New Assiut University of Technology Physics Midterm Exam PDF 2024-2025

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New Assiut University of Technology

2024

New Assiut University of Technology

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This is a physics midterm exam from New Assiut University of Technology, Faculty of Industrial and Energy Technology, for the 1st semester of 2024-2025. The exam contains multiple-choice questions and short answer questions covering topics of physics like units, dimensions, pressure, conversions, mechanics (force, acceleration, momentum and kinetic friction, etc.).

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New Assiut University of Technology First Level Faculty of Industrial and Energy Technology Course: Physics Departments of Information Technology...

New Assiut University of Technology First Level Faculty of Industrial and Energy Technology Course: Physics Departments of Information Technology Midterm (30 degrees) st 1 Semester 2024-2025 Time: 60 min Date: 01/12/2024 Exam in Two Pages Name: Academic no: ------------------------------------------------------------------------------------------------------------------------------------------ Q1. Choose the correct answer (15 degrees- One degree each) 1) Which unit NOT belongs to International System (SI) of basic units. A. Kelvin B. Candela C. Newton D. Second 2) The dimension of pressure is …. (Pressure=Force/Area) A. M2 L T-1 B. M L3 T-1 C. M L-1 T-2 D. M2 L-1 T 3) Which of the following relation is correct? (where; 𝒙 is a length, 𝒂 is an accelaration and 𝒕 is time) 𝟏 𝟏 𝟏 A. 𝒙 = 𝟐 𝒂 𝒕𝟐 B. 𝒙 = 𝟐 𝒂 𝒕 C. 𝒙𝟐 = 𝟐 𝒂 𝒕𝟐 D. None of mentioned 4) Convert 0.65 cm3 to mm3 A. 650 mm3 B. 6.5 mm3 C. 0.0065 mm3 D. 0.00065 mm3 5) A car goes around a circuler curve at 20.0 m/s. If the radius of the curve is 50.0 m, what is the period time? A. 2.51 s B. 15.7 s C. 88 s D. 144 s 6) Calculate the mass of an atom of iron molar mass 𝑨𝑭𝒆 = 𝟓𝟓. 𝟗 𝒈𝒎/𝒎𝒐𝒍, 𝑵𝑨 = 𝟔. 𝟎𝟐 × 𝟏𝟎𝟐𝟑 𝒂𝒕𝒐𝒎/𝒎𝒐𝒍 A. 𝟒. 𝟓 × 𝟏𝟎−𝟐𝟑 𝒈𝒎 B. 𝟒. 𝟓 × 𝟏𝟎𝟐𝟑 𝒈𝒎 C. 𝟗. 𝟑 × 𝟏𝟎−𝟐𝟑 𝒈𝒎 D. 𝟗. 𝟑 × 𝟏𝟎𝟐𝟑 𝒈𝒎 7) The action force is …. in magnitude to the reaction force and …. in direction A. equal - same B. double - same C. equal - opposite D. double - opposite 8) The acceleration of an object is directly proportional to the …. acting on it and inversely proportional to its …. A. net force - mass B. mass - net force C. velocity – displacement D. displacement - velocity 9) A horse runs a distance of 10 kilometers in 30 minutes. Its average speed is: A. 20 km/h B. 30 km/h C. 15 km/h D. 0.3 km/h 10) Which of following is a vector quantity? A. Speed B. Mass C. Temperature D. Force 11) A jumper leaves the ground at an angle of 20.0° above the horizontal and at a speed of 11.0m/s. How far does he jump in the horizontal direction (Range)? (g=9.8 m/s2) A. 0.722 m B. 7.39 m C. 13.2 m D. 39.2 m/ 12) The force of friction is in the same direction as the object motion. A. True | B. False 13) The object accelerates only if the net force acting on it is equal to zero. A. True | B. False 14) The attractive force exerted by the Earth on an object is called the gravitational force. A. True | B. False 15) When no force acts on an object, the acceleration of the object is zero. A. True | B. False Put your answers on this table. 1) 2) 3) 4) 5) C C A A B 6) 7) 8) 9) 10) C C A A D 11) 12) 13) 14) 15) B B B A A 1|2 Q2. Answer the following questions (15 degrees – 5 degrees each) 1- Given the vectors ⃗𝑨 = 𝟒. 𝟎𝟎 𝒊̂ + 𝟔 𝒋̂ and𝑩 ⃗⃗ = −𝟐 𝒊̂ + 𝟖 𝒋̂, the vector difference ⃗𝑫 ⃗ = ⃗𝑨 - ⃗𝑩 ⃗. Calculate ⃗⃗ of unit vectors and then in terms of magnitude and angle. 𝑫 𝐶 = 𝐴 − 𝐵 𝐶 = 4 𝑖 + 6 𝑗 − (− 2 𝑖 + 8 𝑗) = 4 𝑖 + 6 𝑗 + 2 𝑖 − 8 𝑗 ⇒ 𝐶 = 6 𝑖 − 2 𝑗 Then the magnitude is |𝐶| = √62 + 22 = √36 + 4 = 6.325 The direction is −2 𝜃𝐶 = 𝑡𝑎𝑛−1 ( ) = −18.4° + 360° = 341.57° 6 2- A hockey puck on a frozen bond is hit and given an initial speed of 30.0 m/s. If the puck always remains on the ice and slides 145 m before coming to rest, determine the coefficient of kinetic friction between the puck and the ice. 𝑓𝑘 = −𝑚𝑎𝑥 = 𝜇𝑘 𝑛 𝑎𝑛𝑑 𝑛 = 𝑚𝑔 −𝑚𝑎𝑥 = 𝜇𝑘 𝑚𝑔 ⇒ 𝑎𝑥 = −𝜇𝑘 𝑔 From kinematics equations 𝑣𝑓2 = 𝑣𝑖2 + 2𝑎𝑥 (𝑥𝑓 − 𝑥𝑖 ) 02 = 302 + 2𝑎𝑥 (145) 900 𝑎𝑥 = − = −3.1 𝑚/𝑠 2 290 3.1 −𝜇𝑘 𝑔 = −3.1 ⇒ 𝜇𝑘 = = 0.317 9.8 3- Determine the magnitude of the acceleration of the two masses m1 = 2 kg, m2 = 4 kg and the tension in the string of the Atwood's machine? (𝑚2 − 𝑚1 ) 4−2 𝑎𝑦 = 𝑔= × 9.8 = 3.27 𝑚/𝑠 2 (𝑚1 + 𝑚2 ) 2+4 2𝑚1 𝑚2 2×2×4 𝑇= 𝑔= × 9.8 = 26.1 𝑁 (𝑚1 + 𝑚2 ) 2+4 End of Questions Good Luck Dr. Hadeer El-Hawary 2|2

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