How many moles of O2 will be formed from 1.65 moles of KClO3? How many moles of KClO3 are needed to make 3.50 moles of KCl? How many moles of KCl will be formed from 2.73 moles of... How many moles of O2 will be formed from 1.65 moles of KClO3? How many moles of KClO3 are needed to make 3.50 moles of KCl? How many moles of KCl will be formed from 2.73 moles of KClO3?
Understand the Problem
The question presents a set of stoichiometry problems asking about the relationships between moles of different substances involved in chemical reactions. Each part requires the application of stoichiometric principles to determine the moles of reactants or products based on given amounts.
Answer
1. 2.48 mol O₂ 2. 3.50 mol KCl₃ 3. 2.73 mol KCl
Answer for screen readers
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2.48 mol O₂ will be produced from 1.65 mol of KClo₃.
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3.50 mol of KClo₃ are needed to make 3.50 mol of KCl.
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2.73 mol of KCl will be formed from 2.73 mol of KClo₃.
Steps to Solve
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Understanding the Reaction
The chemical reaction involved is: $$ 2 , \text{KClo}_3 \rightarrow 2 , \text{KCl} + 3 , \text{O}_2 $$
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Calculating Moles of O₂ from KClo₃
From the reaction, 2 moles of $ \text{KClo}_3 $ produce 3 moles of $ \text{O}_2 $. The relation can be expressed as: $$ \frac{3 , \text{mol O}_2}{2 , \text{mol KClo}_3} $$
Using 1.65 moles of $ \text{KClo}_3 $: $$ \text{Moles of } O_2 = 1.65 , \text{mol KClo}_3 \times \frac{3 , \text{mol O}_2}{2 , \text{mol KClo}_3} = 2.48 , \text{mol O}_2 $$
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Calculating Moles of KClo₃ from KCl
Next, using the reaction ratio to find how many moles of $ \text{KClo}_3 $ are needed for 3.50 moles of KCl: $$ \frac{2 , \text{mol KClo}_3}{2 , \text{mol KCl}} $$
Hence: $$ \text{Moles of } KClo_3 = 3.50 , \text{mol KCl} \times \frac{2 , \text{mol KClo}_3}{2 , \text{mol KCl}} = 3.50 , \text{mol KClo}_3 $$
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Calculating Moles of KCl from KClo₃
Finally, using 2.73 moles of $ \text{KClo}_3 $ to find moles of KCl produced: $$ \frac{2 , \text{mol KCl}}{2 , \text{mol KClo}_3} $$
So: $$ \text{Moles of KCl} = 2.73 , \text{mol KClo}_3 \times \frac{2 , \text{mol KCl}}{2 , \text{mol KClo}_3} = 2.73 , \text{mol KCl} $$
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2.48 mol O₂ will be produced from 1.65 mol of KClo₃.
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3.50 mol of KClo₃ are needed to make 3.50 mol of KCl.
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2.73 mol of KCl will be formed from 2.73 mol of KClo₃.
More Information
This problem illustrates how to apply stoichiometry to calculate the various relationships between reactants and products in a chemical reaction. Recognizing the ratios from the balanced equation is critical to these computations.
Tips
- Forgetting to balance the chemical equation before performing stoichiometric calculations.
- Confusing the coefficients in the balanced equation, leading to incorrect mole ratios.
To avoid these mistakes, always ensure the chemical equation is balanced and double-check the ratios derived from it.
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