Find the value of m if F = mx i - 5y j + 2z k is a Solenoidal vector.
Understand the Problem
The question is asking to find the value of 'm' such that a given vector field is a Solenoidal vector, which means its divergence must be zero. This involves applying the concept of divergence to the vector field ( \mathbf{F} = mx \hat{i} - 5y \hat{j} + 2z \hat{k} ).
Answer
The value of \( m \) is \( 3 \).
Answer for screen readers
The value of ( m ) is ( 3 ).
Steps to Solve
- Identify the vector field and its divergence
The given vector field is
$$ \mathbf{F} = mx \hat{i} - 5y \hat{j} + 2z \hat{k}. $$
We need to find the divergence of this vector field.
- Calculate the divergence of the vector field
The divergence of a vector field ( \mathbf{F} = P \hat{i} + Q \hat{j} + R \hat{k} ) is given by
$$ \nabla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}. $$
For our vector field:
- ( P = mx )
- ( Q = -5y )
- ( R = 2z )
Now calculate each partial derivative:
-
( \frac{\partial P}{\partial x} = \frac{\partial (mx)}{\partial x} = m )
-
( \frac{\partial Q}{\partial y} = \frac{\partial (-5y)}{\partial y} = -5 )
-
( \frac{\partial R}{\partial z} = \frac{\partial (2z)}{\partial z} = 2 )
- Combine the results into the divergence formula
Now substitute these derivatives into the divergence formula:
$$ \nabla \cdot \mathbf{F} = m - 5 + 2 = m - 3. $$
- Set the divergence equal to zero
Since the vector field is solenoidal, we set the divergence to zero:
$$ m - 3 = 0. $$
- Solve for m
Now solve the equation for ( m ):
$$ m = 3. $$
The value of ( m ) is ( 3 ).
More Information
A solenoidal vector field is one where the divergence is zero, denoting incompressibility in fluid dynamics or magnetic fields in physics. This property is essential in many applications, including electromagnetism and fluid flow.
Tips
- Forgetting to differentiate correctly or incorrectly calculating the coefficients in the vector field.
- Not setting the divergence equal to zero properly for solenoidal fields.
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