Recursive Algorithms: Advantages and Efficiency
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Questions and Answers

Which of the following best describes the primary advantage of using a recursive algorithm for problems that exhibit a clear recurrence relation?

  • Automatic handling of edge cases and input validation, ensuring robustness of the algorithm.
  • Direct and concise translation of the recurrence relation, leading to simpler and more readable code. (correct)
  • Improved execution speed compared to iterative solutions due to optimized compiler handling of recursive calls.
  • Reduced memory usage, as recursive algorithms do not require storing intermediate results.

In the context of designing recursive algorithms, what is the significance of the 'base case'?

  • It specifies the initial input values for which the algorithm is first executed.
  • It defines the condition under which the algorithm makes recursive calls.
  • It optimizes the algorithm's performance by caching previously computed results.
  • It provides a non-recursive stopping condition, preventing infinite recursion. (correct)

Consider the recursive Fibonacci sequence implementation. What is the primary reason for its inefficiency compared to an iterative approach?

  • Iterative approaches use registers more efficiently than recursive approaches.
  • The iterative approach can be easily parallelized, while the recursive one cannot.
  • Recursive calls consume more memory due to the overhead of function call stacks.
  • The recursive approach involves redundant calculations, leading to exponential time complexity. (correct)

Given a recurrence relation $T(n) = 2T(n/2) + n$, which of the following algorithms could this represent, keeping in mind the structure of recursive algorithms?

<p>Merge Sort (D)</p> Signup and view all the answers

When translating a recurrence relation into a recursive algorithm, which aspect of the recurrence relation directly corresponds to the base case in the algorithm?

<p>The initial condition(s) that define the starting point. (A)</p> Signup and view all the answers

In a recursive function, what is the significance of the base case?

<p>It specifies the condition under which the function stops calling itself, preventing infinite recursion. (A)</p> Signup and view all the answers

What does each call to a recursive function create?

<p>A new instance of the function with its own copy of local variables. (A)</p> Signup and view all the answers

Given the recursive function for factorial, what is the time efficiency of the algorithm?

<p>O(n) (B)</p> Signup and view all the answers

If T(n) represents the number of multiplications required to compute factorial(n), and T(0) = 1, which of the following recurrence relations correctly describes T(n)?

<p>$T(n) = T(n - 1) + 1$ (C)</p> Signup and view all the answers

Which of the following is a potential drawback of using recursion compared to iteration?

<p>Recursion can lead to stack overflow errors if the depth of recursion is too great. (B)</p> Signup and view all the answers

In the context of the factorial function, if factorial(5) is called, how many times will the factorial function be called in total (including the original call)?

<p>6 (B)</p> Signup and view all the answers

What is the primary reason for using backward substitution when analyzing the time complexity of a recursive function?

<p>To transform the recurrence relation into a closed-form expression. (B)</p> Signup and view all the answers

How does having each call to a recursive function create its own copy of local values affect memory usage compared to an iterative approach?

<p>Recursion typically uses more memory because each call duplicates the local variable space. (A)</p> Signup and view all the answers

Under what condition is a function $f(n)$ considered asymptotically smaller than another function $g(n)$ by a polynomial factor?

<p>$f(n) &lt; g(n)^c$ for some constant $c &gt; 0$ (B)</p> Signup and view all the answers

When does the master method fail to provide a solution for a recurrence relation?

<p>When $f(n)$ falls into the gaps between the cases defined in the master theorem or the regularity condition in case 3 does not hold. (B)</p> Signup and view all the answers

Which of the following pairs of functions, $f(n)$ and $g(n)$, satisfies the condition that $f(n)$ is polynomially smaller than $g(n)$?

<p>$f(n) = n$ and $g(n) = n^2$ (A)</p> Signup and view all the answers

Consider the recurrence relation $T(n) = 4T(n/2) + 1$. Based on the master theorem, which case applies to this recurrence?

<p>Case 1, where $f(n)$ is polynomially smaller than $n^{\log_b a - \epsilon}$ for some constant $\epsilon &gt; 0$. (D)</p> Signup and view all the answers

For the recurrence $T(n) = 4T(n/2) + n \log n$, why can't we directly apply any of the three cases of the master theorem?

