Loading...
Loading...
Loading...
Loading...
Loading...
Loading...
Loading...

Transcript

## Isotopes of H * **1 H *(hydrogen)* ** * p = 1 * n = 0 * e = 1 * ** 2 H *(deuterium)* ** * p = 1 * n = 1 * e = 1 * ** 3 H *(tritium)* ** * p = 1 * n = 2 * e = 1 * ** Isotopes effect = 1/1 + 1/2 + 1/3** * ** ¹H only element which don't have neutrons** ### Aver...

## Isotopes of H * **1 H *(hydrogen)* ** * p = 1 * n = 0 * e = 1 * ** 2 H *(deuterium)* ** * p = 1 * n = 1 * e = 1 * ** 3 H *(tritium)* ** * p = 1 * n = 2 * e = 1 * ** Isotopes effect = 1/1 + 1/2 + 1/3** * ** ¹H only element which don't have neutrons** ### Average atomic mass * Defines for isotopes * Depends on % abundance relative * Average abundance of isotopes in universe * Atomic mass of an element = (Sumation) & isotopic mass X abundance/100 * It can be fractional ### Q. B has two isotopes ¹⁰B * (19%)* and ¹¹B * (81%)*. The atomic mass of B is. * ¹⁰B & ¹¹B * Avg atomic mass[B] = 10 x 19 + 11 x 81 = 190+891/100 = 10.81 ans ## Isoelectronic * **Same no. of electrons.** * **e.g. 8+2+3** ## Atomic * **Ek atom ka nikalna hai** * **(of the element)** * **Atomic mass 19 or 1** ### → I am uor * 10 ## Molecular * Sum ### Mole * Moles X Molar mass ### Molar * 100

Tags

isotopes chemistry atomic mass
Use Quizgecko on...
Browser
Browser