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Solving Variable Equations in Mathematics
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Solving Variable Equations in Mathematics

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Questions and Answers

What is the key step in solving a linear equation with one variable?

  • Isolating the variable by moving all other terms to one side (correct)
  • Squaring both sides of the equation
  • Eliminating the square root from the variable term
  • Applying the quadratic formula
  • What does the discriminant (b² - 4ac) in the quadratic formula represent?

  • The value of the constant term in the quadratic equation
  • The number of real solutions to the quadratic equation (correct)
  • The value of the coefficient of the linear term in the quadratic equation
  • The value of the coefficient of the squared term in the quadratic equation
  • If the discriminant (b² - 4ac) in the quadratic formula is negative, what type of solutions does the quadratic equation have?

  • No solutions
  • One real solution
  • Two real solutions
  • Two complex solutions (correct)
  • Which of the following steps is typically required when solving equations involving square roots (radicals)?

    <p>Clearing fractions and simplifying expressions</p> Signup and view all the answers

    In the equation $\sqrt{x + 1} = 3 - (x/5)$, what is the first step to solve for x?

    <p>Multiply both sides by 5 to eliminate the fraction</p> Signup and view all the answers

    Which of the following equations is a linear equation with one variable?

    <p>$3x - 7 = 0$</p> Signup and view all the answers

    Study Notes

    When solving for variables in a mathematical formula, it's essential to understand the different types of formulas and how they behave. Here is some information on these aspects:

    1. Linear equations: These are simple equations with one variable. To solve them, you can isolate the variable by moving all other terms to one side of the equation. For example, if we have the equation x + y = 2, we can rearrange it to get y = 2 - x.

    2. Quadratic equations: These involve squared terms and require more steps to solve. One approach is using the quadratic formula:

      x = (-b ± sqrt(b² - 4ac)) / 2a
      

      This expression gives two possible values for x. Which value is correct depends on whether the discriminant b² - 4ac is positive, negative, or zero. If it's positive, both solutions are real numbers; if it's zero, there is only one solution; and if it's negative, the solutions are complex numbers.

    3. Equations involving radicals (square roots): In such cases, you may need additional steps like clearing fractions, simplifying expressions, and eliminating square roots from the variable term. For instance, consider the equation √(x + 1) = 3 - (x/5). To solve this, first eliminate the fraction (x/5) by multiplying both sides by 5, which results in 5√(x + 1) = 15 - 5x. Then, square both sides to remove the square root notation, resulting in 25(x + 1) = 225 - 25x. Finally, subtract 25x from both sides to get 25x + 25 = 225 - 25x, which simplifies to 50 = 0, indicating no solution exists.

    In conclusion, solving for variables involves understanding different types of equations, applying specific methods to isolate the variable, and considering whether the solution will result in multiple or single values.

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    Description

    Learn about solving equations with one variable, including linear equations, quadratic equations, and equations involving radicals. Understand methods such as isolating the variable, using the quadratic formula, and eliminating square roots to find solutions.

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