<p>$n \log n$ falls in the gap between being polynomially smaller and polynomially larger than $n^2$. (C)</p> Signup and view all the answers

Given the recurrence relation $T(n) = 9T(n/3) + n$, how does $n$ compare to $n^{\log_b a}$?

<p>$n &lt; n^{\log_b a}$ (D)</p> Signup and view all the answers

What is the purpose of analyzing recurrence relations such as $T(n) = aT(n/b) + f(n)$?

<p>To determine the time complexity of a recursive algorithm. (B)</p> Signup and view all the answers

In the Master Method, what does the term $f(n)$ typically represent?

<p>The work done outside the recursive calls. (A)</p> Signup and view all the answers

When using the Master Method, which of the following comparisons is crucial for determining the time complexity?

<p>Comparing $f(n)$ with $n^{\log_b a}$. (D)</p> Signup and view all the answers

If $f(n) = O(n^{\log_b a - \epsilon})$ for some constant $\epsilon > 0$, according to the Master Method, what can be concluded about the time complexity $T(n)$?

<p>$T(n) = \Theta(n^{\log_b a})$ (D)</p> Signup and view all the answers

Consider a recurrence relation $T(n) = aT(n/b) + f(n)$. If $f(n) = \Theta(n^{\log_b a})$, what does the Master Theorem suggest about $T(n)$?

<p>$T(n) = \Theta(n^{\log_b a} \log n)$ (C)</p> Signup and view all the answers

Suppose an algorithm's runtime is described by $T(n) = 2T(n/2) + n^2$. Which case of the Master Theorem applies, and what is the resulting time complexity?

<p>Case 3, $T(n) = \Theta(n^2)$ (B)</p> Signup and view all the answers

An algorithm has a recurrence relation $T(n) = 4T(n/2) + n \log n$. Which of the following correctly describes how the Master Theorem would be applied?

<p>Compare $n \log n$ with $n^2$ and apply Case 3 if $n \log n$ grows faster and satisfies the regularity condition. (B)</p> Signup and view all the answers

In the substitution method for solving recurrences, what is the primary challenge in the initial steps?

<p>Coming up with a good initial guess for the solution. (D)</p> Signup and view all the answers

When the substitution method fails to prove that $T(n) = O(f(n))$, what is the most reasonable next step?

<p>Refine the guess for $f(n)$ based on insights from the failed proof. (A)</p> Signup and view all the answers

Given a recurrence relation $T(n) = 2T(n/2) + n \lg n$, and a guess that $T(n) = O(n^2)$, under what condition can we determine that this guess holds true?

<p>If it can be shown that $T(n) \leq cn^2$ for some constant <em>c</em> and sufficiently large <em>n</em>. (D)</p> Signup and view all the answers

Consider two recurrences: $T_1(n) = 2T_1(n/2 + 17) + n$ and $T_2(n) = 2T_2(n/2) + n$. According to the remarks on guessing, what can be inferred?

<p>The asymptotic behavior of $T_1(n)$ is bounded by O(n lg n). (D)</p> Signup and view all the answers

Why is the recursion-tree method particularly useful for analyzing divide-and-conquer algorithms?

<p>It helps visualize and sum the costs of subproblems at each level of recursion. (A)</p> Signup and view all the answers

What is a key difference between the substitution method and the recursion-tree method for solving recurrences?

<p>The substitution method requires an initial guess, while the recursion-tree method helps in generating that guess. (D)</p> Signup and view all the answers

In the context of solving recurrences, what does it mean to establish 'loose upper and lower bounds'?

<p>To find two solutions, one that is definitely an overestimate and one that is definitely an underestimate of the actual solution. (B)</p> Signup and view all the answers

Suppose you've determined that $T(n) = 2T(n/2) + n \lg n$ is either $O(n^2)$ or $O(n(\lg n)^2)$. How would you typically proceed using the substitution method to refine your guess?

<p>First attempt to prove either $T(n) = O(n^2)$ or $T(n) = O(n(\lg n)^2)$, and if that fails, switch to the other guess. (B)</p> Signup and view all the answers

What is the primary characteristic of the recursive Fibonacci sequence implementation that leads to its inefficiency?

<p>The repeated calculation of the same Fibonacci numbers. (B)</p> Signup and view all the answers

In the given recursive Fibonacci sequence implementation, what will be the return value of f(4)?

<p>3 (A)</p> Signup and view all the answers

If the Fibonacci sequence function f(n) is called with n = -1, what will happen?

