Percentage MCQ Objective Questions PDF

# Latest Percentage MCQ Objective Questions ## Question 1: A cricketer scored 1200 runs in a season and had a strike rate of 150%. If the total balls faced were 800, what percentage of his total runs were scored in boundaries (assuming each boundary scores 4 runs and he hit 50 boundaries)? 1. 33....

# Latest Percentage MCQ Objective Questions ## Question 1: A cricketer scored 1200 runs in a season and had a strike rate of 150%. If the total balls faced were 800, what percentage of his total runs were scored in boundaries (assuming each boundary scores 4 runs and he hit 50 boundaries)? 1. 33.33% 2. 20% 3. 25% 4. More than one of the above 5. None of the above **Answer:** None of the above **Detailed Solution:** Total runs scored: 1200 Strike rate: 150% Total balls faced: 800 Number of boundaries: 50 Runs per boundary: 4 To find the percentage of runs scored through boundaries, calculate the total runs from boundaries and then find what percentage this is of the total runs scored. **Calculation:** Total runs from boundaries 50 boundaries × 4 runs/boundary = 200 runs Percentage of runs from boundaries (Total runs from boundaries ÷ Total runs scored) × 100 ⇒ (200 runs ÷ 1200 runs) × 100 = 16.67% .. The percentage of his total runs scored in boundaries is 16.67%. ## Question 2: A bulb manufacturer found that 19% of the total product is faulty. If the number of lossless products is 2349 then find out the number of defective products. 1. 552 2. 554 3. 553 4. More than one of the above 5. None of the above **Answer:** None of the above **Detailed Solution:** Number of lossless products = 2349 Percentage of faulty products = 19% **Formula Used:** Number of total products = Number of lossless products / (1 - Percentage of faulty products) Number of defective products = Total products – Number of lossless products **Calculation:** Let the total number of products be x. x × (1 - 19%) = 2349 x = 2349 / 0.81 ⇒ x = 2900 (Total number of products) Number of defective products = 2900 - 2349 → Number of defective products = 551 The number of defective products is 551. ## Question 3: Three friends A, B, and C purchased land at the cost of Rs. 100000. The share of A and B is 300% of C, and the share of B and C is 200% of A + 5000. Find the total share of A and C. 1. 60000 2. 75000 3. 55000 4. 65000 5. 70000 **Answer:** 55000 **Detailed Solution:** Let's denote the shares of A, B, and C as A, B, and C respectively. The share of A and B is 300% of C: A + B = 3C (1) The share of B and C is 200% of (A + 5000): B + C = 2(A + 5000) = 2Α + 10000 B + C = 2Α + 10000 (2) The total cost of the land is Rs. 100000: Α + Β + C = 100000 (3) Let's express B in terms of A and C using equation 1: Β = 3C - Α Substitute B into equation 2: (3C - A) + C = 2A + 10000 4C - A = 2A + 10000 4C = 3A + 10000 C = (3A + 10000) / 4 Substitute B and C into equation 3: A + (3C - A) + C = 100000 4C = 100000 C = 25000 Substitute C = 25000 into the expression for Β: Β = 3C - A Β = 3(25000) - A Β = 75000 - A Substitute C = 25000 into the expression for C: C = (3A + 10000) / 4 = 25000 3A + 10000 = 100000 3A = 90000 A = 30000 Calculate B using A: B = 75000 - 30000 B = 45000 Check if the total equals Rs. 100000: A + B + C = 30000 + 45000 + 25000 = 100000 Thus, the shares are: A = 30000 C = 25000 The total share of A and C = 30000 + 25000 = Rs. 55000. ## Question 4: A has 20% more money than B, and C has 20% less money than B. What percent more money does A have than C? 1. 30 2. 50 3. 17 4. More than one of the above 5. None of the above **Answer:** 50 **Detailed Solution:** Money of 'A' = 20% more than Money of B and Money of 'C' = 20% less than Money of B. **Concept Used:** Percentage: A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the per cent sign, '%'. If P is x per cent more than Q, then P = Q{1 + (x/100)} If P is x per cent less than Q, then P = Q{1 - (x/100)} Percentage of P more than Q = {(P - Q)/Q} × 100% **Calculation:** Let, B have x money, then according to the question, Money of 'A' = 20% than Money of B A = B{1 + (20/100)} A = (6/5) × B --(1) Money of 'C' = 20% less than Money of B, i.e C = B{1 - (20/100)} C = (4/5) × B .....(2) So, the amount of money of A, more than C will be A - C = (6/5 - 4/5) × B A - C = (2/5) × B Percentage of money, A has more than C {(A - C)/C} x 100% {(2/5) × B}/{(4/5) x B} x 100% = (1/2) × 100% = 50% .. A has 50% more money than C. **Alternate Method** Let, B has 100 rupees Then, according to the question, Money of A = 120 rupees, and Money of C = 80 rupees Therefore, the difference in money between A and C 40 rupees Percentage of money, A have more than C = {(A - C)/C} x 100% ⇒ (40/80) × 100% = (1/2) × 100% = 50% .. A has 50% more money than C. ## Question 5: If a plate contains 20 eggs and 5 of them have gone bad, what is the percentage of the remaining good eggs? 1. 