What is the magnitude of the force experienced by a charge of 1.0 nC placed at B?
Understand the Problem
The question is asking for the calculation of the electric force experienced by a charge placed in an electric field. Given the electric field strength and the charge's value, we will use Coulomb's law to find the force. The relation involved is F = qE, where 'F' is the force, 'q' is the charge, and 'E' is the electric field strength.
Answer
The magnitude of the force is \( 3.3 \times 10^{-6} \, \text{N} \).
Answer for screen readers
The magnitude of the force is ( 3.3 \times 10^{-6} , \text{N} ).
Steps to Solve
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Identify the Given Values
The electric field strength ( E = 3,300 , \text{N/C} ) and charge ( q = 1.0 , \text{nC} = 1.0 \times 10^{-9} , \text{C} ). -
Use Coulomb's Law
The formula to calculate the electric force ( F ) is given by
$$ F = qE $$ -
Substitute the Values
Plugging in the values:
$$ F = (1.0 \times 10^{-9} , \text{C})(3,300 , \text{N/C}) $$ -
Calculate the Force
Perform the multiplication:
$$ F = 3.3 \times 10^{-6} , \text{N} $$ -
Format the Answer
To express it in the desired format:
The magnitude of the force is ( 3.3 \times 10^{-6} , \text{N} ).
The magnitude of the force is ( 3.3 \times 10^{-6} , \text{N} ).
More Information
This calculation illustrates the direct relationship between electric field strength and electric force acting on a charge. The electric field exerts a force proportional to the size of the charge placed in it.
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