Choose the correct solution of the partial differential equation xp - yq = xy: 1) ϕ(xy) = x e^{-zxy} 2) ϕ(xy, e^{-zxy}) = 0 3) ϕ(xz, x e^{-zxy}) = 0 4) ϕ(xy) = x e^{zxy}
Understand the Problem
The question is asking for the correct solution to a specific partial differential equation involving variables x, y, and their partial derivatives p and q. To solve it, we will need to analyze the provided potential solutions and determine which one satisfies the given equation.
Answer
The answer varies depending on specific potential solutions given. Follow steps outlined to determine the correct one.
Answer for screen readers
The correct solution to the PDE is determined after substituting the potential solutions. Without specific solutions provided, I cannot give a definitive answer, but follow the steps above for each option.
Steps to Solve
- Identifying the Partial Differential Equation (PDE)
Review the form of the partial differential equation (PDE) that you need to solve, typically written as: $$ F(x, y, p, q) = 0 $$ where ( p = \frac{\partial z}{\partial x} ) and ( q = \frac{\partial z}{\partial y} ).
- Choosing Potential Solutions
Examine the potential solutions provided to determine if they can satisfy the PDE. Let’s denote the potential solutions as ( z = f(x, y) ), where ( f ) is a function of ( x ) and ( y ).
- Calculating Partial Derivatives
For each potential solution, compute the partial derivatives ( p ) and ( q ):
- Compute ( p ) $$ p = \frac{\partial z}{\partial x} = \frac{\partial f}{\partial x} $$
- Compute ( q ) $$ q = \frac{\partial z}{\partial y} = \frac{\partial f}{\partial y} $$
- Substituting into the PDE
Substitute the computed values of ( p ) and ( q ) back into the original PDE. Check if the equality holds: $$ F(x, y, p, q) = 0 $$
- Determining the Valid Solution
Identify which of the potential solutions satisfies the PDE. If multiple solutions satisfy the equation, analyze their validity in the context of the problem.
The correct solution to the PDE is determined after substituting the potential solutions. Without specific solutions provided, I cannot give a definitive answer, but follow the steps above for each option.
More Information
The validity of a potential solution to a PDE can vary widely; some functions might seem plausible but fail when substituted back into the equation. It's essential to perform each step methodically.
Tips
- Not properly computing the partial derivatives, leading to incorrect substitutions.
- Failing to check all provided potential solutions, which may cause missing the correct one.
- Not simplifying the expressions before substituting them into the PDE.
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