What is the standard form of a circle's equation?

Understand the Problem

The question is asking for the standard form of a circle's equation, which is a fundamental concept in geometry related to the relationship between a circle's center and radius.

Answer

The standard form of a circle's equation is $ (x - h)^2 + (y - k)^2 = r^2 $.
Answer for screen readers

The standard form of a circle's equation is given by:
$$(x - h)^2 + (y - k)^2 = r^2$$

Steps to Solve

  1. Identify the circle's center and radius
    You need to determine the center of the circle and the radius. In the standard form of a circle's equation, which is given by:
    $$ (x - h)^2 + (y - k)^2 = r^2 $$
    Here, $(h, k)$ is the center and $r$ is the radius.

  2. Substitute the values into the formula
    Replace $h$, $k$, and $r$ in the standard form equation with the respective values. For example, if the center is at $(3, -2)$ and the radius is $5$, the equation would become:
    $$ (x - 3)^2 + (y + 2)^2 = 5^2 $$

  3. Simplify the equation
    Finally, calculate $r^2$ and simplify the equation. Continuing the example:
    $$ (x - 3)^2 + (y + 2)^2 = 25 $$

The standard form of a circle's equation is given by:
$$(x - h)^2 + (y - k)^2 = r^2$$

More Information

The standard form of a circle's equation is very useful in geometry and analytic geometry. It helps you determine critical properties of the circle such as its center and radius quickly.

Tips

  • Misidentifying the center: Make sure to correctly identify $(h, k)$ from the coordinates provided.
  • Incorrectly calculating $r^2$: Always square the radius correctly. For example, if the radius is 4, $r^2$ must be 16, not 12 or any other number.

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