Let S be a set. Which one of the following is always correct? 1) a ∈ S and b ∈ S implies {a, b} ⊆ P(S) 2) a ∈ S and b ∈ S implies {a, b} ∈ P(S) 3) a ∈ S and b ∈ S implies {a, b} ∈... Let S be a set. Which one of the following is always correct? 1) a ∈ S and b ∈ S implies {a, b} ⊆ P(S) 2) a ∈ S and b ∈ S implies {a, b} ∈ P(S) 3) a ∈ S and b ∈ S implies {a, b} ∈ S 4) a ∈ S implies a ∈ P(S)

Understand the Problem

The question is asking to determine which of the given statements about set membership and power sets is always correct when certain conditions about elements a and b being in set S are met.

Answer

If $a \in S$ and $b \in S$, then $\{a\} \in \mathcal{P}(S)$ and $\{b\} \in \mathcal{P}(S)$.
Answer for screen readers

The statement that is always correct given the conditions is that if $a \in S$ and $b \in S$, then both ${a}$ and ${b}$ are elements of the power set $\mathcal{P}(S)$.

Steps to Solve

  1. Identify the Given Statements

List all the statements regarding set membership and power sets that need to be evaluated for correctness.

  1. Understanding Set Membership

Recall the definition of set membership. If $a \in S$, then $a$ is an element of set $S$. If $b \in S$, then the same applies for $b$.

  1. Understanding Power Sets

Recall that the power set of a set $S$, denoted as $\mathcal{P}(S)$, is the set of all subsets of $S$. This includes the empty set $\emptyset$, the set $S$ itself, and every combination of elements in $S$.

  1. Evaluating the Statements

For each statement, check if it logically follows from the properties of set membership and power sets. Formulate logical conclusions based on the definitions.

  1. Determine Which Statement is Always Correct

After evaluating each statement, identify the one that is universally true regardless of the specific elements involved, as long as the conditions about $a$ and $b$ being in $S$ are met.

The statement that is always correct given the conditions is that if $a \in S$ and $b \in S$, then both ${a}$ and ${b}$ are elements of the power set $\mathcal{P}(S)$.

More Information

This conclusion is based on the properties of subsets. Any single element of a set is always a subset of that set, hence it will always belong to its power set. A power set contains all possible subsets of the set.

Tips

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