Analyze the following code. public class Test { public static void main(String args[]) { NClass nc = new NClass(); nc.t = nc.t++; } } class NClass{ int t; private NClass() { } } A)... Analyze the following code. public class Test { public static void main(String args[]) { NClass nc = new NClass(); nc.t = nc.t++; } } class NClass{ int t; private NClass() { } } A) The program compiles and runs fine. B) The program has a compile error because the NClass class has a private constructor. C) The program compiles, but has a runtime error because t has no initial value. D) The program does not compile because the parameter list of the main method is wrong.
Understand the Problem
The question is asking to analyze a piece of Java code for its compilation and runtime behavior, specifically focusing on class access modifiers and operations performed on instance variables.
Answer
The program has a compile error due to the private constructor of NClass.
The program has a compile error because the NClass class has a private constructor.
Answer for screen readers
The program has a compile error because the NClass class has a private constructor.
More Information
In Java, constructors define how objects of a class are created. If a constructor is private, it restricts the creation of instances of that class from outside the class itself, which leads to a compile-time error when trying to initialize an object from another class.
Tips
A common mistake is not noticing the access level of the constructor. Always check if a constructor is private, public, or protected when analyzing code.
Sources
AI-generated content may contain errors. Please verify critical information
