What is the width of a rectangle with an area of 4 4/5 square yards and a length of 1 4/5 yards?
Understand the Problem
The question is asking for the width of a rectangle, given the area and one of the dimensions. We need to determine the missing dimension based on the provided area and the length.
Answer
The width is $2 \frac{2}{3}$ yards.
Answer for screen readers
The width of the rectangle is ( 2 \frac{2}{3} ) yards.
Steps to Solve
- Convert Mixed Numbers to Improper Fractions
First, we need to convert the mixed numbers into improper fractions for easier calculations.
The area ( 4 \frac{4}{5} = \frac{24}{5} ) (since ( 4 \times 5 + 4 = 24 )).
The length ( 1 \frac{4}{5} = \frac{9}{5} ) (since ( 1 \times 5 + 4 = 9 )).
- Using Area Formula to Find Width
The area ( A ) of a rectangle is given by the formula:
$$ A = \text{length} \times \text{width} $$
We can rearrange this to find the width (( w )):
$$ w = \frac{A}{\text{length}} $$
Substituting the values we have:
$$ w = \frac{\frac{24}{5}}{\frac{9}{5}} $$
- Simplifying the Width Calculation
To simplify the fraction, we multiply by the reciprocal of the denominator:
$$ w = \frac{24}{5} \times \frac{5}{9} $$
- Final Calculation for Width
The ( 5 ) in the numerator and denominator cancel:
$$ w = \frac{24}{9} $$
Now simplify this fraction:
$$ w = \frac{8}{3} $$
- Convert Back to Mixed Number
To convert ( \frac{8}{3} ) back to a mixed number:
$$ 8 \div 3 = 2 \text{ R } 2 $$
So, ( \frac{8}{3} = 2 \frac{2}{3} ).
The width of the rectangle is ( 2 \frac{2}{3} ) yards.
More Information
The area of a rectangle is calculated using the length and width. By knowing either dimension along with the area, one can easily find the missing dimension using basic algebraic manipulation.
Tips
- Confusing mixed numbers and improper fractions can lead to errors. Always convert to improper fractions before calculations.
- Forgetting to multiply by the reciprocal when dividing fractions.
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