What does this expression evaluate to? (define x (length (range 3000)))
Understand the Problem
The question is asking us to evaluate a Lisp expression that defines a variable x to be the length of a range from 0 to 2999. The goal is to determine the numerical value of x after evaluating the expression.
Answer
The expression evaluates to \( x = 3000 \).
Answer for screen readers
The expression evaluates to ( x = 3000 ).
Steps to Solve
-
Understanding the
rangeFunction
The range function generates a sequence of numbers from 0 up to (but not including) the specified number. In this case, range(3000) generates numbers from 0 to 2999.
- Calculating the Length of the Range
Next, we need to determine the length of the list created by range(3000). The sequence starts at 0 and ends at 2999. Thus, the number of elements is:
$$ \text{Length} = 2999 - 0 + 1 = 3000 $$
- Defining the Value of x
According to the expression, we now define the variable (x) that holds the length calculated:
$$ x = 3000 $$
The expression evaluates to ( x = 3000 ).
More Information
The range function in Lisp generates a list of numbers, and its length can be determined by simple arithmetic. In this case, range(3000) produces a list of 3000 elements, where (x) is defined to store this length.
Tips
- Mistaking the upper limit: Some might miscount the values in the range, forgetting that the upper limit is not included.
- Off-by-one errors: It's important to remember that if the range starts from 0, the count includes that number.
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