The carbon chain of fatty acids is shortened by 2 carbon atoms at a time. This involves successive reactions catalyzed by 4 enzymes. These act in the following order: A. Acetyl CoA... The carbon chain of fatty acids is shortened by 2 carbon atoms at a time. This involves successive reactions catalyzed by 4 enzymes. These act in the following order: A. Acetyl CoA dehydrogenase, OH acyl CoA dehydrogenase, enoyl hydratase, thiolase B. Acyl CoA dehydrogenase, thiolase, enoyl hydratase, OH acyl CoA dehydrogenase C. Acyl CoA dehydrogenase, thiolose, enoyl hydratase, OH acyl CoA dehydrogenase D. Enoyl hydratase, OH acyl CoA dehydrogenase, acyl CoA dehydrogenase, acyl CoA dehydrogenase, thiolase.

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Understand the Problem

The question is asking about the enzymatic reactions involved in shortening the carbon chain of fatty acids by 2 carbon atoms, specifically the order of enzymes participating in this process.

Answer

Order: Acyl CoA dehydrogenase, enoyl hydratase, OH acyl CoA dehydrogenase, thiolase.

The correct order is: Acyl CoA dehydrogenase, enoyl hydratase, OH acyl CoA dehydrogenase, thiolase.

Answer for screen readers

The correct order is: Acyl CoA dehydrogenase, enoyl hydratase, OH acyl CoA dehydrogenase, thiolase.

More Information

In the β-oxidation pathway, fatty acids are broken down into acetyl-CoA units in a cyclic process that shortens the carbon chain by two carbons each cycle.

Tips

A common mistake is confusing the order of OH acyl CoA dehydrogenase and enoyl hydratase. Remember, hydratase adds water before dehydrogenase oxidizes.

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