In an experiment with a haploid frog embryo, what is the effect of reducing DNA content? A) MBT is delayed, resulting in a higher cell count. B) Cell division speed increases with... In an experiment with a haploid frog embryo, what is the effect of reducing DNA content? A) MBT is delayed, resulting in a higher cell count. B) Cell division speed increases with each cycle. C) More cleavage divisions occur than normal. D) MBT occurs at the same time as in diploid embryos.
Understand the Problem
The question asks about the effects of reducing DNA content in a haploid frog embryo during an experiment, specifically looking at the implications on cell division and development. It is likely seeking to identify the correct impact on the cell's developmental timing and division processes.
Answer
A) MBT is delayed, resulting in a higher cell count.
The final answer is A) MBT is delayed, resulting in a higher cell count.
Answer for screen readers
The final answer is A) MBT is delayed, resulting in a higher cell count.
More Information
Reducing DNA content in haploid embryos decreases the DNA-to-cytoplasm ratio, delaying the onset of the Mid-Blastula Transition (MBT). This results in additional cleavage cycles before the transition, leading to a higher cell count compared to diploid embryos.
Tips
A common mistake is to assume that DNA content affects only the speed of cell division or the overall timing of MBT without considering the impact on cell number.
Sources
- Histone titration against the genome sets the DNA-to-cytoplasm ratio threshold in Xenopus embryos - pnas.org
- Interphase-arrested Drosophila embryos activate zygotic gene expression upon DNA replication checkpoint inactivation - journals.plos.org
- Spatiotemporal Patterning of Zygotic Genome Activation in a Model System - cell.com
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