Of the two cells represented in the figure, which would likely be more efficient at exchanging substances with the surrounding environment?
Understand the Problem
The question asks which of the two cell models depicted would be more efficient at exchanging substances based on their surface-area-to-volume ratios. To find the answer, we will compare the surface-area-to-volume ratios of Cell A and Cell B.
Answer
Cell A, as it has the larger surface-area-to-volume ratio.
The final answer is Cell A, because it has the larger surface-area-to-volume ratio.
Answer for screen readers
The final answer is Cell A, because it has the larger surface-area-to-volume ratio.
More Information
A cell with a larger surface-area-to-volume ratio can exchange materials more efficiently because there is more area available for substances to diffuse across, relative to the volume that must be supplied.
Tips
A common mistake is to incorrectly calculate the surface area or volume, leading to an incorrect ratio.
Sources
- AP Biology AP Classroom Quizzes - Quizlet - quizlet.com
- Two Different Models of a Living Cell - Numerade - numerade.com
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