35% 2. 75% 3. 95% 4. More than one of the above 5. None of the above **Answer:** 75% **Detailed Solution:** Total eggs = 20 & Bad eggs = 5 Therefore, good eggs = Total eggs - Bad eggs = 20 - 5 = 15 To find the percentage of good eggs out of the total: Percentage of good eggs = (Good eggs / Total eggs) × 100 Percentage of good eggs = (15/20) × 100 Percentage of good eggs = 0.75 x 100 Percentage of good eggs = 75% So, the percentage of the remaining good eggs is 75%. ## Question 6: In an election between two candidates, the winning candidate got 70 percent votes of the valid votes and he won by a majority of 3630 votes. If out of total votes polled 75 percent votes are valid, then what is the total number of votes polled? 1. 15200 2. 13000 3. 16350 4. 12100 **Answer:** 12100 **Detailed Solution:** Valid votes = 75% of total votes Winning Candidate = 70% of Valid votes He won by a majority of 3630 votes Losing Candidate = 30% of Valid votes **Calculation:** Let 100x be the total number of votes polled Valid votes = 75% of total votes = 0.75 × 100x = 75x Majority of the Winning Candidate is 3630 Then, Difference between Winning and Losing Candidate = (70 % - 30%) of valid votes = 40% of the valid votes Valid Votes = 75x Then, = 0.40 × 75x = 30x Hence, 30х is Majority of winning candidate 30х = 3630 x = 121 Total number of votes is 100х = 100 × 121 = 12100 Answer is 12100. ## Question 7: If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre, by how much percent a person has to decrease his consumption so that his expenditure remains same. 1. 66.67% 2. 40% 3. 33.33% 4. 45% 5. None of these **Answer:** 33.33% **Detailed Solution:** GIVEN : If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre **CALCULATION:** Let the consumption be 100 litres. When price is Rs. 40 per litres, then, the expenditure = 100 × 40 = Rs. 4,000. At Rs. 60 per litre, the 60 × consumption = 4000 Consumption = 4,000/60 = 66.67 litres. .. Required decreased % = 100 - 66.67 = 33.33% ## Question 8: A fruit seller sells 45% of the oranges that he has along with one more orange to a customer. He then sells 20% of the remaining oranges and 2 more oranges to a second customer. He then sells 90% of the now remaining oranges to a third customer and is still left with 5 oranges. How many oranges did the fruit seller have initially? 1. 121 2. 111 3. 100 4. 120 **Answer:** 120 **Detailed Solution:** Let the initial oranges with the fruit seller be x. 1st selling = 0.45x + 1 Remaining = x - (0.45x + 1) = 0.55x - 1 2nd selling = 1/5 × (0.55x - 1) = 0.11x - 0.2 + 2 = 0.11x + 1.8 Remaining after second selling = 0.55x - 1 - (0.11x + 1.8) = 0.55x - 0.11x - 1 - 1.8 = 0.44x - 2.8 3rd selling = 90% × (0.44x - 2.8) Remaining after 3rd selling = 0.1 × (0.44x - 2.8) = 0.044x - 0.28 According to the question 0.044x - 0.28 = 5 0.044x = 5.28 x = 5.28 / 0.044 = 120 .. The number of oranges was 120. **Alternate Method ** At last, he sells 90% of the remaining oranges after selling the oranges to a second customer, then he has 10% of the remaining oranges. 10% of the remaining oranges after selling the oranges to the second customer = 5 So remaining oranges after selling the oranges to the second customer = 100% of the remaining oranges after selling the oranges to the second customer = 50 oranges He gave 2 extra oranges to the second customer, so the remaining oranges = 50 + 2 = 52 He sells 20% of the remaining oranges to the second customer, so he has 80% of the remaining oranges = 52 100% of remaining oranges after selling the oranges to the first customer = (52/4) * 5 = 65 oranges He gave 1 extra orange to the first customer, so the total oranges after selling 45% of the oranges = 65 + 1 = 66 oranges (100%-45% = 55%) of total oranges = 66 SO 100% of oranges = (66/55) * 100 = 120 oranges ## Question 9: The price of wheat is reduced by 4%. How many more or less kg of wheat can now be bought for the money which was sufficient to buy 48 kg wheat earlier? 1. 1 kg less 2. 1 kg more 3. 2 kg more 4. 2 kg less 5. None of these **Answer:** 2 kg more **Detailed Solution:** GIVEN : The price of wheat is reduced by 4%. **ASSUMPTION:** Let the price of wheat be Rs.100/kg. **CALCULATION:** The price of 48 kg wheat = 4800 As price is reduce by 4% it means that it became 96% of initial 100% hence, After price decrease = 4800/96 = 50 kg Hence, the required quantity of wheat = (50 - 48) = 2 kg more. ## Question 10: If the average of a number, 50% of that number and 25% of the same number is 280, then the number is 1. 280 2. 480 3. 