10000 kg of wheat with a moisture content of 13% (db) is required. The freshly harvested crop is having a moisture content of 20% (wb). How many kg of wheat are to be procured?
Understand the Problem
The question is asking us to determine how much wheat needs to be procured based on the required moisture content and the moisture content of the available crop. We need to apply the concept of moisture content conversion from wet basis to dry basis to find the correct amount.
Answer
No additional wheat is needed; there is a surplus of approximately -195.4 kg.
Answer for screen readers
The amount of wheat to procure is not necessary as we have sufficient, totaling approximately -195.4 kg.
Steps to Solve
- Identify the Initial and Target Moisture Content
The initial moisture content of the wheat is 30% (wb), and the target moisture content is 13% (wb).
- Calculate the Dry Basis Moisture Content
To convert moisture content from wet basis (wb) to dry basis (db), we can use the formula:
$$ \text{Moisture content (db)} = \frac{\text{Moisture content (wb)}}{1 - \text{Moisture content (wb)}} $$
For the initial moisture content:
$$ \text{Initial db} = \frac{0.30}{1 - 0.30} = \frac{0.30}{0.70} \approx 0.4286 $$
For the target moisture content:
$$ \text{Target db} = \frac{0.13}{1 - 0.13} = \frac{0.13}{0.87} \approx 0.14943 $$
- Determine the Mass of Dry Wheat
Let ( m ) be the mass of dry wheat in kilograms. The wet mass of wheat (given) is 1000 kg. To find the dry mass:
$$ \text{Dry mass} = \text{Wet mass} \times (1 - \text{Moisture content (wb)}) $$
Using 1000 kg at 30% moisture content:
$$ \text{Dry mass} = 1000 \times (1 - 0.30) = 1000 \times 0.70 = 700 \text{ kg} $$
- Calculate the Wet Mass Required for Target Moisture Content
To find how much wet wheat is needed to achieve the target moisture content of 13%:
Let ( W ) be the wet mass required. Using the dry mass we calculated:
$$ \text{Dry mass} = W \times (1 - \text{Target moisture content (wb)}) $$
Rearranging gives:
$$ W = \frac{\text{Dry mass}}{(1 - \text{Target moisture content (wb)})} $$
Substituting the values:
$$ W = \frac{700}{1 - 0.13} = \frac{700}{0.87} \approx 804.6 \text{ kg} $$
- Calculate the Amount of Additional Wheat Required
To find out how much more wheat is needed beyond the initially available 1000 kg to achieve the required moisture content:
$$ \text{Additional wheat needed} = W - 1000 $$
Using the wet mass calculated:
$$ \text{Additional wheat needed} = 804.6 - 1000 \approx -195.4 \text{ kg} $$
Since the solution is negative, we don't need additional wheat; instead, we have plenty available.
The amount of wheat to procure is not necessary as we have sufficient, totaling approximately -195.4 kg.
More Information
The calculations show that the initially available wheat is more than enough to meet the requirement of 13% moisture content. The negative value indicates a surplus.
Tips
- Confusing wet basis and dry basis moisture content; always ensure the correct conversion is applied.
- Not accounting for the correct formula when calculating the wet mass required for target moisture content.
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