Solve the system by substitution: y = -x and 10x + 2y = 40.

Understand the Problem

The question is asking us to solve a system of equations using the substitution method. This involves substituting one equation into the other to find the values of x and y.

Answer

The solution to the system of equations is $\left( \frac{4}{3}, \frac{17}{3} \right)$.
Answer for screen readers

The solution to the system of equations is $\left( \frac{4}{3}, \frac{17}{3} \right)$.

Steps to Solve

  1. Identify the equations Let's say we have the following system of equations:

$$ \begin{align*}

  1. & \quad y = 2x + 3 \

  2. & \quad x + y = 7 \end{align*} $$

  3. Substitute the first equation into the second We will substitute the expression for $y$ from the first equation into the second equation.

This gives us: $$ x + (2x + 3) = 7 $$

  1. Simplify the equation Now, combine like terms in the equation: $$ 3x + 3 = 7 $$

  2. Solve for x Next, isolate $x$ by subtracting 3 from both sides: $$ 3x = 4 $$ Now divide both sides by 3: $$ x = \frac{4}{3} $$

  3. Substitute x back to find y Now we have the value of $x$. We substitute $x = \frac{4}{3}$ back into the first equation to find $y$: $$ y = 2\left(\frac{4}{3}\right) + 3 $$

  4. Calculate y This simplifies to: $$ y = \frac{8}{3} + 3 = \frac{8}{3} + \frac{9}{3} = \frac{17}{3} $$

  5. State the solution The solution to the system of equations is: $$ \left( \frac{4}{3}, \frac{17}{3} \right) $$

The solution to the system of equations is $\left( \frac{4}{3}, \frac{17}{3} \right)$.

More Information

This solution involves using the substitution method for systems of linear equations. It shows that you can effectively find variable values step by step.

Tips

  • Forgetting to substitute the correct expression when moving from one equation to the other.
  • Making arithmetic errors when combining and simplifying terms.

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