antiderivative of x^(2/3)

Understand the Problem

The question is asking for the antiderivative of the function x^(2/3). To find the antiderivative, we will apply the power rule of integration, which states that the integral of x^n is (x^(n+1))/(n+1) plus a constant of integration.

Answer

The antiderivative of $x^{\frac{2}{3}}$ is $ \frac{3}{5} x^{\frac{5}{3}} + C $.
Answer for screen readers

The antiderivative of the function $x^{\frac{2}{3}}$ is

$$ \frac{3}{5} x^{\frac{5}{3}} + C $$

Steps to Solve

  1. Identify the function and the power

    We are working with the function $x^{\frac{2}{3}}$.

  2. Apply the power rule of integration

    According to the power rule, the antiderivative is calculated as follows:

    $$ \int x^n , dx = \frac{x^{n+1}}{n+1} + C $$

    In our case, $n = \frac{2}{3}$. Therefore, we will add 1 to the exponent:

    $$ n + 1 = \frac{2}{3} + 1 = \frac{2}{3} + \frac{3}{3} = \frac{5}{3} $$

  3. Calculate the antiderivative

    Now we will insert the new exponent into the power rule formula:

    $$ \int x^{\frac{2}{3}} , dx = \frac{x^{\frac{5}{3}}}{\frac{5}{3}} + C $$

    Dividing by a fraction is the same as multiplying by its reciprocal:

    $$ \frac{x^{\frac{5}{3}}}{\frac{5}{3}} = x^{\frac{5}{3}} \cdot \frac{3}{5} = \frac{3}{5} x^{\frac{5}{3}} $$

  4. Add the constant of integration

    Finally, we will include the constant of integration $C$:

    $$ \int x^{\frac{2}{3}} , dx = \frac{3}{5} x^{\frac{5}{3}} + C $$

The antiderivative of the function $x^{\frac{2}{3}}$ is

$$ \frac{3}{5} x^{\frac{5}{3}} + C $$

More Information

This result shows the application of the power rule of integration. The constant $C$ represents an infinite number of antiderivatives that differ by a constant value. Understanding this concept is crucial in calculus, especially when dealing with indefinite integrals.

Tips

  • Forgetting to add the constant of integration $C$ after finding the antiderivative.
  • Miscalculating the exponent when applying the power rule, especially when dealing with fractions.
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