the graph is a straight line, the resistance is constant The resistance increases as the graph curves The filament lamp obeys Ohm's Law for small voltages Thermistor The I–V graph for a thermistor is a shallow curve upwards The increase in the potential difference results in an increase in current which causes the temperature of the thermistor to rise As its temperature rises, its resistance decreases This means even more current is able to flow through Since the current is not directly proportional to the potential difference (the graph is still curved), the thermistor does not obey Ohm's Law Page 8 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Worked example The I–V characteristic of two electrical component X and Y are shown. Which statement is correct? A. The resistance of X increases as the current increases B. At 2 V, the resistance of X is half the resistance of Y C. Y is a semiconductor diode and X is a resistor D. X is a resistor and Y is a filament lamp ANSWER: C The I–V graph X is linear This means the graph has a constant gradient. I/V and the resistance is therefore also constant (since gradient = 1/R) This is the I–V graph for a conductor at constant temperature e.g. a resistor The I–V graph Y starts with z ero gradient and then the gradient increases rapidly This means it has infinite resistance at the start which then decreases rapidly This is characteristic of a device that only has current in one direction e.g a semiconductor diode Therefore, the answer is C Page 9 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Exam Tip Make sure you're confident in drawing the I–V characteristics for different components, as you may be asked to sketch these from memory in exam questions Maths Tip: In maths, the gradient is the slope of the graph The graphs below show a summary of how the slope of the graph represents the gradient Page 10 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources 4.2.3 Investigating Electrical Characteristics of Components Investigating Electrical Characteristics of Components Aim of the Experiment The aim of the experiment is to investigate electrical characteristics for a range of ohmic and non-ohmic components These include a fixed resistor, lamp and diode Variables: Independent variable = Potential difference, V Dependent variable = Current, I Control variables: E.m.f of the power supply Use of the same equipment eg. wires, diodes Equipment List Page 11 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Your notes Resolution of measuring equipment: Variable resistor = 0.005 Ω Voltmeter = 0.1 V Ammeter = 0.01 A Method Page 12 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Circuit diagram of the apparatus set up. The fixed resistor will be replaced by a filament lamp and diode 1. Set up the circuit as shown with the fixed resistor 2. Vary the voltage across the component by changing the resistance of the variable resistor, using a wide range of voltages (between 8-10 readings). Check the appropriate voltage reading on the voltmeter 3. For each voltage, record the value of the current from the ammeter 3 times and calculate the average current 4. Increase the voltage further in steps of 0.5 V and repeat steps 2 and 3 5. Make sure to switch off the circuit in between readings to prevent heating of the component and wires 6. Reverse the terminals of the power supply and take readings for the negative voltage (and therefore negative current) 7. Replace the fixed resistor with the filament lamp, then the diode, repeating the experiment for each An example of a suitable table might look like this: Page 13 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Analysis of Results Plot a graph of average current against voltage (an I-V graph) for each component If the I-V graph is a straight line, it is an ohmic conductor. This is expected from the fixed resistor This means it obeys Ohm's Law: V = IR If the I-V graph is a curve, it is a non-ohmic conductor. This is expected from the filament lamp and diode Compare the results from the graphs obtained to the known I-V graphs for the resistor, filament lamp and diode. These should look like: Page 14 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes The expected I-V graphs for the resistor, diode and filament lamp Evaluating the Experiment Systematic Errors: The voltmeter and ammeters should start from z ero, to avoid z ero error in the readings Random Errors: Page 15 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources In practice, the voltmeter and ammeter will still have some resistance, therefore the voltages and currents displayed may be slightly inaccurate The temperature of the equipment could affect its resistance. This must be controlled carefully Taking multiple readings of the current for each component will provide a more accurate result and reduce uncertainties Safety Considerations When there is a high current, and a thin wire, the wire will become very hot. Make sure never to touch the wire directly when the circuit is switched on Switch off the power supply right away if burning is smelled Make sure there are no liquids close to the equipment, as this could damage the electrical equipment The components will get hot especially at higher voltages. Be careful when handling them especially the filament lamp Disconnect the power supply in between readings to avoid the components heating up too much Page 16 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources 4.2.4 The Light-Dependent Resistor (LDR) The Light-Dependent Resistor (LDR) A light-dependent resistor (LDR) is a non-ohmic conductor and sensory resistor Its resistance automatically changes depending on the light energy falling onto it (illumination) As the light intensity increases, the resistance of an LDR decreases Resistance of an LDR depends on the light intensity falling on it This is shown by the following graph: Page 17 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Your notes Graph of light intensity and resistance for an LDR LDRs can be used as light sensors, so, they are useful in circuits which automatically