<p>The function will likely raise an exception or error due to the invalid input. (B)</p> Signup and view all the answers

Consider a scenario where you need to calculate f(n) for a very large value of n (e.g., n = 100). Which of the following optimization techniques would be most effective in improving the performance of the Fibonacci sequence calculation?

<p>Using a loop-based iterative approach instead of recursion. (B)</p> Signup and view all the answers

What is the space complexity of the given recursive Fibonacci sequence implementation?

<p>O(n) - linear space (A)</p> Signup and view all the answers

How does memoization improve the performance of calculating Fibonacci numbers recursively?

<p>By reducing the number of recursive calls by storing and reusing previously computed values. (B)</p> Signup and view all the answers

Consider the iterative (loop-based) approach to calculating Fibonacci numbers. What is its primary advantage over the recursive approach?

<p>It avoids the overhead of function calls and reduces redundant computations. (C)</p> Signup and view all the answers

What is the time complexity of an iterative (loop-based) Fibonacci sequence implementation?

<p>O(n) (D)</p> Signup and view all the answers

If f(n) represents the nth Fibonacci number, which of the following equations correctly expresses the relationship between consecutive Fibonacci numbers?

<p>$f(n) = f(n-1) + f(n-2)$ (C)</p> Signup and view all the answers

Imagine you are tasked with calculating the Fibonacci sequence for a range of numbers repeatedly in a performance-critical application. Which approach would generally be most efficient?

<p>Using a lookup table with pre-computed Fibonacci numbers for all possible inputs and their corresponding results within the given range. (C)</p> Signup and view all the answers

Flashcards

What is Recursion?

A method where a function calls itself to solve smaller instances of the same problem.

Recursive Algorithm Design

  1. Identify the recurrence relation.
  2. Translate it to a recursive algorithm.
  3. Translate initial conditions to base cases.

Recurrence Relation Translation

Direct translation between the recurrence relation and the recursive algorithm. Each step mirrors the other.

What is a Base Case?

The condition that stops the recursive calls and provides a direct solution. Prevents infinite loops.

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What is the Fibonacci Sequence?

A sequence where each number is the sum of the two preceding ones, usually starting with 0 and 1.

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Asymptotically Smaller

f(n) must grow slower than n^c by a factor of n for some constant c > 0.

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Polynomially Smaller

If f(n) is polynomially smaller than g(n), f(n) = O(n^k) for some constant k.

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Master Method: Growth Rate

Comparing the growth rate of f(n) to n^(log_b a) in recurrence relations to determine the overall time complexity.

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Polynomial Growth Comparison

f(n) = 1 and g(n) = n^2; f(n) is polynomially smaller than g(n). Example, f(n) = log n and g(n) = n. In those cases, f(n) is not polynomially smaller than g(n)

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Master Method Limitations

When f(n) does not fit the polynomial relationship conditions or fails regularity condition of the Master Theorem.

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Substitution Method

A method used to solve recurrences by guessing the form of the solution and then using mathematical induction to find the constants and show that the solution works.

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Incorrect Guess - Recurrences

When using the substitution method, your initial guess of the solution is incorrect.

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Recursion-tree Method

A method for solving recurrences where you expand the recurrence into a tree-like structure representing the cost of each subproblem.

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Recursion Tree

A visual representation of a recursive algorithm, showing the cost of each subproblem.

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Guessing Solutions (Recurrences)

Useful when a recurrence is similar to one you've solved before.

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Bounding Recurrences

Establish loose upper and lower bounds to narrow the range of possible solutions.

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Recursion Trees

Useful for analyzing the runtime of divide-and-conquer algorithms.

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Analyzing Subproblems

Expanding a recurrence to see the cost of each subproblem.

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Recursion

A programming technique where a function calls itself to solve smaller subproblems until a base case is reached.

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Base Case

The condition that stops a recursive function from calling itself indefinitely.

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Recursive Call

The part of a recursive function where the function calls itself.

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Function Instance

Each call to a function starts a new instance, with its own copies of local variables and parameters.

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Factorial Time Analysis

For factorial(n), the number of multiplications, T(n), equals T(n-1) + 1, with T(0) = 1.

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Backward Substitution

A method for solving recurrence relations by repeatedly substituting the function's definition into itself.

