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Questions and Answers
The enthalpy change for the reaction converting maleic acid to fumaric acid is ΔHrxn = -23.3 kJ mol−1.
The enthalpy change for the reaction converting maleic acid to fumaric acid is ΔHrxn = -23.3 kJ mol−1.
True
Fumaric acid has a higher enthalpy of formation than maleic acid.
Fumaric acid has a higher enthalpy of formation than maleic acid.
False
The balanced equation for the combustion of glucose in oxygen produces two molecules of carbon dioxide and six molecules of water.
The balanced equation for the combustion of glucose in oxygen produces two molecules of carbon dioxide and six molecules of water.
False
The standard enthalpy of formation of O2 in its gaseous state is 0 kJ mol−1.
The standard enthalpy of formation of O2 in its gaseous state is 0 kJ mol−1.
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At 305 K, the enthalpy of formation of water (H2O) in its liquid state is −285.8 kJ mol−1.
At 305 K, the enthalpy of formation of water (H2O) in its liquid state is −285.8 kJ mol−1.
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The sum of the enthalpies of formation for glucose, oxygen, carbon dioxide, and water equals ΔHrxn for the process.
The sum of the enthalpies of formation for glucose, oxygen, carbon dioxide, and water equals ΔHrxn for the process.
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The enthalpy change for the reaction of glucose and oxygen is dependent on the phase of the reactants and products.
The enthalpy change for the reaction of glucose and oxygen is dependent on the phase of the reactants and products.
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For the reaction involving glucose metabolism, oxygen acts as a reactant, while carbon dioxide and water are the products.
For the reaction involving glucose metabolism, oxygen acts as a reactant, while carbon dioxide and water are the products.
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Study Notes
Thermochemistry Tutorial
- Given the enthalpies of formation of fumaric acid and maleic acid are −807.6 and −784.4 kJ mol−1, respectively, the enthalpy change for maleic acid to fumaric acid is −23.2 kJ mol−1
- The balanced reaction for the metabolism of glucose (C6H12O6) with oxygen (O2) producing carbon dioxide (CO2) and water (H2O) is: C6H12O6 + 6O2 → 6 CO2 + 6 H2O
- The enthalpy change for the metabolism of glucose is calculated using the enthalpy values for each:
- △H⁰f C6H12O6 (s) = −1273.0 kJ mol−1
- △H⁰f O2 (g) = 0 kJ mol−1 (element)
- △H⁰f H2O (l) = −285.8 kJ mol−1
- △H⁰f CO2 (g) = −393.5 kJ mol−1
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Description
This quiz delves into key concepts of thermochemistry, including enthalpy changes associated with the formation of fumaric and maleic acids, as well as the metabolic processes of glucose. Solve problems related to the enthalpy of formation and chemical reactions to test your understanding of thermochemical principles.