Luke is building a bike ramp. The ramp is going to be 3 feet tall on the high end and is 6 feet long. How long is the base of the ramp?
Understand the Problem
The question is asking for the length of the base of a right triangle formed by the bike ramp, where the height and the length of the ramp are given. This is a classic application of the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the ramp) is equal to the sum of the squares of the other two sides (height and base).
Answer
The length of the base of the ramp is $3\sqrt{3}$ feet.
Answer for screen readers
The length of the base of the ramp is $3\sqrt{3}$ feet, which is approximately 5.20 feet.
Steps to Solve
- Identify the known values
In this problem, we have the height of the triangle ($h$) and the length of the hypotenuse ($r$). The height is given as 3 feet, and the length of the ramp (hypotenuse) is 6 feet.
- $h = 3 \text{ feet}$
- $r = 6 \text{ feet}$
- Apply the Pythagorean theorem
The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. This can be written as:
$$ r^2 = h^2 + b^2 $$
where $b$ is the length of the base we want to find.
- Substitute the known values into the equation
Now we substitute $r$ and $h$ into the equation:
$$ 6^2 = 3^2 + b^2 $$
Simplifying gives:
$$ 36 = 9 + b^2 $$
- Solve for the base
To find $b^2$, we rearrange the equation:
$$ b^2 = 36 - 9 $$
which simplifies to:
$$ b^2 = 27 $$
Now, take the square root of both sides to find $b$:
$$ b = \sqrt{27} = 3\sqrt{3} \text{ feet} $$
The length of the base of the ramp is $3\sqrt{3}$ feet, which is approximately 5.20 feet.
More Information
The Pythagorean theorem is a fundamental concept in geometry used extensively in various applications, including construction and engineering. The values can be confirmed by plugging them back into the original formula.
Tips
- Miscalculating the square of the hypotenuse or any of the triangle's sides.
- Forgetting to subtract correctly while rearranging the equation.
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