Differentiate cosh²(5x) with respect to x.
Understand the Problem
The question is asking to find the derivative of the function cosh²(5x) with respect to x. To solve this, we will apply the chain rule of differentiation, along with the derivative of the hyperbolic cosine function.
Answer
$$ 10 \cosh(5x) \sinh(5x) $$
Answer for screen readers
The derivative of the function ( \cosh^2(5x) ) with respect to ( x ) is
$$ 10 \cosh(5x) \sinh(5x) $$
Steps to Solve
- Identify the function to differentiate
We start with the function ( f(x) = \cosh^2(5x) ). This is a composition of functions, which means we will apply the chain rule.
- Apply the chain rule
The chain rule states that if we have a function ( g(h(x)) ), then the derivative is given by:
$$ g'(h(x)) \cdot h'(x) $$
Here, let ( g(u) = u^2 ) where ( u = \cosh(5x) ). Therefore, we have:
$$ \frac{d}{dx} \cosh^2(5x) = 2 \cosh(5x) \cdot \frac{d}{dx} (\cosh(5x)) $$
- Differentiate the inner function
Next, we differentiate ( \cosh(5x) ). The derivative of the hyperbolic cosine function is:
$$ \frac{d}{dx} \cosh(x) = \sinh(x) $$
Using the chain rule again, we have:
$$ \frac{d}{dx} \cosh(5x) = 5 \sinh(5x) $$
- Combine the derivatives
Now, we can combine our results:
$$ \frac{d}{dx} \cosh^2(5x) = 2 \cosh(5x) \cdot (5 \sinh(5x)) $$
So we simplify this to:
$$ \frac{d}{dx} \cosh^2(5x) = 10 \cosh(5x) \sinh(5x) $$
The derivative of the function ( \cosh^2(5x) ) with respect to ( x ) is
$$ 10 \cosh(5x) \sinh(5x) $$
More Information
This result represents how the function ( \cosh^2(5x) ) changes with respect to ( x ). The hyperbolic cosine and sine functions are analogs of the regular cosine and sine functions, commonly used in hyperbolic trigonometry.
Tips
A common mistake when using the chain rule is forgetting to multiply by the derivative of the inner function. It's important to be careful with each step to capture all parts of the derivative correctly.
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