Factor polynomials in the form 'a² + 2ab + b²'. Fill in the correct answers in the blanks for the provided expressions.
Understand the Problem
The question is asking how to factor polynomials in the form 'a² + 2ab + b²' using an identity known as the identity of the perfect square. It provides examples for practicing the technique involved in recognizing and applying this identity and requires filling in blanks for given expressions.
Answer
1. $(x + 2)^2$ 2. $(x + 6)^2$ 3. $(x + 1)^2$ 4. $(x + 5)^2$ 5. $(x + 9)^2$ 6. $(4 + y)^2$ 7. $(6 + y)^2$ 8. $(7 + y)^2$
Answer for screen readers
- $x^2 + 4x + 4 = (x + 2)^2$
- $36 + 12x + x^2 = (x + 6)^2$
- $x^2 + 2x + 1 = (x + 1)^2$
- $x^2 + 10x + 25 = (x + 5)^2$
- $x^2 + 18x + 81 = (x + 9)^2$
- $16 + 8y + y^2 = (4 + y)^2$
- $36 + 12y + y^2 = (6 + y)^2$
- $49 + 14y + y^2 = (7 + y)^2$
Steps to Solve
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Identifying the form Recognize that we are working with expressions of the form $a^2 + 2ab + b^2$, which factors to $(a + b)^2$.
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Rewriting the expression Write the polynomial in the standard form for perfect squares:
- For example, in the first problem $x^2 + 4x + 4$, identify $a = x$ and $b = 2$.
- Substituting values Substitute into the identity:
- The expression $x^2 + 4x + 4$ can be recognized as $(x + 2)^2$.
- Filling in the blanks For each problem:
- Fill in the appropriate blanks with the identified values for $a$ and $b$.
- Factoring the remaining expressions Continue with the same steps for each additional expression:
- For the second problem $36 + 12x + x^2$, we can rearrange it as $x^2 + 12x + 36$ and identify $a = x$ and $b = 6$. So it's factorable as $(x + 6)^2$.
- Applying to all expressions Repeat the process through problems 3 to 8 in the same way. Identify $a$ and $b$, fill in the factors, and write the factored form.
- $x^2 + 4x + 4 = (x + 2)^2$
- $36 + 12x + x^2 = (x + 6)^2$
- $x^2 + 2x + 1 = (x + 1)^2$
- $x^2 + 10x + 25 = (x + 5)^2$
- $x^2 + 18x + 81 = (x + 9)^2$
- $16 + 8y + y^2 = (4 + y)^2$
- $36 + 12y + y^2 = (6 + y)^2$
- $49 + 14y + y^2 = (7 + y)^2$
More Information
These results show how polynomial expressions can be factored using the identity of perfect squares. Recognizing the patterns allows for quick factoring of quadratic expressions.
Tips
- Overlooking sign changes: Ensure signs are correct when identifying $b$ from $2b$.
- Misidentifying terms: Verify that the expression conforms to the perfect square identity before factoring.
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