1. 20000 x 3.5% x 5 - [20000 x 0.3% ÷ 12 x (48 + 3)] = 32450 2. 20000 x 4.35% ÷ 12 x 7 = 5075
Understand the Problem
The question presents two mathematical expressions involving percentages and asks for their calculation. The first expression involves multiplying a number by 3.5% and also includes a subtraction calculation involving another percentage. The second expression is similar, involving a different percentage. This indicates a need for step-by-step mathematical calculations to arrive at a solution.
Answer
1. $3245$ 2. $507.5$
Answer for screen readers
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$3245$
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$507.5$
Steps to Solve
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Calculate 3.5% of 20000 and Multiply by 5
First, find $3.5%$ of $20000$:
$$ 20000 \times \frac{3.5}{100} = 700 $$
Then multiply by 5:
$$ 700 \times 5 = 3500 $$ -
Calculate 0.3% of 20000
Next, find $0.3%$ of $20000$:
$$ 20000 \times \frac{0.3}{100} = 60 $$ -
Divide the Result by 12
Now, divide the result from step 2 by 12:
$$ \frac{60}{12} = 5 $$ -
Add 48 and 3
Add $48$ and $3$:
$$ 48 + 3 = 51 $$ -
Multiply the Result of Step 3 by Step 4
Now, multiply the result from step 3 by the result from step 4:
$$ 5 \times 51 = 255 $$ -
Subtract from Step 1 Result
Finally, subtract the result from step 5 from the result of step 1:
$$ 3500 - 255 = 3245 $$
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Calculate 4.35% of 20000
For the second expression, find $4.35%$ of $20000$:
$$ 20000 \times \frac{4.35}{100} = 870 $$ -
Divide by 12 and Multiply by 7
Now divide the result from step 7 by 12:
$$ \frac{870}{12} = 72.5 $$
Then, multiply by 7:
$$ 72.5 \times 7 = 507.5 $$
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$3245$
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$507.5$
More Information
The calculations involve the use of percentages and basic arithmetic operations (multiplication, division, addition, and subtraction). Understanding these operations is essential for handling requests related to financial calculations or similar situations.
Tips
- Forgetting to convert percentages to decimals before calculations. Always remember to divide the percentage by 100.
- Misplacing parentheses which could lead to altering the order of operations.
- Not accurately following the order of operations (BODMAS/BIDMAS) while solving expressions.
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