The number of moles of solute present in 2.0 L of 1 M NaOH is;
Understand the Problem
The question is asking for the calculation of the number of moles of solute (NaOH) in 2.0 L of a 1 M solution. To find this, we can use the formula: moles = molarity × volume.
Answer
The number of moles of solute present in 2.0 L of 1 M NaOH is $2$ moles.
Answer for screen readers
The number of moles of solute present in 2.0 L of 1 M NaOH is $2$ moles.
Steps to Solve
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Identify the formula for moles To find the number of moles of solute, we use the formula: $$ \text{moles} = \text{molarity} \times \text{volume} $$
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Substitute the given values Here, the molarity is 1 M (moles per liter) and the volume is 2.0 L. Substituting these values into the equation: $$ \text{moles} = 1, \text{M} \times 2.0, \text{L} $$
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Calculate the number of moles Perform the multiplication: $$ \text{moles} = 1 \times 2.0 = 2, \text{moles} $$
The number of moles of solute present in 2.0 L of 1 M NaOH is $2$ moles.
More Information
In a 1 M solution, there is 1 mole of solute (NaOH) in 1 liter of solution. Therefore, in 2 liters, the amount doubles to 2 moles. This concept is fundamental in chemistry for preparing solutions.
Tips
Common mistakes include:
- Confusing molarity with other concentration units like molality.
- Not using the correct units for volume (liters).
- Miscalculating the multiplication of molarity and volume.
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