What is the equilibrium constant (Kc) value for the reaction of H2, I2, and HI at 400°C?
Understand the Problem
The question is asking for the specific value of the equilibrium constant (Kc) for a chemical reaction involving hydrogen (H2), iodine (I2), and hydrogen iodide (HI) at a given temperature (400°C). This requires knowledge of chemical equilibrium and possibly looking up data from a chemistry resource.
Answer
Kc = 54.3
The equilibrium constant (Kc) value for the reaction H2(g) + I2(g) ⇔ 2HI(g) at 400°C is 54.3.
Answer for screen readers
The equilibrium constant (Kc) value for the reaction H2(g) + I2(g) ⇔ 2HI(g) at 400°C is 54.3.
More Information
The value of the equilibrium constant for a reaction depends on temperature. Therefore, it is crucial to specify the temperature when discussing Kc values.
Tips
A common mistake is missing the importance of stating the temperature at which the equilibrium constant is calculated, as Kc varies with temperature.
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