Which of the following initial values of the variable y would result in the variable z being set to 2 after the code segment is executed?
Understand the Problem
The question is asking which initial value of the variable y, when used in the given code segment, will result in the variable z being set to 2 after the segment executes. The code performs a modulus operation, so we need to find values of y that satisfy the equation 23 MOD y = 2.
Answer
$y = 3$
Answer for screen readers
The initial value of the variable $y$ that results in the variable $z$ being set to $2$ after the code segment is executed is $y = 3$.
Steps to Solve
- Understand the Modulus Operation
The modulus operation $z = x \mod y$ gives the remainder when $x$ is divided by $y$. We need to find values of $y$ such that when $23$ is divided by $y$, the remainder is $2$.
- Set Up the Equation
From the problem, we can set up the equation: $$ 23 \mod y = 2 $$
This means that the expression $23 - 2$ needs to be divisible by $y$.
- Calculate the Divisor
Rearranging the equation gives: $$ 21 = 23 - 2 $$
So, we need to find values of $y$ that divide $21$. The possible values of $y$ are the divisors of $21$.
- Identify Divisors of 21
The divisors of $21$ are $1$, $3$, $7$, and $21$. We'll also check which of these, when substituted into $x \mod y$, results in $z = 2$:
- For $y = 1$: $23 \mod 1 = 0$ (not valid)
- For $y = 3$: $23 \mod 3 = 2$ (valid)
- For $y = 7$: $23 \mod 7 = 2$ (valid)
- For $y = 21$: $23 \mod 21 = 2$ (valid)
- Select from Given Options
The problem gives us the following options for $y$:
- A. 1
- B. 2
- C. 3
- D. 4
From our identified values, only $y = 3$ meets the requirement from the options.
The initial value of the variable $y$ that results in the variable $z$ being set to $2$ after the code segment is executed is $y = 3$.
More Information
This problem involves understanding the modulus operation. The key point is identifying divisors of the adjusted number to yield the desired remainder.
Tips
- Confusing the modulus operation, thinking it gives the quotient instead of the remainder.
- Not considering all divisors of the calculated number (in this case, $21$).
AI-generated content may contain errors. Please verify critical information