Select and write the most appropriate answer from the given alternatives. 1) Negation of P → (p v ~q) is a) ~p → (~p v q) b) p ∧ (~p ∧ q) c) ~p v (~p v ~q) d) ~p → (~p v q). 2) The... Select and write the most appropriate answer from the given alternatives. 1) Negation of P → (p v ~q) is a) ~p → (~p v q) b) p ∧ (~p ∧ q) c) ~p v (~p v ~q) d) ~p → (~p v q). 2) The equation of tangent to the curve y = 1 - e^(x/2) at the point of intersection with Y - axis is .......... a) x + 2y = 0 b) 2x + y = 0 c) x - y = 2 d) x + y = 2. 3) The value of tan(2tan^(-1)(3)) is ........... a) 15/27 b) 14/27 c) 3/4 d) 13/27. 4) If y = cot^(-1)(1 + 6x^2) then dy/dx = ............ a) 1/(1+9x^2) b) 3/(1+9x^2) c) 2/(1+4x^2) d) 6/(1+9x^2). 5) The joint equation of pair of lines passing through (2, 3) and parallel to coordinate axes is ........ a) xy - 3x - 2y + 6 = 0 b) xy + 3x + 2y + 6 = 0 c) xy = 0 d) xy - 3x - 2y - 6 = 0. 6) ∫(1/x) logx dx = .......... a) log(logx) + c b) 1/2(logx)^2 + c c) 2logx + c d) logx + c. 7) If A = [3 2; 4] and A (adjA) = KI then value of K is ........... a) 2 b) -2 c) 10 d) -10. 8) The solution set of inequalities 2x + 3y < 6 is ............ a) Whole xy plane b) open half plane which does not contain origin c) half plane that contains the origin d) open half plane. 2) If y = sin^(-1)x + cos^(-1)x find dy/dx. 2) Find value of cos^(-1)(9π/4). 3) Write the negation of (p ↔ q). 4) Write the separate equations of lines represented by the equation 5x^2 - 9y^2 = 0.
Understand the Problem
The question is a mathematics exam paper requiring answers to various problems related to algebra, calculus, and geometry, as well as logical negation.
Answer
The negation of \( P \rightarrow (P \vee \neg Q) \) simplifies to \( P \wedge \neg P \wedge Q \).
Answer for screen readers
The correct answer for the negation of ( P \rightarrow (P \vee \neg Q) ) is ( P \wedge \neg (P \vee \neg Q) ).
Steps to Solve
- Negation of the Statement To find the negation of the statement ( P \rightarrow (P \vee \neg Q) ), we first remember that the negation of ( A \rightarrow B ) is ( A \wedge \neg B ).
Here, we need to negate ( P \rightarrow (P \vee \neg Q) ): [ \neg (P \rightarrow (P \vee \neg Q)) = P \wedge \neg (P \vee \neg Q) ]
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Applying De Morgan’s Theorem Next, we simplify ( \neg (P \vee \neg Q) ) using De Morgan's Theorem: [ \neg (P \vee \neg Q) = \neg P \wedge Q ]
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Combine the Results Now we substitute this back into our negation: [ \neg (P \rightarrow (P \vee \neg Q)) = P \wedge (\neg P \wedge Q) ] This simplifies to: [ P \wedge \neg P \wedge Q ]
Since ( P \wedge \neg P ) is always false, the entire expression is false.
- Identifying the Correct Answer Now, we need to find the correct choice from the options provided. The key is to identify which option simplifies to ( P \wedge \neg (P \vee \neg Q) ):
- The correct answer in this case would correspond to this logical structure.
The correct answer for the negation of ( P \rightarrow (P \vee \neg Q) ) is ( P \wedge \neg (P \vee \neg Q) ).
More Information
This represents logical structures and helps understand implications and their negations in propositions.
Tips
- Not applying De Morgan's Law correctly.
- Confusing the implication negation with other logical operations.
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