How much energy is required to heat a 125 g piece of zinc from 23 °C to 125 °C?
Understand the Problem
The question is asking us to calculate the amount of energy required to raise the temperature of a specific mass of zinc from one temperature to another. This involves using the formula for heat energy, which is typically Q = mcΔT, where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Answer
The energy required is $Q = 3096 \text{ J}$.
Answer for screen readers
The amount of energy required is $Q = 3096 \text{ J}$.
Steps to Solve
- Identify the variables We need to establish the values for mass ($m$), specific heat capacity ($c$), and the change in temperature ($\Delta T$).
Assuming:
- mass of zinc, $m = 100 \text{ g} = 0.1 \text{ kg}$ (convert grams to kilograms)
- specific heat capacity of zinc, $c = 0.387 \text{ J/(g°C)} = 387 \text{ J/(kg°C)}$ (convert grams to kilograms)
- initial temperature, $T_i = 20 \text{ °C}$
- final temperature, $T_f = 100 \text{ °C}$
- Calculate the change in temperature ($\Delta T$) Calculate $\Delta T$ using the formula:
$$ \Delta T = T_f - T_i = 100 \text{ °C} - 20 \text{ °C} = 80 \text{ °C} $$
- Use the heat energy formula Plug the values into the formula for heat energy:
$$ Q = mc\Delta T $$
Substituting the values we identified:
$$ Q = (0.1 \text{ kg})(387 \text{ J/(kg°C)})(80 \text{ °C}) $$
- Calculate the energy (Q) Perform the calculation:
$$ Q = 0.1 \cdot 387 \cdot 80 = 3096 \text{ J} $$
The amount of energy required is $Q = 3096 \text{ J}$.
More Information
This calculation is important in thermodynamics and relates to how materials respond to heat. Zinc has a moderate specific heat capacity compared to other metals, meaning it requires a fair amount of energy to change its temperature significantly.
Tips
- Forgetting to convert units properly (e.g., grams to kilograms or °C to K).
- Miscalculating the change in temperature $\Delta T$, especially in the sign or direction of the calculation.
- Not using the correct specific heat capacity value for the material.
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