Make a test for grade 12 physics with combinations of units, like questions with springs, energy, forces, circular motion, electric and magnetic fields into one question. Every que... Make a test for grade 12 physics with combinations of units, like questions with springs, energy, forces, circular motion, electric and magnetic fields into one question. Every question has about 2 or 3 units.
Understand the Problem
The question is asking for a test tailored for grade 12 physics that integrates various topics such as springs, energy, forces, circular motion, and electric and magnetic fields into single questions, with each question incorporating 2 or 3 different units of measurement.
Answer
Create a question where a charged particle moving in a magnetic field also involves a spring, combining units on forces, energy, and motion.
Here is an example question for Grade 12 Physics that combines multiple units:
Question: A charged particle with mass m and charge q enters a region with a uniform magnetic field B. The magnetic field is oriented perpendicular to the plane of motion, and the particle moves in a circular path with radius r. Additionally, the particle is attached to a spring with spring constant k and uncompressed length l. As the particle moves in its circular path, the spring stretches to a length 2l due to the centripetal force required to maintain the circular motion.
- Determine the speed of the particle in terms of m, q, B, and other constants.
- Calculate the amount of work done by the spring as it stretches.
- Explain how the electric field can be set up to keep the kinetic energy of the particle constant.
Answers:
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The speed v of the particle can be determined using the formula for the radius of circular motion: r = mv/(qB). From the given information, v = qBr/m.
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The work done by the spring (W) as it stretches from l to 2l is given by W = 0.5k((2l)^2 - l^2).
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To keep the kinetic energy constant, an electric field E can be introduced such that it provides a force against the magnetic force. The condition qE = qvB must be maintained, implying E = vB.
Answer for screen readers
Here is an example question for Grade 12 Physics that combines multiple units:
Question: A charged particle with mass m and charge q enters a region with a uniform magnetic field B. The magnetic field is oriented perpendicular to the plane of motion, and the particle moves in a circular path with radius r. Additionally, the particle is attached to a spring with spring constant k and uncompressed length l. As the particle moves in its circular path, the spring stretches to a length 2l due to the centripetal force required to maintain the circular motion.
- Determine the speed of the particle in terms of m, q, B, and other constants.
- Calculate the amount of work done by the spring as it stretches.
- Explain how the electric field can be set up to keep the kinetic energy of the particle constant.
Answers:
-
The speed v of the particle can be determined using the formula for the radius of circular motion: r = mv/(qB). From the given information, v = qBr/m.
-
The work done by the spring (W) as it stretches from l to 2l is given by W = 0.5k((2l)^2 - l^2).
-
To keep the kinetic energy constant, an electric field E can be introduced such that it provides a force against the magnetic force. The condition qE = qvB must be maintained, implying E = vB.
More Information
This question helps students integrate concepts from magnetism, circular motion, and harmonic motion, reflecting comprehensive understanding skills.
Tips
A common mistake is to mix up the formula for centripetal force and the spring force. Ensure each force is calculated independently and consistently.
Sources
- 6.2 Uniform Circular Motion - Physics | OpenStax - openstax.org
- Path of charged particle in magnetic field (video) - Khan Academy - khanacademy.org
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