360 4. None of the above **Answer:** 480 **Detailed Solution:** Average is 280. **Formula used:** Average = sum of the observation/number of the observation **Calculation:** Let the number be x According to the question, (x + 50% of x + 25% of x)/3 = 280 (x + x/2 + x/4)/3 = 280 7x/12 = 280 ⇒ x = 480 .. The number is 480. ## Question 11: The price of an umbrella decreased by 20%. As a result of which the sale increased by 40%. What will be the net effect on the total revenue of the shop? 1. 12% decrease 2. 15% increase 3. 20% decrease 4. 12% increase 5. 18% decrease **Answer:** 12% increase **Detailed Solution:** The price of an umbrella decreased by 20%. [20% can be written as 1/5] Let the initial price be = 5x. After 20% decrease = 4x Sales is increase by 40% [40% can be written as 2/5] Let the initial sale be = 5x After 40% increase = 7x The ratio of the cost price and selling price = 25x:28x = 25:28 The net effect on revenue [net profit%] = (28 - 25) × 100 / 25 = 12% increase. Hence, the correct answer is 12% increase. ## Question 12: Two students appeared for an examination. One of them secured 22 marks more than the other and his marks were 55% of the sum of their marks. The marks obtained by them are 1. 121 and 99 2. 43 and 21 3. 58 and 36 4. 86 and 64 **Answer:** 121 and 99 **Detailed Solution:** Let the students be A and B Let the marks secured by B = x Marks secured by A = x + 22 Sum of their marks of A & B = x + x + 22 = 2x + 22 Accoring to question, Marks of A = 55% of the sum of marks x + 22 = 0.55 × (2x + 22) x + 22 = 1.1x + 12.1 0.1x = 9.9 x = 9.9/0.1 = 99 marks Marks secured by A = 99 + 22 = 121 marks Therefore the correct answer is 121. **Shortcut Trick** Let us go by options. The difference between the numbers is 22 in all cases. So, now check the next statement. 121 = 0.55 × (121 + 99) That is, as the first option itself satisfies the condition and since we do no have a combination of answers, it is the solution. .. The required numbers are 121 and 99. ## Question 13: There were two candidates in an election, 10% of voters did not vote and 48 votes were found invalid. The winning candidate got 53% of all the voters in the list and won by 304 votes. Find the total number of votes enrolled. 1. 1600 2. 1230 3. 4561 4. 1653 **Answer:** 1600 **Detailed Solution:** There were two candidates in an election, 10% of voters did not vote and 48 votes were found invalid. The winning candidate got 53% of the total votes and won by 304 votes. **Concept used:** Percentage **Calculation:** Let the total number of voters be 100x 10% of voters did not vote Number of voters who vote = 100x - 10x = 90x 48 votes were found invalid Valid votes - 90x - 48 Votes gained by the winning candidate = 53/100 × 100x = 53x Votes gained by the loosing candidate = 90x - 48 - 53x = 37x - 48 As per the question, 53x - (37x - 48) = 304 16x = 304 - 48 16x = 256 ⇒ x = 16 .. Total number of voters = 100x = 1600 **Alternate Method** Let total number of votes be 100 units, 10% voters did not cast their vote ⇒ Votes polled = 90 units The winning candidate got 53% of all the voters in the list and won by 304 votes, Winning candidate got = 53 units votes Other candidate got = 37 units votes Difference in votes = 53 units votes - 37 units votes = 304 - 48 =256 votes ⇒16 units = 256 .. 100 units votes = 256/16 x 100 = 1600 votes .. Total number of voters = 1600. ## Question 14: Out of two numbers, 65% of the smaller number is equal to 45% of the larger number. If the sum of two numbers is 2574, then what is the value of the larger number? 1. 1521 2. 1471 3. 1641 4. 1419 **Answer:** 1521 **Detailed Solution:** Out of two numbers, 65% of the smaller number is equal to 45% of the larger number. If the sum of two numbers is 2574 **Calculation:** Let the smaller number be 'x' and the larger number be 'y' From the problem, it is given that 65%x = 45%y ⇒ 13x = 9y ⇒ x = (9/13)y ----(1) Given the sum of the numbers = 2574 ⇒ (x + y) = 2574 ----(2) Substituting the value of 'x' from Equation 1 in Equation 2, we get (9/13)y + y = 2574 (9y + 13y) = 2574 × 13 22y = (2574 × 13) y = (2574 × 13)/22 = 1521 .. Value of the larger number is 1521 ## Question 15: 800 g of sugar solution has 40% sugar in it. How much sugar should be added to make its proportion at 60% in the solution? 1. 320 g 2. 380 g 3. 400 g 4. 420 g **Answer:** 400 g **Detailed Solution:** Quantity of sugar in solution = 800 × (40/100) = 320 gm Let the quantity of sugar added be x gm. According to the question (320 + x)/(800 + x) = 60/100 (320 + x)/(800 + x) = 3/5 ⇒ (320 + x) × 5 = 3 × (800 + x) 1600 + 5x = 2400 + 3x 5x - 3x = 2400 - 1600 ⇒ x = 400 gm **Shortcut Trick** |40% | 60% | 100% | |-------|--------|-------| |40:20 | 2:1 | | 2 unit = 800 g 1 unit = 400 g