If a plant with genotype AaBb is self-pollinated, what phenotypic ratio would you expect to observe in the progeny if complete linkage were to occur?
Understand the Problem
The question asks us to predict the phenotypic ratio in the progeny of a self-pollinated plant with genotype AaBb, assuming complete genetic linkage between genes A and B. Complete linkage means that no recombination occurs, so the alleles A and B will always be inherited together.
Answer
The expected phenotypic ratio is 3:1 due to the complete linkage of the genes.
If a plant with genotype AaBb is self-pollinated and complete linkage occurs, the expected phenotypic ratio in the progeny would be 3:1. This is because the two genes (A and B) are located close together on the same chromosome and are inherited as a single unit.
Answer for screen readers
If a plant with genotype AaBb is self-pollinated and complete linkage occurs, the expected phenotypic ratio in the progeny would be 3:1. This is because the two genes (A and B) are located close together on the same chromosome and are inherited as a single unit.
More Information
Complete linkage means that there is no crossing over between the two genes. If the genes were not linked, the expected ratio would be 9:3:3:1.
Tips
A common mistake is to apply the dihybrid cross ratio (9:3:3:1) even when the genes are linked, which is incorrect.
Sources
- Chapter 5: Linkage – Crop Genetics - iastate.pressbooks.pub
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