Select and write the most appropriate answer from the given alternatives. 1) Negation of P → (p v ~q) is a) ~p → (~p v q) b) p ∧ (~p ∧ q) c) ~p v (~p v ~q) d) ~p → (~p v q). 2) The... Select and write the most appropriate answer from the given alternatives. 1) Negation of P → (p v ~q) is a) ~p → (~p v q) b) p ∧ (~p ∧ q) c) ~p v (~p v ~q) d) ~p → (~p v q). 2) The equation of tangent to the curve y = 1 - e^(x/2) at the point of intersection with Y - axis is .......... a) x + 2y = 0 b) 2x + y = 0 c) x - y = 2 d) x + y = 2. 3) The value of tan(2tan^(-1)(3)) is ........... a) 15/27 b) 14/27 c) 3/4 d) 13/27. 4) If y = cot^(-1)(1 + 6x^2) then dy/dx = ............ a) 1/(1+9x^2) b) 3/(1+9x^2) c) 2/(1+4x^2) d) 6/(1+9x^2). 5) The joint equation of pair of lines passing through (2, 3) and parallel to coordinate axes is ........ a) xy - 3x - 2y + 6 = 0 b) xy + 3x + 2y + 6 = 0 c) xy = 0 d) xy - 3x - 2y - 6 = 0. 6) ∫(1/x) logx dx = .......... a) log(logx) + c b) 1/2(logx)^2 + c c) 2logx + c d) logx + c. 7) If A = [3 2; 4] and A (adjA) = KI then value of K is ........... a) 2 b) -2 c) 10 d) -10. 8) The solution set of inequalities 2x + 3y < 6 is ............ a) Whole xy plane b) open half plane which does not contain origin c) half plane that contains the origin d) open half plane. 2) If y = sin^(-1)x + cos^(-1)x find dy/dx. 2) Find value of cos^(-1)(9π/4). 3) Write the negation of (p ↔ q). 4) Write the separate equations of lines represented by the equation 5x^2 - 9y^2 = 0.

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Understand the Problem

The question is a mathematics exam paper requiring answers to various problems related to algebra, calculus, and geometry, as well as logical negation.

Answer

The negation of \( P \rightarrow (P \vee \neg Q) \) simplifies to \( P \wedge \neg P \wedge Q \).
Answer for screen readers

The correct answer for the negation of ( P \rightarrow (P \vee \neg Q) ) is ( P \wedge \neg (P \vee \neg Q) ).

Steps to Solve

  1. Negation of the Statement To find the negation of the statement ( P \rightarrow (P \vee \neg Q) ), we first remember that the negation of ( A \rightarrow B ) is ( A \wedge \neg B ).

Here, we need to negate ( P \rightarrow (P \vee \neg Q) ): [ \neg (P \rightarrow (P \vee \neg Q)) = P \wedge \neg (P \vee \neg Q) ]

  1. Applying De Morgan’s Theorem Next, we simplify ( \neg (P \vee \neg Q) ) using De Morgan's Theorem: [ \neg (P \vee \neg Q) = \neg P \wedge Q ]

  2. Combine the Results Now we substitute this back into our negation: [ \neg (P \rightarrow (P \vee \neg Q)) = P \wedge (\neg P \wedge Q) ] This simplifies to: [ P \wedge \neg P \wedge Q ]

Since ( P \wedge \neg P ) is always false, the entire expression is false.

  1. Identifying the Correct Answer Now, we need to find the correct choice from the options provided. The key is to identify which option simplifies to ( P \wedge \neg (P \vee \neg Q) ):
  • The correct answer in this case would correspond to this logical structure.

The correct answer for the negation of ( P \rightarrow (P \vee \neg Q) ) is ( P \wedge \neg (P \vee \neg Q) ).

More Information

This represents logical structures and helps understand implications and their negations in propositions.

Tips

  • Not applying De Morgan's Law correctly.
  • Confusing the implication negation with other logical operations.

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