How many moles of Ca(NO3)2 are in a 75 mL of 0.25 M solution?
Understand the Problem
The question is asking how to calculate the number of moles of Ca(NO3)2 in a specific volume of solution using the molarity equation, which relates moles, volume, and concentration.
Answer
$$ \text{moles} = M \times \frac{V}{1000} $$
Answer for screen readers
Assuming we have a specific molarity $M$ and volume in milliliters $V$, the formula gives:
$$ \text{moles} = M \times \frac{V}{1000} $$
Steps to Solve
- Write the Molarity Equation
The molarity (M) equation is given by:
$$ M = \frac{\text{moles of solute}}{\text{liters of solution}} $$
We can rearrange this equation to find the number of moles of solute:
$$ \text{moles of solute} = M \times \text{liters of solution} $$
- Identify Given Values
Make sure to identify:
- The molarity (concentration) of the solution, $M$.
- The volume of the solution in liters.
- Convert Volume if Necessary
If the volume is not already in liters, convert it:
$$ \text{liters} = \frac{\text{milliliters}}{1000} $$
- Calculate Moles
Now, plug the values into the rearranged equation:
$$ \text{moles of Ca(NO}_3\text{)}_2 = M \times \text{liters of solution} $$
- Perform the Calculation
Multiply the molarity by the volume in liters to get the number of moles.
Assuming we have a specific molarity $M$ and volume in milliliters $V$, the formula gives:
$$ \text{moles} = M \times \frac{V}{1000} $$
More Information
The number of moles gives an understanding of how much solute is present in the solution, which is important for various applications in chemistry, such as stoichiometry in reactions. Molarity is a commonly used concept that allows chemists to prepare solutions of desired concentrations.
Tips
- Forgetting to convert volume from milliliters to liters, which would result in a calculation error.
- Misunderstanding what the term "molarity" means; it specifically refers to moles per liter of solution.
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