Write an exponential function that has a y-intercept of -4 and passes through the points (1, -1.6) and (2, -0.64).

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Understand the Problem

The question is asking to formulate an exponential function that has a specific y-intercept and meets two given points. This involves applying the general form of exponential functions and solving for the parameters.

Answer

The exponential function is $f(x) = -4(0.4)^x$.
Answer for screen readers

The exponential function is given by: $$ f(x) = -4(0.4)^x $$

Steps to Solve

  1. Define the exponential function

The general form of an exponential function is given by: $$ f(x) = ab^x $$ where $a$ is the y-intercept and $b$ is the base. In this case, since the y-intercept is $-4$, we have: $$ f(x) = -4b^x $$

  1. Plug in the first point (1, -1.6)

Using the point $(1, -1.6)$, plug in $x = 1$ and $f(x) = -1.6$ into the function: $$ -1.6 = -4b^1 $$ This simplifies to: $$ -1.6 = -4b $$ Now, solve for $b$: $$ b = \frac{-1.6}{-4} = 0.4 $$

  1. Plug in the second point (2, -0.64)

Now use the second point $(2, -0.64)$, substituting $x = 2$ and $f(x) = -0.64$ into the function: $$ -0.64 = -4b^2 $$ We now substitute $b = 0.4$ into the equation: $$ -0.64 = -4(0.4)^2 $$ Calculate $(0.4)^2$: $$ (0.4)^2 = 0.16 $$ Now substitute this back: $$ -0.64 = -4(0.16) $$ This simplifies to: $$ -0.64 = -0.64 $$ Since this is a true statement, the value of $b$ is consistent.

  1. Write the final function

Now that we have found both $a$ and $b$, we can write the final exponential function: $$ f(x) = -4(0.4)^x $$

The exponential function is given by: $$ f(x) = -4(0.4)^x $$

More Information

This exponential function indicates that it has a y-intercept at $-4$ and passes through the points $(1, -1.6)$ and $(2, -0.64)$. The function will decrease as $x$ increases, consistent with the negative y-intercept.

Tips

  • Ignoring the y-intercept: Ensure you correctly use the y-intercept when defining the function.
  • Mistakes in substitution or calculations: Always double-check your arithmetic when plugging in coordinates and calculating the base.

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