A plane is flying due north at 160 km/h relative to the surrounding air. There is a crosswind blowing due east. If the magnitude of the resultant velocity of the plane is 200 km/h,... A plane is flying due north at 160 km/h relative to the surrounding air. There is a crosswind blowing due east. If the magnitude of the resultant velocity of the plane is 200 km/h, what is the speed of the crosswind?

Question image

Understand the Problem

The question involves determining the speed of a crosswind affecting a plane's flight path. The plane is flying north, and a wind is blowing east, creating a resultant velocity. We need to apply the Pythagorean theorem to find the speed of the crosswind based on the given velocities.

Answer

The speed of the crosswind is $120 \, \text{km/h}$.
Answer for screen readers

The speed of the crosswind is $120 , \text{km/h}$.

Steps to Solve

  1. Identify known and unknown quantities

We have the following velocities:

  • Velocity of the plane flying north, $V_p = 160 , \text{km/h}$.
  • Magnitude of the resultant velocity, $V_r = 200 , \text{km/h}$.
  • Velocity of the crosswind, $V_w$, is unknown.
  1. Apply the Pythagorean theorem

The plane's velocity and the crosswind velocity are perpendicular to each other. Hence, we can use the Pythagorean theorem:

$$ V_r^2 = V_p^2 + V_w^2 $$

Substituting the known values:

$$ (200 , \text{km/h})^2 = (160 , \text{km/h})^2 + V_w^2 $$

  1. Calculate the squares

Calculate the squares of the velocities:

$$ 40000 , \text{km}^2/\text{h}^2 = 25600 , \text{km}^2/\text{h}^2 + V_w^2 $$

  1. Rearrange the equation

Now, rearranging the equation to isolate $V_w^2$:

$$ V_w^2 = 40000 , \text{km}^2/\text{h}^2 - 25600 , \text{km}^2/\text{h}^2 $$

  1. Perform the subtraction

Calculate the right side:

$$ V_w^2 = 14400 , \text{km}^2/\text{h}^2 $$

  1. Take the square root

Now take the square root to find $V_w$:

$$ V_w = \sqrt{14400} , \text{km/h} $$

  1. Calculate the speed of the crosswind

The final step is to compute the square root:

$$ V_w = 120 , \text{km/h} $$

The speed of the crosswind is $120 , \text{km/h}$.

More Information

The calculation demonstrates how to apply the Pythagorean theorem in a real-world situation involving vector velocities. The crosswind affects the plane's actual path and can be critical for navigation.

Tips

  • Mixing up the velocities; ensure that the correct values are squared and added according to the Pythagorean theorem.
  • Forgetting to take the square root when finally extracting the crosswind speed.

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