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Factorial Algorithm Time Efficiency

The recursive factorial algorithm performs n multiplications.

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Internal Anatomy

for factorial(n) where the function calls itself

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Fibonacci Sequence

A sequence of numbers where each number is the sum of the two preceding ones.

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Recursive Function

A function that calls itself within its own definition.

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Multiple recursive calls

Calling same function multiple times (as we saw in the faulty example).

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Internal Sequence

An 'internal' sequence, or an implementation detail that users don't need to directly interact with.

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Recursive Definition

Describes a function that solves a problem by breaking it down to smaller instances of the same problem.

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Unbounded Recursion

When a recursive function doesn't reach a base case and calls itself indefinitely, leading to a crash.

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Recursive Function Definition

A function that is defined in terms of itself.

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n == 0

The 'zero' case of the function or when the input to the function is zero.

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Exponential Growth

When the total number of function calls grow rapidly, particularly with multiple recursive calls.

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What is a Recurrence?

A formula that expresses the value of a function in terms of its value at another point.

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Master Method Recurrence Form

T(n) = aT(n/b) + f(n), where 'a' is number of subproblems, 'n/b' is the subproblem size, and 'f(n)' is the work done outside the recursive calls.

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What does 'a' represent?

The number of subproblems in the recurrence.

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What does 'b' represent?

The factor by which the input size is reduced in each subproblem.

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What does 'f(n)' represent?

The work done outside the recursive calls in the master method recurrence.

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Master Theorem Case 1

Compare f(n) with n^(log_b a). If f(n) = O(n^(log_b a - ε)) for some constant ε > 0, then T(n) = Θ(n^(log_b a)).

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Master Theorem Case 2

Compare f(n) with n^(log_b a). If f(n) = Θ(n^(log_b a)), then T(n) = Θ(n^(log_b a) * log n).

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Master Theorem Case 3

Compare f(n) with n^(log_b a). If f(n) = Ω(n^(log_b a + ε)) for some constant ε > 0, and if a f(n/b) ≤ c f(n) for some constant c < 1 and all sufficiently large n, then T(n) = Θ(f(n)).

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Study Notes

Recursion Overview

  • Recursion is the process where a function calls itself directly or indirectly.
  • It's used frequently in computer programs.

Recurrence Relations and Fibonacci Sequence

  • Recurrence relations are equations that relate an element of a sequence to some of its predecessors.
  • The Fibonacci sequence can be defined through a recurrence relation.
  • The Fibonacci sequence includes: 1, 1, 2, 3, 5, 8, 13, 21, 34.
  • The recurrence relation is fₙ = fₙ₋₁ + fₙ₋₂ for n ≥ 2.
  • Initial conditions are needed to provide starting values for a finite sequence; for Fibonacci, f₀ = 0 and f₁ = 1.

Recursive Calls

  • A recursive function calls itself.
  • The factorial function can be defined recursively.
  • The factorial function is defined as n! = n × (n - 1)!.
  • Base case: 0! = 1 by definition.
  • The factorial function can expressed as: factorial(n) = n * factorial(n - 1).

Anatomy of a Recursive Call

  • The base case (initial condition) enables the recursive calls to stop.
  • Each recursive call solves an identical but smaller problem.
  • Each call to a function starts that function anew.
  • Each call has its own copy of any local values, including the values of the parameters.

Time Analysis of N!

  • T(n) represents the number of multiplications needed to compute factorial(n).
  • T(n) = T(n - 1) + 1.
  • T(0) = 1.
  • T(n - 1) multiplications are needed to compute factorial(n - 1), plus one more multiplication to multiply the result by 'n'.
  • Using backward substitution leads to a time efficiency of O(n) for the recursive factorial algorithm.

Beauty of Recursive Algorithms

  • Direct translation between the recurrence relation and the recursive algorithm is possible.

Strategy for Designing Recursive Algorithms

  • Identify the recurrence relation to solve the problem followed by translating the recurrence relation into a recursive algorithm.
  • Translate the initial condition in the recurrence relation into the BASE CASE for the recursive algorithm.

Recursive vs. Iterative

  • Conciseness, clarity, and simplicity of recursive algorithms may hide inefficiencies.
  • Be cautious when using as such algorithms can be inefficient.