switch on lights when it gets dark, for example, street lighting and garden lights In the dark, its resistance is very large (millions of ohms) In bright light, its resistance is small (tens of ohms) Page 18 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes LDRs are used for automatic street lights Worked example Which graph best represents the way in which the current I through an LDR depends upon the potential difference V across it? The correct answer is B As the potential difference across the LDR increases, the light intensity increases causing its resistance to decrease Ohm’s law states that V = IR The resistance is equal to V/I or 1/R = I/V = gradient of the graph Since R decreases, the value of 1/R increases, so the gradient must increase Therefore, I increases with the p.d with an increasing gradient Page 19 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources 4.2.5 Resistivity Your notes Resistivity All materials have some resistance to the flow of charge As free electrons move through a metal wire, they collide with ions which get in their way As a result, they transfer some, or all, of their kinetic energy on collision, which causes electrical heating Free electrons collide with ions which resist their flow Since current is the flow of charge, the ions resisting their flow causes resistance Resistance depends on the length of the wire, the cross-sectional area through which the current is passing and the resistivity of the material Page 20 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources The resistivity equation shows that: The longer the wire, the greater its resistance The thicker the wire, the smaller its resistance Your notes The length and width of the wire affect its resistance Resistivity is a property that describes the extent to which a material opposes the flow of electric current through it It is a property of the material, and is dependent on temperature Resistivity is measured in Ω m Resistivity of some materials at room temperature Page 21 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes The higher the resistivity of a material, the higher its resistance This is why copper, with its relatively low resistivity at room temperature, is used for electrical wires — current flows through it very easily Insulators have such a high resistivity that virtually no current will flow through them Page 22 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Worked example Two electrically-conducting cylinders made from copper and aluminium respectively. Their dimensions are shown below. Copper resistivity = 1.7 × 10-8 Ω m Aluminium resistivity = 2.6 × 10-8 Ω m Which cylinder is the better conductor? Page 23 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Your notes Exam Tip You won’t need to memorise the value of the resistivity of any material, these will be given in the exam question. Remember if the cross-sectional area is a circle e.g. in a wire, it is proportional to the diameter squared. This means if the diameter doubles, the area quadruples (× 4) causing the resistance to drop by a quarter. Page 24 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Variation of the Resistivity of Metals and Semiconductors The resistivity of a material depends on its temperature How it varies depends on whether the material is a metal or a semiconductor Metals All solids are made up of vibrating atoms As the temperature rises, the ions vibrate with a greater frequency and amplitude Electric current is the flow of free electrons in a material The electrons collide with the vibrating atoms which impede their flow, hence the current decreases Metal atoms and free electrons at low and high temperatures So, if the current decreases, then the resistance will increase (from V = IR) Therefore, its resistivity will increase since ρ ∝ R (if the area A and length L is constant) For a metallic conductor which obeys Ohm's law: An increase in temperature causes an increase in resistance and resistivity A decrease in temperature causes a decrease in resistance and resistivity Page 25 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Semiconductors The resistivity of semiconductors behaves in the opposite way to metals The number density of charge carriers (such as electrons) increases with increasing temperature Therefore, for a semiconductor: An increase in temperature causes a decrease in resistance and resistivity A decrease in temperature causes an increase in resistance and resistivity One example of this is a thermistor This is often used in temperature sensing circuits such as thermometers and thermostats This is only for semiconductors with a negative temperature coefficient (NTC) Page 26 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources 4.2.6 Determining the Resistivity of a Metal Determining the Resistivity of a Metal Aims of the Experiment The aim of the experiment is to determine the resistivity of a 2 metre constantan wire Variables: Independent variable = Length, L, of the wire (m) Dependent variable = The current, I, through the wire (A) Control variables: Voltage through the wire The material the wire is made from Equipment List Resolution of measuring equipment: Metre ruler = 1 mm Micrometer screw gauge = 0.01 mm Page 27 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Voltmeter = 0.1 V Ammeter = 0.01 A Your notes Method 1. Measure the diameter of the constantan wire using a micrometer. The measurement should be taken between 5-10 times randomly along the wire. Calculate the mean diameter from these values 2. Set up the equipment so the wire is taped or clamped to the ruler with one end of the circuit attached to the wire where the ruler reads 0. The ammeter is connected in series and the voltmeter in parallel to the wire 3. Attach the flying lead to the test wire at 0.25 m and set the power supply at a voltage of 6.0 V. Check that this is the voltage through the wire on the voltmeter 4. Read and record the current from the ammeter, then switch off the current immediately after the reading (the short wire will get very hot) 5. Vary the distance