In 2022, the cost of posting a parcel with a mass of 1 kg or less is $4.60. The cost increases by $1.10 for each additional 0.5 kg. Find the cost of posting a parcel with a mass of... In 2022, the cost of posting a parcel with a mass of 1 kg or less is $4.60. The cost increases by $1.10 for each additional 0.5 kg. Find the cost of posting a parcel with a mass of 3.5 kg.
Understand the Problem
The question is asking to calculate the cost of posting a parcel weighing 3.5 kg based on a given pricing structure. The cost starts at $4.60 for 1 kg or less, and will increase by $1.10 for every additional 0.5 kg. We need to determine the total cost for a parcel of 3.5 kg.
Answer
The cost is $10.10.
Answer for screen readers
The cost of posting a parcel with a mass of 3.5 kg is $10.10.
Steps to Solve
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Determine the base cost The cost of posting a parcel with a mass of 1 kg or less is given as $4.60.
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Calculate the additional weight The total weight to consider is 3.5 kg. Since the base weight is 1 kg, calculate the additional weight:
$$ 3.5 , \text{kg} - 1 , \text{kg} = 2.5 , \text{kg} $$ -
Find the number of 0.5 kg increments Next, convert the additional weight into increments of 0.5 kg: $$ \frac{2.5 , \text{kg}}{0.5 , \text{kg}} = 5 $$
This means there are 5 increments of 0.5 kg over the initial kg. -
Calculate the additional cost Each 0.5 kg increment costs $1.10. Therefore, the total additional cost is: $$ 5 \times 1.10 = 5.50 $$
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Find the total cost Now, add the base cost and the additional cost: $$ \text{Total Cost} = 4.60 + 5.50 = 10.10 $$
The cost of posting a parcel with a mass of 3.5 kg is $10.10.
More Information
In this pricing structure, the cost increases systematically based on the weight increments. Understanding how to break down the weight into manageable increments is crucial for calculating shipping costs accurately.
Tips
- Forgetting to convert the additional weight into increments of 0.5 kg can lead to incorrect calculations.
- Overlooking the base cost when adding additional costs results in an inaccurate total.
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