Fibonacci Sequence Example Analysis

  • Iterative algorithm: the running time for Fibonacci numbers runs in O(n).
  • Recursion: each call leads to another two calls: f(n - 1) and f(n - 2).
  • The total number of calls grows exponentially.
  • The running time of the recursive Fibonacci algorithm is approximately (3/2)ⁿ.

Compute Fibonacci: Recursive vs. Non-recursive Complexity

  • Recursive implementation is inefficient.
  • A graph shows how the time increases compared to O(n) for Fibonacci.
  • Goal: Given array and a key, you can find the index of the key in array.
  • Compare the key being searched for with the middle entry of an array
  • A smaller key searches in left half.
  • A bigger key will search in right half.
  • An equal key gives the index.
  • If the size is <= 0 then operation will return -1.

Example: Exponentiation

  • Compute aⁿ for an integer n.
  • A basic algorithm involves multiplying 'a' by itself 'n' times.
  • Time complexity is O(n) for a quick and easy algorithm:

Fast Exponentiation

  • Involves a divide and conquer strategy.
  • Example: 2⁸ = 2⁴ x 2⁴ = 16 x 16.
  • Offers better performance.

Analysis of Recursive Algorithms

  • Decide on parameter n indicating input size.
  • Identify the algorithm's basic operation.
  • Set up recurrence relation with an appropriate initial condition.
  • This expresses the number of times the basic operation is executed.
  • Solve the recurrence by backward substitutions or other methods.

FAST Exponentiation Analysis

  • Time efficiency of the recursive power algorithm is O(lg n), where lg is the base-2 logarithm.

Recursion Tree Method

  • Tree: each node represents a single sub problem
  • Sum the costs within each level of the tree to create a recursive solution

Recurrences

  • The recursive version is used divide and conquer the algorithm.
  • This contains 3 steps: divide, conquer recursively, and combine into original problem solution.

Analyzing recursive algorithms

  • Algorithm complexity takes constant time if the dividend and conquer takes constant item 6(1)
  • Otherwise, diving the problem yields yield a sub-problem with a size of 1/b original problem.
  • The running time is given as T(n) = T(n/b) + D(n) + C(n)
  • D(n) is the time spent dividing problem into sub-problems
  • C(n) is the time to combine the sub-problems for solutions

Methods for Solving Recurrences

  • Substitution Method involves guessing a bound and uses mathematical induction.
  • Recursion Tree Method involves converting the recurrence into a tree whose nodes are the cost incurred at various levels of recursion.
  • Master Method provides bounds for recurrences.
  • Master Theorem formula is T(n) = aT(n/b) + f(n) for constant numbers a >=1 and b > 1, and give function for f(n).

Substitution Method Cases:

  • Case 1 requires proving that a given answer/solution is correct
  • Case 2 requires finding the answer/solution.

Recursion-Tree Method

  • It is difficult to come up with something original when you are using the substitution method.
  • The recurrence tree solves this problem by determining the cost of sub-problem

Master Method

  • Determine a way to reduce form to solve the recurrence relations.
  • Basic form is T(n) = aT(n/b) + f(n) where a >=1 and b> 1 where a and b are constant and f(n) is the asymptomatically positive function. In this case, a sub-problem is solved recursively
  • Problem is divided into "a" sub-problem. Each can have n/b number of data and require T(n/b), which will take time.
  • f(n) = D(n) + C(n) is the cost for dividing problem and will combining results of sub-problem

Master Method:

Let a 1 or more >=1 and b>1.

  • Cases function can bounded asymptotically with these steps:
  • Case 1: F(n) = O(n (Log base b a) - E) if true, the T(n) is Big Theta (n(log base b a)). Where E is the constant for some cases.
    • Case 2: Find f(n)= G(n *(log base b a)), T(n) = G(n (g base b a) lg n)
      • Case 3: for f(n) = Q/ (n * (Log base b a)+E, T(n) becomes T(n) = Big Theta (f(n), and f is also regular. This is also equal to, you must show A *f(n/b) f(n) for all n larger than constant b.

Remarks When Guessing in Substitution Method

  • There is no general way to guess, but if recursion is similar and reasonable, the similar solution is the answer.
  • To guess, make a loose upper and lower bound approximation.

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Explore the advantages of recursive algorithms, focusing on their application to problems with recurrence relations. Understand the importance of the base case and analyze the efficiency of recursive implementations, particularly in the context of the Fibonacci sequence and time complexity.

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