between the fixed end of the wire and the flying lead in 0.25 m intervals (0.25 m, 0.50 m, 0.75 etc.) until the full length of the 2.0 m wire. The original length and the intervals can be changed (e.g. start at 0.1 m and increase in 0.1 m intervals), as long as there are 8-10 readings 6. Record the current for each length at least 3 times and calculate an average current, I 7. For each length, calculate the average resistance of the length of the wire using the equation Where V is the voltage and I is the average current through the wire for that length An example of a table of results might look like this: Page 28 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Analysis of Results The resistivity, ρ, of the wire is equal to Where: ρ = resistivity ( Ω m) R = resistance (Ω) A = cross-sectional area of the wire (m2 ) L = length of wire (m) Rearranging for the resistance, R: Comparing this to the equation of a straight line: y = mx y=R x=L Gradient = ρ / A The resistivity can therefore be calculated from the gradient of the resistance against length graph, multiplied by the cross-sectional area of the wire Page 29 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources 1. Calculate the cross-sectional area, A, of the wire Your notes 2. Plot a graph of the length of the wire, L, against the average resistance of the wire, R3. Draw a line of best fit and calculate the gradient of this graph4. Calculate the resistivity ρ by multiplying the gradient by the cross-sectional area A Evaluating the Experiment Systematic Errors: The end of the wire that is attached to the circuit (not the flying lead) must start at 0 on the ruler Otherwise, this could cause a z ero error in your measurements of the length Random Errors: Only allow small currents to flow through the wire The resistivity of a material depends on its temperature. The current flowing through the wire will cause its temperature to increase and affect its resistance and resistivity. Therefore the temperature is kept constant and low by small currents The current should be switched off between readings so its temperature doesn't change its resistance Page 30 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Make at least 5-10 measurements of the diameter of the wire with the micrometer screw gauge and calculate an average diameter to reduce random errors in the reading Safety Considerations When there is a high current, and a thin wire, the wire will become very hot Make sure never to touch the wire directly when the circuit is switched on Switch off the power supply right away if burning is smelled Make sure there are no liquids close to the equipment, as this could damage the electrical equipment Page 31 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Worked example A student wants to find the resistivity of a constantan wire. They set up the experiment by attaching one end of the wire to a circuit with a 6.0 V battery and the other with a flying lead and measure the length with a ruler.Attaching the flying lead onto the wire at different lengths, they obtain the following table of results: The following additional data for the wire is: Calculate the resistivity of the wire. Step 1: Complete the average current and resistance columns in the table The resistance is calculated using the equation Page 32 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Your notes Head to savemyexams.com for more awesome resources Your notes Step 2: Calculate the cross-sectional area of the wire from the diameter The average diameter is 0.191 mm = 0.191 × 10–3 m The cross-sectional area is equal to Step 3: Plot a graph of the length L against the resistance R Page 33 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Step 4: Calculate the gradient of the graph Page 34 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Step 5: Calculate the resistivity of the wire Page 35 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources 4.2.7 Thermistors Your notes Thermistors A thermistor is a non-ohmic conductor and sensory resistor whose resistance varies with temperature Most thermistors are negative temperature coefficient (ntc) components This means that if the temperature increases, the resistance of the thermistor decreases (and vice versa) The resistance through a thermistor is dependent on the temperature of it The temperature-resistance graph for a thermistor is shown below Page 36 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Your notes Graph of temperature against resistance for a thermistor Thermistors are temperature sensors and are used in circuits in ovens, fire alarms and digital thermometers As the thermistor gets hotter, its resistance decreases As the thermistor gets cooler, its resistance increases A digital thermometer uses a thermistor Page 37 of 38 © 2015-2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers Head to savemyexams.com for more awesome resources Worked example A thermistor is connected in series with a resistor R and a battery. The resistance of the thermistor is equal to the resistance of R at room temperature. When the temperature of the thermistor decreases, which statement is correct? A. The p.d across the thermistor increases B. The current in R increases C. The current through the thermistor decreases D. The p.d across R increases ANSWER: A The resistance of the thermistor increases as the temperature decreases Since the thermistor and resistor R are connected in series, the current I in both of them is the same Ohm’s law states that V = IR Since the resistance of the thermistor increases, and I is the same, the potential difference V across it increases Therefore, statement A is correct Exam Tip Make sure you remember the shape of the temperature-resistance graph for a thermistor, as it is a common exam question to draw and interpret this.The graph should not touch the x-axis, as this implies 0 resistance which is only possible in superconductors. 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OCR A Level Physics Resistance & Resistivity PDF

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