The order of bases on a segment of DNA is represented by C-A-C-T-G-A. What would be the end result of transcription for this sequence? RNA structure is different from DNA structure... The order of bases on a segment of DNA is represented by C-A-C-T-G-A. What would be the end result of transcription for this sequence? RNA structure is different from DNA structure because only RNA has which of the following? Which statement describes the offspring that would result if individual 1 has children with a woman that does not carry the allele for this disorder?

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Understand the Problem

The questions in the image are related to DNA transcription and the differences between DNA and RNA structures, as well as inheritance in genetics. They require knowledge of base pairing in DNA and RNA, as well as understanding genetic inheritance patterns.

Answer

G-U-G-A-C-U; RNA has ribose sugar; none of the daughters would be affected.

The transcription of the DNA sequence C-A-C-T-G-A into RNA results in G-U-G-A-C-U. Only RNA contains ribose sugars, differing it from DNA which contains deoxyribose. The offspring of individual 1 with a non-carrier woman would have none of the daughters affected by the disorder.

Answer for screen readers

The transcription of the DNA sequence C-A-C-T-G-A into RNA results in G-U-G-A-C-U. Only RNA contains ribose sugars, differing it from DNA which contains deoxyribose. The offspring of individual 1 with a non-carrier woman would have none of the daughters affected by the disorder.

More Information

During transcription, uracil replaces thymine in RNA, resulting in a complementary RNA strand. The use of ribose sugar is a key difference between RNA and DNA.

Tips

A common mistake is mixing up base pairing rules, especially remembering that adenine pairs with uracil in RNA instead of thymine.

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