Polar to Cartesian and vice versa equation conversion practice problems
Understand the Problem
The question is asking for practice problems related to the conversion between polar and Cartesian coordinates, including the equations and examples of how to perform these conversions.
Answer
Use the formulas $x = r \cos(\theta)$, $y = r \sin(\theta)$ for conversions from polar to Cartesian, and $r = \sqrt{x^2 + y^2}$, $\theta = \tan^{-1}\left(\frac{y}{x}\right)$ for Cartesian to polar conversions.
Answer for screen readers
The practice problems involve converting between polar and Cartesian coordinates using the formulas $x = r \cos(\theta)$, $y = r \sin(\theta)$ for polar to Cartesian, and $r = \sqrt{x^2 + y^2}$, $\theta = \tan^{-1}\left(\frac{y}{x}\right)$ for Cartesian to polar.
Steps to Solve
- Understanding Polar and Cartesian Coordinates
Polar coordinates are represented as $(r, \theta)$ where $r$ is the distance from the origin and $\theta$ is the angle from the positive x-axis. Cartesian coordinates are represented as $(x, y)$.
- Conversion from Polar to Cartesian
To convert from polar to Cartesian coordinates, use the following formulas:
- $x = r \cos(\theta)$
- $y = r \sin(\theta)$
This means that if you have a point in polar coordinates, you can find its Cartesian coordinates using the angle and the radius.
- Example of Polar to Cartesian Conversion
Let's say we have polar coordinates $(5, \frac{\pi}{3})$.
Using the formulas:
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For $x$: $$ x = 5 \cos\left(\frac{\pi}{3}\right) = 5 \times \frac{1}{2} = 2.5 $$
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For $y$: $$ y = 5 \sin\left(\frac{\pi}{3}\right) = 5 \times \frac{\sqrt{3}}{2} \approx 4.33 $$
Thus, in Cartesian coordinates, it becomes $(2.5, 4.33)$.
- Conversion from Cartesian to Polar
To convert from Cartesian to polar coordinates, use these formulas:
- $r = \sqrt{x^2 + y^2}$
- $\theta = \tan^{-1}\left(\frac{y}{x}\right)$
Therefore, given Cartesian coordinates, you can determine the polar coordinates using these equations.
- Example of Cartesian to Polar Conversion
Suppose we have Cartesian coordinates $(3, 4)$.
Using the conversion formulas:
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For $r$: $$ r = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 $$
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For $\theta$: $$ \theta = \tan^{-1}\left(\frac{4}{3}\right) \approx 0.93 , \text{radians} $$
So, in polar coordinates, it becomes $(5, 0.93)$.
The practice problems involve converting between polar and Cartesian coordinates using the formulas $x = r \cos(\theta)$, $y = r \sin(\theta)$ for polar to Cartesian, and $r = \sqrt{x^2 + y^2}$, $\theta = \tan^{-1}\left(\frac{y}{x}\right)$ for Cartesian to polar.
More Information
Understanding the conversion between polar and Cartesian coordinates is essential in fields such as physics, engineering, and computer graphics. It provides a way to describe points in two-dimensional space, leveraging different coordinate systems based on the needs of the problem.
Tips
- Confusing the formulas during conversion (e.g., using polar formulas when working in Cartesian coordinates).
- Forgetting to appropriately handle the angle in radians when using trigonometric functions.
- Neglecting to consider the quadrant when determining $\theta$ from Cartesian coordinates.
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