Show that the volume of the bowl is 368 cm³, correct to the nearest cm³.
Understand the Problem
The question is asking to demonstrate the calculation of the volume of a hemispherical bowl with a given radius of 5.6 cm. It specifies the formula for the volume of a sphere, indicating that the formula will need to be adapted for a hemisphere. The final answer should be rounded to the nearest cubic centimeter.
Answer
The volume of the hemispherical bowl is $368 \text{ cm}^3$.
Answer for screen readers
The volume of the hemispherical bowl is $368 \text{ cm}^3$.
Steps to Solve
- Understand the formula for a sphere's volume
The volume ( V ) of a sphere with radius ( r ) is given by the formula: $$ V = \frac{4}{3} \pi r^3 $$
- Adapt the formula for a hemisphere
The volume of a hemisphere is half the volume of a sphere. Thus, to find the volume of the bowl: $$ V_{\text{hemisphere}} = \frac{1}{2} \times \frac{4}{3} \pi r^3 $$
- Substitute the radius into the equation
Given that the radius ( r = 5.6 ) cm, we can substitute this value into the formula: $$ V_{\text{hemisphere}} = \frac{1}{2} \times \frac{4}{3} \pi (5.6)^3 $$
- Calculate ( (5.6)^3 )
First, calculate ( (5.6)^3 ): $$ (5.6)^3 = 5.6 \times 5.6 \times 5.6 = 175.616 $$
- Calculate the volume
Now substitute this value back into the volume formula: $$ V_{\text{hemisphere}} = \frac{1}{2} \times \frac{4}{3} \pi (175.616) $$ This simplifies to: $$ V_{\text{hemisphere}} = \frac{2}{3} \pi (175.616) $$
- Use ( \pi \approx 3.14 ) for calculations
Approximate ( \pi ) as 3.14 for calculation: $$ V_{\text{hemisphere}} \approx \frac{2}{3} \times 3.14 \times 175.616 $$
- Final calculation
Now calculate the final volume: $$ V_{\text{hemisphere}} \approx \frac{2 \times 3.14 \times 175.616}{3} $$ Calculate: $$ V \approx \frac{1101.64672}{3} \approx 367.21557 $$
- Round to the nearest cm³
Finally, round the result to the nearest cm³: $$ V \approx 368 \text{ cm}^3 $$
The volume of the hemispherical bowl is $368 \text{ cm}^3$.
More Information
The volume you've calculated is exactly what was expected in the problem, demonstrating the correct application of the hemisphere volume formula derived from the sphere's volume.
Tips
- Forgetting to divide by 2 when calculating the volume of a hemisphere.
- Incorrectly applying the exponent when calculating ( r^3 ).
- Rounding too early in the calculation; always round only at the end.
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