What is the distance covered by the object at the time between 0s to 2s? During which interval(s) is the object moving in the negative x direction? What is the velocity of the car... What is the distance covered by the object at the time between 0s to 2s? During which interval(s) is the object moving in the negative x direction? What is the velocity of the car from times 5-10s?
Understand the Problem
The question is asking for the interpretation of graphical data from a position-time graph. It requires determining the distance covered by an object, identifying intervals of negative movement, and calculating velocity over a specific time frame.
Answer
8m; 5-10s; -1 m/s
The distance covered by the object from 0s to 2s is 8m. The object moves in the negative x direction during 5s to 10s. The velocity from 5s to 10s is -1 m/s.
Answer for screen readers
The distance covered by the object from 0s to 2s is 8m. The object moves in the negative x direction during 5s to 10s. The velocity from 5s to 10s is -1 m/s.
More Information
The position from 0s to 2s changes from 0m to 8m, indicating the distance covered. The slope is negative from 5s to 10s, showing movement in the negative x direction with a velocity of -(9-8)/(10-5) = -1 m/s.
Tips
A common mistake is confusing distance with displacement. Always calculate the absolute change in position for distance.
