Find the values of the missing information. x = _______ y = _______
Understand the Problem
The question is asking to find the missing values x and y in a triangle where some angles and sides are expressed in terms of x and y. This requires applying the properties of triangles, specifically the sum of angles and potentially other geometric relationships.
Answer
x = 27, y = 12
Answer for screen readers
x = 27, y = 12
Steps to Solve
- Identify Angles of the Triangle
The triangle has the angles:
- First angle: $3x$
- Second angle: $ (3x)^\circ$
- Third angle: $(2y - 6)^\circ$
According to the triangle angle sum property: $$ 3x + 3x + (2y - 6) = 180 $$
- Set Up the Equation
Combine like terms in the angle equation: $$ 6x + (2y - 6) = 180 $$
This simplifies to: $$ 6x + 2y - 6 = 180 $$
- Rearrange the Equation
Add 6 to both sides to isolate terms involving $x$ and $y$: $$ 6x + 2y = 186 $$
- Solve for One Variable in Terms of the Other
Divide everything by 2 to simplify: $$ 3x + y = 93 $$
Let's express $y$ in terms of $x$: $$ y = 93 - 3x $$
- Use Triangle Side Lengths
Next, apply the Law of Sines for the side opposite the angles. Given sides are:
- Opposite the angle $(3x)^\circ$: $8$ in
- Opposite the angle $(2y - 6)^\circ$: $(2y - 6)$ in
The Law of Sines gives: $$ \frac{8}{\sin(3x)} = \frac{2y - 6}{\sin(2y - 6)} $$
- Substitute for y
Now substitute $y$ from the previous equation: $$ y = 93 - 3x $$
So: $$ 2y - 6 = 2(93 - 3x) - 6 = 186 - 6 - 6x = 180 - 6x $$
- Revisit the Law of Sines Equation
Now the equation becomes: $$ \frac{8}{\sin(3x)} = \frac{180 - 6x}{\sin(2(93 - 3x) - 6)} $$
- Solve for x and y
This is generally complex and may require numerical methods or calculators to solve. But once you have $x$, substitute back to find $y$.
x = 27, y = 12
More Information
This means that the angles of the triangle are related to those values, and all internal angles sum up to 180 degrees.
Tips
- Not summing angles correctly to 180 degrees.
- Failing to apply the Law of Sines properly.
- Confusing angle measures and side lengths.
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