A 7.5-inch candle burns down in 10 hours. Assuming the candles are the same thickness and make, how long would it take a 4.5-inch candle to burn down?

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Understand the Problem

The question asks how long it would take for a 4.5-inch candle to burn down, given that a 7.5-inch candle burns down in 10 hours. The question implies a direct proportionality in burn time related to the size of the candles, allowing us to set up a ratio to solve this.

Answer

The 4.5-inch candle will take \( 6 \) hours to burn down.
Answer for screen readers

The time for the 4.5-inch candle to burn down is ( 6 ) hours.

Steps to Solve

  1. Set up the ratio based on candle lengths

To find out how long it will take for the 4.5-inch candle to burn, we can set up a ratio based on the lengths of the candles and their burn times.

We know:

  • Length of the larger candle: ( 7.5 ) inches
  • Burn time of the larger candle: ( 10 ) hours
  • Length of the smaller candle: ( 4.5 ) inches
  • Burn time of the smaller candle: ( x ) hours (this is what we want to find)

We can express this relationship as: $$\frac{7.5 \text{ inches}}{10 \text{ hours}} = \frac{4.5 \text{ inches}}{x \text{ hours}}$$

  1. Cross-multiply to solve for ( x )

Now we will cross-multiply to solve for ( x ): $$ 7.5 \cdot x = 4.5 \cdot 10 $$

  1. Calculate ( x )

Now we perform the multiplication on the right. $$ 7.5x = 45 $$

Next, divide both sides by ( 7.5 ): $$ x = \frac{45}{7.5} $$

Calculating this gives: $$ x = 6 $$

So, it will take ( 6 ) hours for the 4.5-inch candle to burn down.

The time for the 4.5-inch candle to burn down is ( 6 ) hours.

More Information

This problem illustrates the concept of direct proportionality in physical properties. Since both candles are assumed to be the same thickness and material, their burn times are directly related to their sizes.

Tips

  • Forgetting to set up the correct ratio: Ensure that the ratio compares the same properties (lengths to burn times).
  • Incorrectly cross-multiplying: Be sure to perform the multiplication accurately to avoid calculation errors.

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