Solve for x and y given the parallelogram.

Question image

Understand the Problem

The question is asking to solve for the values of x and y in the context of a given parallelogram, which involves using the properties of the angles in the shape.

Answer

$x \approx 22.71$, $y = 128$
Answer for screen readers

$x \approx 22.71$
$y = 128$

Steps to Solve

  1. Identify angle relationships in the parallelogram

In a parallelogram, opposite angles are equal, and consecutive angles are supplementary (add up to 180°). Here, we can establish two equations based on the given angles.

  1. Set up the first equation using consecutive angles

The angle represented as $(2x + 30)^\circ$ and the angle represented as $(5x - 9)^\circ$ are consecutive angles.

The relationship can be expressed as:
$$(2x + 30) + (5x - 9) = 180$$

  1. Simplify and solve for x

Combine like terms in the equation and isolate (x):

$$2x + 30 + 5x - 9 = 180$$
$$7x + 21 = 180$$
$$7x = 180 - 21$$
$$7x = 159$$
$$x = \frac{159}{7}$$
$$x = 22.71$$ (approximately)

  1. Set up the second equation using the other angles

The angle represented as $\left(\frac{1}{2}y\right)^\circ$ and the angle represented as $(y - 12)^\circ$ are also consecutive angles.

The relationship can be expressed as:
$$\frac{1}{2}y + (y - 12) = 180$$

  1. Simplify and solve for y

Combine like terms in the equation and isolate (y):

$$\frac{1}{2}y + y - 12 = 180$$
$$\frac{3}{2}y - 12 = 180$$
$$\frac{3}{2}y = 180 + 12$$
$$\frac{3}{2}y = 192$$
$$y = \frac{192 \cdot 2}{3}$$
$$y = \frac{384}{3}$$
$$y = 128$$

$x \approx 22.71$
$y = 128$

More Information

In a parallelogram, the properties of angles lead to the establishment of systems of equations. Here, the relationships exploited allowed us to find the values of both (x) and (y).

Tips

  • Not recognizing that consecutive angles are supplementary: Always remember that in parallelograms, adjacent angles add to 180°.
  • Confusing the relationships of opposite angles: Ensure you understand that opposite angles in a parallelogram are equal.

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