Simplify the square root. Assume all variables represent positive numbers. If the square root is already simplified, so state. √63 = ?
Understand the Problem
The question is asking to simplify the square root of 63 and to state if it is already in its simplest form. The goal is to determine if the square root can be simplified further or confirm that it is simplified.
Answer
$$ \sqrt{63} = 3\sqrt{7} $$
Answer for screen readers
$$ \sqrt{63} = 3\sqrt{7} $$
Steps to Solve
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Find the prime factorization of 63
To simplify $\sqrt{63}$, we begin by determining its prime factors. The prime factorization of 63 is:
$$ 63 = 3^2 \times 7 $$ -
Rewrite the square root using the prime factors
Using the prime factorization, we can express the square root as:
$$ \sqrt{63} = \sqrt{3^2 \times 7} $$ -
Apply the property of square roots
We know that $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$. Therefore, we can separate the factors:
$$ \sqrt{3^2 \times 7} = \sqrt{3^2} \times \sqrt{7} $$ -
Simplify the square root
Now we simplify $\sqrt{3^2}$, which equals 3:
$$ \sqrt{3^2} = 3 $$
So, we have:
$$ \sqrt{63} = 3 \times \sqrt{7} $$ -
Final simplified form
Thus, the simplified form of $\sqrt{63}$ is:
$$ \sqrt{63} = 3\sqrt{7} $$
Conclusion
The expression is not in its simplest form initially; it simplifies to $3\sqrt{7}$.
$$ \sqrt{63} = 3\sqrt{7} $$
More Information
The square root $\sqrt{63}$ simplifies to $3\sqrt{7}$ because 63 contains a perfect square factor, which is $3^2 = 9$. Simplifying square roots is common in mathematics to express numbers in a more manageable form.
Tips
- Forgetting to factor the number: Always factor the number inside the square root to find perfect squares.
- Incorrectly simplifying fractions: Be sure to apply simplification rules correctly when manipulating fractions that involve square roots.
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